Ios UIColor扩展

我在objective-c中扩展了UIColor类 头文件如下所示：

@interface UIColor (ColorDecision)
+ (UIColor*) directOrLegacyWithColor;
+ (UIColor*) changeColor;
@end

#define Color_C7           [SharedUtility colorWithHexString:@"FF6A00"] // orange
#define Color_Direct      [Utility colorWithHexString:@"313d53"] // Color for direct

实施：

#import "UIColor+ColorDecision.h"

@implementation UIColor (ColorDecision)
 + (UIColor *)directOrLegacyWithColor {
     UIColor *color;
     UIColor *returenedColor = self.changeColor;
     color = LoginsManager.getSharedInstance.isDirect ? returenedColor : [UIColor self];
     return color;
}

 + (UIColor *)changeColor{
     UIColor *newColor;
     if (self == Color_C7) newColor = Color_Direct;

     return newColor;
}
@end

我从“类”的下面一行“分配给“UIColor*”的不兼容指针类型”得到编译器的警告

我知道问题出在与指针的关系上，但我不知道该怎么办

编辑 感谢manishharma93注释，我现在解决了第一个问题，当我想使用指定的方法时，这些方法似乎不可见

我在全局头文件中定义了我的颜色，如下所示：

@interface UIColor (ColorDecision)
+ (UIColor*) directOrLegacyWithColor;
+ (UIColor*) changeColor;
@end

#define Color_C7           [SharedUtility colorWithHexString:@"FF6A00"] // orange
#define Color_Direct      [Utility colorWithHexString:@"313d53"] // Color for direct

这是实用程序类中“colorWithHexString”函数的实现：

+(UIColor *)colorWithHexString:(NSString *)hexString {
NSString *colorString = [[hexString stringByReplacingOccurrencesOfString: @"#" withString: @""] uppercaseString];
CGFloat alpha, red, blue, green;
switch ([colorString length]) {
    case 3: // #RGB
        alpha = 1.0f;
        red   = [SharedUtility colorComponentFrom: colorString start: 0 length: 1];
        green = [SharedUtility colorComponentFrom: colorString start: 1 length: 1];
        blue  = [SharedUtility colorComponentFrom: colorString start: 2 length: 1];
        break;
    case 4: // #ARGB
        alpha = [SharedUtility colorComponentFrom: colorString start: 0 length: 1];
        red   = [SharedUtility colorComponentFrom: colorString start: 1 length: 1];
        green = [SharedUtility colorComponentFrom: colorString start: 2 length: 1];
        blue  = [SharedUtility colorComponentFrom: colorString start: 3 length: 1];
        break;
    case 6: // #RRGGBB
        alpha = 1.0f;
        red   = [SharedUtility colorComponentFrom: colorString start: 0 length: 2];
        green = [SharedUtility colorComponentFrom: colorString start: 2 length: 2];
        blue  = [SharedUtility colorComponentFrom: colorString start: 4 length: 2];
        break;
    case 8: // #AARRGGBB
        alpha = [SharedUtility colorComponentFrom: colorString start: 0 length: 2];
        red   = [SharedUtility colorComponentFrom: colorString start: 2 length: 2];
        green = [SharedUtility colorComponentFrom: colorString start: 4 length: 2];
        blue  = [SharedUtility colorComponentFrom: colorString start: 6 length: 2];
        break;
    default:
        LOG(@"WARNING: tried to set color from string: %@ BUT string should be  a hex value of the form #RBG, #ARGB, #RRGGBB, or #AARRGGBB ", hexString);
        return nil;
        break;
}
return [UIColor colorWithRed: red green: green blue: blue alpha: alpha];
}

现在，当我想使用我的扩展函数时，例如： self.background=Color_C7。直接与颜色搭配 “directOrLegacyWithColor”功能不可见

在您的方法中，请将“self”更改为“[UIColor self]”

---

将“self”更改为“[UIColor self]”。警告意志go@manishsharma93问题解决了，谢谢。但是现在我有另一个问题，当我想使用例如Color_C7。directOrLegacyWithColor方法“directOrLegacyWithColor”不可见。是否可以使用Color_C7和Color_Direct的值更新答案。这样我就很容易找到原因了。我会写上面的评论作为回答，如果它解决了你的问题，请接受。我接受了你的答案，但在编辑中我添加了另一个one@taratandel谢谢你的回答。但我认为您无法访问宏上的UIColor类方法。因此，您可以做的是，创建一个UIColor对象并将值放入其中，例如，UIColor*color=[UIColor director egacyWithColor]；。然后你可以随意使用这些颜色我可以这样做吗？+（UIColor*）director egacywithcolor:（UIColor*）color{UIColor*newColor；UIColor*returenedColor=self.changeColor:color；newColor=LoginsManager.getSharedInstance.isDirect？returenedColor:[UIColor-self]；return newColor；}+（UIColor*）changeColor:（UIColor*）color*）color{UIColor*newColor；if（self==color\u C7）newColor=Color\u Direct；返回newColor；}是。试着这样做。我仍然得到一个错误：“struct objc_class”中没有名为“changeColor”的成员