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Ios 无法调用类型为';检查表';具有类型为';(())和#x27;_Ios_Iphone_Swift - Fatal编程技术网

Ios 无法调用类型为';检查表';具有类型为';(())和#x27;

Ios 无法调用类型为';检查表';具有类型为';(())和#x27;,ios,iphone,swift,Ios,Iphone,Swift,在清单声明上,它显示了一个错误。 这是我的代码: required init(coder aDecoder: NSCoder) { lists = [Checklist]() super.init(coder: aDecoder) var name: String var list = Checklist(name = " Birthdays") lists.append(list) list = Checklist(name = "Gro

在清单声明上,它显示了一个错误。 这是我的代码:

required init(coder aDecoder: NSCoder)
{
    lists = [Checklist]()

    super.init(coder: aDecoder)

    var name: String

    var list = Checklist(name = " Birthdays")
    lists.append(list)

    list = Checklist(name = "Groceries")
    lists.append(list)

    list = Checklist(name = "Cool Apps")
    lists.append(list)

    list = Checklist(name = "To Do")
    lists.append(list)


}

假设另一个
init
方法如下所示:

required init(name theName: String)
{
     // theName is the parameter and String is the type
}
你应该这样做:

list = Checklist("To Do")

花点时间阅读Swift文档。但是我如何解决这些问题呢?通过学习Swift语言。是的,这需要时间,是单调乏味的,但这是必须付出的代价。谢谢。你知道Swift语言的教程吗苹果有一本关于这种语言的iBook:Swift程序语言。教程关注的范围很窄,通常假定对该语言有相当好的了解。也可以通过iTunes查看。