Ios 替换数组中字符串中的特殊字符

下面是我的代码：

NSString *str = [EpiC objectAtIndex:indexPath.row];
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"];
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\"];
NSLog(@"%@", str); 

它显示的错误如下所示： 此行的未知转义序列：

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"];

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\"];

和程序中意外的“@”，在此行：

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"];

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\"];

未知转义序列意味着您必须用第二个反斜杠转义反斜杠

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];

附加反斜杠也解决了程序中意外的“@”错误。

未知转义序列意味着您必须用第二个反斜杠转义反斜杠

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];

附加的反斜杠也解决了程序中意外的“@”错误。

您喜欢吗

 NSString *str = @"FSJ\/6356232";
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"];
       NSLog(@"%@", str);

你得到了

你喜欢吗

 NSString *str = @"FSJ\/6356232";
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"];
       NSLog(@"%@", str);

你得到了

---

按以下步骤做，我相信这对你很有用

 NSString *str = @"FSJ\/6356232";
 NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];
 str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"];
       NSLog(@"%@", str);

---

照我说的做，我相信对你有用

 NSString *str = @"FSJ\/6356232";
 NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"];
 str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"];
       NSLog(@"%@", str);

---

你能显示你的字符串吗？

str

@Anbu.Karthik FSJ\/6356232这是字符串，我想要它是FSJ\6356232你能显示你的字符串吗？

str

@Anbu.Karthik FSJ\/6356232这是字符串，我希望是FSJ\6356232你的答案和我的答案有什么区别对不起，我没有显示你的答案，而我会给出答案没关系，没问题，你的答案和我的答案有什么区别对不起，我没有显示你的答案，而我会给出答案没问题