Ios 如何根据设备屏幕大小调整集合视图中单元格的大小？

我在Swift工作，我希望我的手机看起来和iPhone 8 plus上这张照片上的手机一样

但当我把它装到iPad上时，电池的大小并不能适应屏幕的大小。看起来是这样的：

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有人知道我如何在CollectionViewController中执行此操作吗？

UICollectionViewDelegateFlowLayout中有一个委托方法

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, sizeForItemAt indexPath: IndexPath) -> CGSize {


    let collectionViewCellSize = collectionView.frame.size.width / 10 // to show 10 cells in a row

    return CGSize(width: collectionViewCellSize, height: collectionViewCellSize)
}
func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, insetForSectionAt section: Int) -> UIEdgeInsets {
    return UIEdgeInsetsMake(0, 0, 0, 0)
}

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, minimumInteritemSpacingForSectionAt section: Int) -> CGFloat {
    return 0
}

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, minimumLineSpacingForSectionAt section: Int) -> CGFloat {
    return 0
}

试试这个

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, sizeForItemAt indexPath: IndexPath) -> CGSize {
    let yourWidth = (collectionView.bounds.width) / 10.0
    let yourHeight = yourWidth

    return CGSize(width: yourWidth, height: yourHeight)
}

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, insetForSectionAt section: Int) -> UIEdgeInsets {
    return UIEdgeInsetsMake(0, 0, 0, 0)
}

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, minimumInteritemSpacingForSectionAt section: Int) -> CGFloat {
    return 0
}

func collectionView(_ collectionView: UICollectionView, layout collectionViewLayout: UICollectionViewLayout, minimumLineSpacingForSectionAt section: Int) -> CGFloat {
    return 0
}

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请出示你的护照code@Tessa，如果这对您有帮助，您可以接受此答案并对此进行投票。随时欢迎：）