Ios 截取UIWebView中图像中的链接

在我的应用程序中，我有一个webview，我想在一个单独的视图控制器中打开加载在网页中的图像，这很好，我所需要做的就是获取图像源的URL并将其加载到另一个视图控制器中，我可以这样做

下面是我用来获取图像源URL的代码

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    if ([gestureRecognizer isKindOfClass:[UITapGestureRecognizer class]]) {
        CGPoint touchPoint = [touch locationInView:self.view];

        NSString *imageSRC = [NSString stringWithFormat:@"document.elementFromPoint(%f, %f).src", touchPoint.x, touchPoint.y];
        NSString *srcOfImage = [webView stringByEvaluatingJavaScriptFromString:imageSRC];
        NSLog(@"src:%@",srcOfImage);
    }
    return YES;
}

---

现在，我的问题是，有时，当图像可能有链接（即标记）时，webview会在图像在我的单独视图控制器中打开时加载链接。我想做的是，如果存在链接，请停止webview打开链接（仅限于图像中的链接）。有没有关于我如何实现这一目标的建议？

最终找到了答案，答案就在UIWebViewDelegate中。对于任何感兴趣的人，以下是我如何解决的

bool isImage;

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    if ([gestureRecognizer isKindOfClass:[UITapGestureRecognizer class]]) {
        CGPoint touchPoint = [touch locationInView:self.view];

        NSString *imageSRC = [NSString stringWithFormat:@"document.elementFromPoint(%f, %f).src", touchPoint.x, touchPoint.y];
        NSString *srcOfImage = [webView stringByEvaluatingJavaScriptFromString:imageSRC];
        NSLog(@"src:%@",srcOfImage);
        NSURL *imgsrcURL = [NSURL URLWithString:srcOfImage];
        if (imgsrcURL && imgsrcURL.scheme && imgsrcURL.host) {
            isImage = TRUE;
        }
    }
    return YES;
}

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
    if ((navigationType == UIWebViewNavigationTypeLinkClicked) && (isImage)) {
        return NO;
        isImage = FALSE;
    } else {
        return YES;
    }
}