Ios 转换为纹理时缺少UIImage的透明度

我将UIImage转换为纹理，然后将该纹理转换为UIImage。透明区域将替换为黑色

我用于将UIImage转换为纹理的函数

func imageToTexture(imageNamed: String, device: MTLDevice) -> MTLTexture {
    let bytesPerPixel = 4
    let bitsPerComponent = 8

    var image = UIImage(named: imageNamed)!

    let width = Int(image.size.width)
    let height = Int(image.size.height)

    let bounds = CGRect(x: 0, y: 0, width: CGFloat(width), height: CGFloat(height))
    var rowBytes = width * bytesPerPixel
    var colorSpace = CGColorSpaceCreateDeviceRGB()

    let context = CGContext(data: nil, width: width, height: height, bitsPerComponent: bitsPerComponent, bytesPerRow: rowBytes, space: colorSpace, bitmapInfo: CGBitmapInfo(rawValue: CGImageAlphaInfo.premultipliedLast.rawValue).rawValue)

    context!.clear(bounds)
    context?.translateBy(x: CGFloat(width), y: CGFloat(height))
    //  CGContextTranslateCTM(context!, CGFloat(width), CGFloat(height))
    context?.scaleBy(x: -1.0, y: -1.0)
    //   CGContextScaleCTM(context!, -1.0, -1.0)
    context?.draw(image.cgImage!, in: bounds)
    //  CGContextDrawImage(context, bounds, image.CGImage)

    var texDescriptor = MTLTextureDescriptor.texture2DDescriptor(pixelFormat: .bgra8Unorm , width: width, height: height, mipmapped: true)

    var texture = device.makeTexture(descriptor: texDescriptor)
    texture?.label = imageNamed

    // var pixelsData = CGBitmapContextGetData(context!)
    var pixelsData = context?.data
    var region = MTLRegionMake2D(0, 0, width, height)
    texture?.replace(region: region, mipmapLevel: 0, withBytes: pixelsData!, bytesPerRow: rowBytes)

    makeImage(from: texture!)
    return texture!
}

将纹理转换为图像的函数。将UIImage更改为纹理后，我正在调用将其转换回UIImage。事实并非如此

func makeImage(from texture: MTLTexture) -> UIImage? {
    let width = texture.width
    let height = texture.height
    let bytesPerRow = width * 4

    let data = UnsafeMutableRawPointer.allocate(bytes: bytesPerRow * height, alignedTo: 4)
    defer {
        data.deallocate(bytes: bytesPerRow * height, alignedTo: 4)
    }

    let region = MTLRegionMake2D(0, 0, width, height)
    texture.getBytes(data, bytesPerRow: bytesPerRow, from: region, mipmapLevel: 0)

    var buffer = vImage_Buffer(data: data, height: UInt(height), width: UInt(width), rowBytes: bytesPerRow)

    let map: [UInt8] = [2, 1, 0, 3]
    vImagePermuteChannels_ARGB8888(&buffer, &buffer, map, 0)

    guard let colorSpace = CGColorSpace(name: CGColorSpace.genericRGBLinear) else { return nil }
    guard let context = CGContext(data: data, width: width, height: height, bitsPerComponent: 8, bytesPerRow: bytesPerRow,
                                  space: colorSpace, bitmapInfo: CGImageAlphaInfo.noneSkipLast.rawValue) else { return nil }
    guard let cgImage = context.makeImage() else { return nil }

    let x =  UIImage(cgImage: cgImage)
    return x;
}

---

此处，输出图像在透明区域为黑色。我不知道我哪里搞砸了。

您正在使用

CGImageAlphaInfo.noneSkipLast

创建位图上下文。您明确告诉它忽略数据中的alpha分量。此外，您可能应该直接从数据创建

CGImage

，而不是通过位图上下文。Ken所说的是最可能的原因。要扩展它，我觉得

imageToTexture

函数很好，请尝试在

makeImage

中使用

CGImageAlphaInfo.premultipledLast

来匹配

imageToTexture

。旁注：如果您只是在进行原型设计，您可能需要考虑使用CoreImage将

UIImage

渲染为

CVPixelBuffer

，将

CVPixelBufferMetalCompatibilityKey

设置为true时从

CVPixelBuffer池

生成的

。您可以使用
CVMetalTextureCacheCreateTextureFromImage（）
获取映射绑定到与该像素缓冲区相同内存的
MTLTexture
。“以我的经验来说，这让事情变得更容易了。”肯特·霍马斯说，谢谢