Ios 两个点之间的距离(带CLLOCATIONCOORDIATE2D) 细节
我试图测量地图上两个坐标(经度、纬度)之间的距离。第一个坐标是我的当前位置,它是一个Ios 两个点之间的距离(带CLLOCATIONCOORDIATE2D) 细节,ios,ios7,core-location,cllocationmanager,Ios,Ios7,Core Location,Cllocationmanager,我试图测量地图上两个坐标(经度、纬度)之间的距离。第一个坐标是我的当前位置,它是一个CLLocation,另一个是地图上的一个pin,类型为CLLocationCoordinate2D CLLocationCoordinate2D locationCoordinate; // Set the latitude and longitude locationCoordinate.latitude = [[item objectForKey:@"lat"] doubleValue]; locati
CLLocation
,另一个是地图上的一个pin,类型为CLLocationCoordinate2D
CLLocationCoordinate2D locationCoordinate;
// Set the latitude and longitude
locationCoordinate.latitude = [[item objectForKey:@"lat"] doubleValue];
locationCoordinate.longitude = [[item objectForKey:@"lng"] doubleValue];
CLLocationDistance dist = [locationCoordinate distanceFromLocation:locationManager.location.coordinate]; // bad receiver type from CLLocationCoordinate2D
问题
我调用distance fromLocation
以获取CLLocation
中的当前位置,但它显示CLLocationCoordinate2D
中的接收器类型不正确
CLLocationCoordinate2D locationCoordinate;
// Set the latitude and longitude
locationCoordinate.latitude = [[item objectForKey:@"lat"] doubleValue];
locationCoordinate.longitude = [[item objectForKey:@"lng"] doubleValue];
CLLocationDistance dist = [locationCoordinate distanceFromLocation:locationManager.location.coordinate]; // bad receiver type from CLLocationCoordinate2D
问题:
我想用公制单位来计算这两个坐标之间的距离,我知道类型不匹配,但是如何转换它们以便我可以计算这两个节点之间的距离?使用下面的方法来计算两个位置之间的距离
-(float)kilometersfromPlace:(CLLocationCoordinate2D)from andToPlace:(CLLocationCoordinate2D)to {
CLLocation *userloc = [[CLLocation alloc]initWithLatitude:from.latitude longitude:from.longitude];
CLLocation *dest = [[CLLocation alloc]initWithLatitude:to.latitude longitude:to.longitude];
CLLocationDistance dist = [userloc distanceFromLocation:dest]/1000;
//NSLog(@"%f",dist);
NSString *distance = [NSString stringWithFormat:@"%f",dist];
return [distance floatValue];
}
例如:
+(double)distanceFromPoint:(double)lat lng:(double)lng
{
CLLocation *placeLocation = [[CLLocation alloc] initWithLatitude:lat longitude:lng];
CLLocationCoordinate2D usrLocation = locationManager.location;
CLLocation * userLocation = [[CLLocation alloc] initWithLatitude:usrLocation.latitude longitude:usrLocation.longitude];
double meters = [userLocation distanceFromLocation:placeLocation];
return meters;
}
尝试将
CLLocationCoordinate2D
转换为CLLocation
使用创建CLLocation
对象
-(id)initWithLatitude:(CLLocationDegrees)latitude longitude:(CLLocationDegrees)longitude
根据@manujmv上面的回答,这里有一个快速扩展(返回米):
distanceFromLocation方法位于CLLocation类中,它将CLLocation对象作为参数(而不是CLLocationCoordinate2D结构)。这就是错误的意思。是的,我知道我为什么会出现这个错误,但我不知道如何将它转换为工作状态!实际上最好返回一个double,因为
distance fromLocation
的结果是一个CLLocationDistance,它实际上是一个double。