Ios 如何检查Objective-C中的字符串是否包含其他字符串?

Ios 如何检查Objective-C中的字符串是否包含其他字符串?,ios,objective-c,string,range,substring,Ios,Objective C,String,Range,Substring,如何检查字符串(NSString)是否包含另一个较小的字符串 我希望有这样的事情: NSString *string = @"hello bla bla"; NSLog(@"%d",[string containsSubstring:@"hello"]); 但我能找到的最接近的是: if ([string rangeOfString:@"hello"] == 0) { NSLog(@"sub string doesnt exist"); } else { NSLog(@"ex

如何检查字符串(
NSString
)是否包含另一个较小的字符串

我希望有这样的事情:

NSString *string = @"hello bla bla";
NSLog(@"%d",[string containsSubstring:@"hello"]);
但我能找到的最接近的是:

if ([string rangeOfString:@"hello"] == 0) {
    NSLog(@"sub string doesnt exist");
} 
else {
    NSLog(@"exists");
}
无论如何,这是确定一个字符串是否包含另一个字符串的最佳方法吗

NSString *string = @"hello bla bla";
if ([string rangeOfString:@"bla"].location == NSNotFound) {
  NSLog(@"string does not contain bla");
} else {
  NSLog(@"string contains bla!");
}
关键是要注意,
rangeOfString:
返回一个
NSRange
struct,如果“草堆”不包含“针”,则返回struct
{NSNotFound,0}


如果您使用的是iOS 8或OS X Yosemite,您现在可以执行以下操作:(*注意:如果在iOS 7设备上调用此代码,您的应用程序将崩溃)。

NSString *string = @"hello bla blah";
if ([string containsString:@"bla"]) {
  NSLog(@"string contains bla!");
} else {
  NSLog(@"string does not contain bla");
}
(这也是它在Swift中的工作方式)


对于iOS 8.0+和macOS 10.10+,可以使用NSString的本机

对于较旧版本的iOS和macOS,您可以为NSString创建自己的(过时)类别:

@interface NSString ( SubstringSearch )
    - (BOOL)containsString:(NSString *)substring;
@end

// - - - - 

@implementation NSString ( SubstringSearch )

- (BOOL)containsString:(NSString *)substring
{    
    NSRange range = [self rangeOfString : substring];
    BOOL found = ( range.location != NSNotFound );
    return found;
}

@end
注意:请注意下面丹尼尔·加拉斯科关于命名的评论

NSString *myString = @"hello bla bla";
NSRange rangeValue = [myString rangeOfString:@"hello" options:NSCaseInsensitiveSearch];

if (rangeValue.length > 0)
{
    NSLog(@"string contains hello");
} 
else 
{
    NSLog(@"string does not contain hello!");
}
//您也可以使用以下选项:

if (rangeValue.location == NSNotFound) 
{
    NSLog(@"string does not contain hello");
} 
else 
{
    NSLog(@"string contains hello!");
}
Oneliner(代码量较小。干燥,因为您只有一个
NSLog
):

NSString上的一个类别的改进版本,它不仅可以告诉您是否在另一个字符串中找到了一个字符串,还可以通过引用获取一个范围,如下所示:

@interface NSString (Contains)
-(BOOL)containsString: (NSString*)substring
              atRange:(NSRange*)range;

-(BOOL)containsString:(NSString *)substring;
@end

@implementation NSString (Contains)

-(BOOL)containsString:(NSString *)substring
              atRange:(NSRange *)range{

    NSRange r = [self rangeOfString : substring];
    BOOL found = ( r.location != NSNotFound );
    if (range != NULL) *range = r;
    return found;
}

-(BOOL)containsString:(NSString *)substring
{
    return [self containsString:substring
                        atRange:NULL];
}

@end
像这样使用它:

NSString *string = @"Hello, World!";

//If you only want to ensure a string contains a certain substring
if ([string containsString:@"ello" atRange:NULL]) {
    NSLog(@"YES");
}

// Or simply
if ([string containsString:@"ello"]) {
    NSLog(@"YES");
}

//If you also want to know substring's range
NSRange range;
if ([string containsString:@"ello" atRange:&range]) {
    NSLog(@"%@", NSStringFromRange(range));
}

下面是一个复制粘贴函数片段:

-(BOOL)Contains:(NSString *)StrSearchTerm on:(NSString *)StrText
{
    return [StrText rangeOfString:StrSearchTerm 
        options:NSCaseInsensitiveSearch].location != NSNotFound;
}

由于这似乎是谷歌排名靠前的结果,我想补充一点:

iOS 8和OS X 10.10将该方法添加到
NSString
。Dave DeLong针对这些系统的示例的更新版本:

NSString *string = @"hello bla bla";
if ([string containsString:@"bla"]) {
    NSLog(@"string contains bla!");
} else {
    NSLog(@"string does not contain bla");
}

使用iOS 8Swift,我们可以使用
localizedCaseInsensitiveContainsString
方法

 let string: NSString = "Café"
 let substring: NSString = "É"

 string.localizedCaseInsensitiveContainsString(substring) // true

如果需要,请写下:

NSString *stringToSearchThrough = @"-rangeOfString method finds and returns the range of the first occurrence of a given string within the receiver.";
BOOL contains = [stringToSearchThrough rangeOfString:@"occurence of a given string"].location != NSNotFound;

如果不介意区分大小写的字符串。 试试这个

NSString *string  = @"Hello World!";

if([string rangeOfString:@"hello" options:NSCaseInsensitiveSearch].location !=NSNotFound)
{
    NSLog(@"found");
}
else
{
    NSLog(@"not found");
}
请使用此代码

NSString*string=@“hello bla bla”;
if([string rangeOfString:@“bla”].location==NSNotFound)
{
NSLog(@“字符串不包含bla”);
} 
其他的
{  
NSLog(@“字符串包含bla!”);
}

所以就我个人而言,我真的很讨厌
NSNotFound
,但我明白它的必要性

但有些人可能不理解与NSNotFound进行比较的复杂性

例如,此代码:

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {
    if([string rangeOfString:otherString].location != NSNotFound)
        return YES;
    else
        return NO;
}
NSLog(@"does string contain string - %@", [self doesString:nil containString:@"hey"] ? @"YES": @"NO");
NSLog(@"does string contain string - %@", [self doesString:nil containString:nil] ? @"YES": @"NO");
有它的问题:

1) 显然,如果
otherString=nil
此代码将崩溃。一个简单的测试是:

NSLog(@"does string contain string - %@", [self doesString:@"hey" containString:nil] ? @"YES": @"NO");
结果是!!撞车

2) 对于刚接触objective-c的人来说,不太明显的是,当
string=nil
时,相同的代码不会崩溃。 例如,此代码:

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {
    if([string rangeOfString:otherString].location != NSNotFound)
        return YES;
    else
        return NO;
}
NSLog(@"does string contain string - %@", [self doesString:nil containString:@"hey"] ? @"YES": @"NO");
NSLog(@"does string contain string - %@", [self doesString:nil containString:nil] ? @"YES": @"NO");
该代码:

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {
    if([string rangeOfString:otherString].location != NSNotFound)
        return YES;
    else
        return NO;
}
NSLog(@"does string contain string - %@", [self doesString:nil containString:@"hey"] ? @"YES": @"NO");
NSLog(@"does string contain string - %@", [self doesString:nil containString:nil] ? @"YES": @"NO");
两者都会导致

does string contains string - YES
这显然不是你想要的

我认为更好的解决方案是使用rangeOfString返回长度为0的事实,因此更好更可靠的代码是:

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {
    if(otherString && [string rangeOfString:otherString].length)
        return YES;
    else
        return NO;
}
或者简单地说:

- (BOOL)doesString:(NSString*)string containString:(NSString*)otherString {
    return (otherString && [string rangeOfString:otherString].length);
}
对于案例1和案例2,将返回

does string contains string - NO
那是我的2美分;-)

请查看my以获取更多有用的代码。

试试这个

NSString*string=@“测试数据”;
if([[string lowercaseString]rangeOfString:@“data”].location==NSNotFound)
{
NSLog(@“字符串不包含数据”);
}   
其他的
{
NSLog(@“字符串包含数据!”);
}

如果是swift,可以使用

let string = "Package #23"
if string.containsString("Package #") {
    //String contains substring
}
else {
    //String does not contain substring
}

最佳解决方案。就这么简单!如果你想找一个词或 绳子的一部分。您可以使用此代码。在本例中,我们将检查word的值是否包含“acter”


如果需要字符串的特定位置,则此代码将出现在Swift 3.0中:

let string = "This is my string"
let substring = "my"

let position = string.range(of: substring)?.lowerBound
在Swift 4中:

let a = "Hello, how are you?"
a.contains("Hello")   //will return true

第一个字符串是否包含第二个字符串

NSString *first = @"Banana";
NSString *second = @"BananaMilk";
NSRange range = [first rangeOfString:second options:NSCaseInsensitiveSearch];

if (range.length > 0) {
    NSLog(@"Detected");
}
else {
    NSLog(@"Not detected");
}

将选项NSCaseInsensitiveSearch与rangeOfString:options一起使用:

NSString *me = @"toBe" ;
NSString *target = @"abcdetobe" ;
NSRange range = [target  rangeOfString: me options: NSCaseInsensitiveSearch];
NSLog(@"found: %@", (range.location != NSNotFound) ? @"Yes" : @"No");
if (range.location != NSNotFound) {
// your code
}
找到输出结果:是

选项可以一起“或”排列,包括:

NSCase不敏感研究 非文字搜索
NSBackardsSearch及更多

Swift 4及以上

let str = "Hello iam midhun"

if str.contains("iam") {
  //contains substring
}
else {
  //doesn't contain substring
}
目标-C

NSString *stringData = @"Hello iam midhun";

if ([stringData containsString:@"iam"]) {
    //contains substring
}
else {
    //doesn't contain substring
}
试试这个:

Swift 4.1、4.2:

let stringData = "Black board"

//swift quick way and case sensitive
if stringData.contains("bla") {
    print("data contains string");
}

//case sensitive
if stringData.range(of: "bla",options: .caseInsensitive) != nil {
    print("data contains string");
}else {
    print("data does not contains string");
}
NSString *stringData = @"Black board";

//Quick way and case sensitive
if ([stringData containsString:@"bla"]) {
    NSLog(@"data contains string");
}

//Case Insensitive
if ([stringData rangeOfString:@"bla" options:NSCaseInsensitiveSearch].location != NSNotFound) {
   NSLog(@"data contains string");
}else {
   NSLog(@"data does not contain string");
}
对于目标C:

let stringData = "Black board"

//swift quick way and case sensitive
if stringData.contains("bla") {
    print("data contains string");
}

//case sensitive
if stringData.range(of: "bla",options: .caseInsensitive) != nil {
    print("data contains string");
}else {
    print("data does not contains string");
}
NSString *stringData = @"Black board";

//Quick way and case sensitive
if ([stringData containsString:@"bla"]) {
    NSLog(@"data contains string");
}

//Case Insensitive
if ([stringData rangeOfString:@"bla" options:NSCaseInsensitiveSearch].location != NSNotFound) {
   NSLog(@"data contains string");
}else {
   NSLog(@"data does not contain string");
}

+1以获得更清晰的结果代码和可重用性。我把它变成了一行
return[self-rangeOfString:substring]。location!=NSNotFound并将其包含在我的重构库es_ios_utils中。看起来苹果喜欢你的想法,并在iOS 8和OSx 10.10(约塞米蒂)中添加了这一功能,正如@DaveDeLong在回答中提到的那样+1 obj-c类别的主要规则是在方法名称前加上3个字母的模块前缀。这是一个完美的例子,因为它现在与iOS 7和10.10版本冲突,使用“if([string rangeOfString:@“bla”options:NSCaseInsensitiveSearch].location!=NSNotFound)”进行不区分大小写的搜索。Dave DeLong在阅读您的编辑答案之前,我只想提到我为此创建的一个类别!由于我主要是一名c#开发人员,我很高兴他们在NSSTring中添加了一个contains方法。如果我的部署目标是iOS7,而我使用containssString,为什么编译器什么也不说呢?为了进一步说明@Vanja提出的观点:如果你要使用iOS 8/Yosemite中引入的[string containssString]快捷方式代码,您可以对不区分大小写的字符串使用以下代码:“[stringToSearch localizedCaseInsensitiveContainsString:string]”,如果要执行不区分大小写和变音符号的搜索,则可以使用此代码:“[stringToSearch localizedStandardContainsString:string]”。请注意表达式
[string rangeOfString:@“bla”]。位置!=当字符串为
nil
时,NSNotFound将为真!我也希望看到它被添加,但同时在NSString上添加它作为一个类别相对容易。使用
if([string rangeOfString:@“hello”]==0){…}
NSRange和int存在类型不匹配错误。要解决这个问题,应该将行更改为以下内容:
if([string rangeOfString:@“hello”])。length==0{…}
iOS 8添加了containssString:下面是一种添加iOS的微创方法