Iphone 如何使我的UIPickerView显示数组的所有元素

我有一个UIPickerView和一个数组，尽管我似乎无法将数组中的所有日期输入UIPicker

我知道语法应该是这样的：

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
   return [treatments objectAtIndex:row];
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
   return[[treatments objectAtIndex:row]valueForKey:@"YourKey"];
}

其中，treatments是数组名，但当我使用它时，会出现以下错误：

-[Treatment isEqualToString:]: unrecognized

我已经搜索了整个项目，但找不到短语：

isEqualToString

处理.h文件：

#import <Foundation/Foundation.h>

@interface Treatment : NSObject {
    NSString *treatmentid;
    NSString *treatmentName;
    NSString *treatmentPrice;
}

@property (nonatomic, strong) NSString *treatmentid;
@property (nonatomic, strong) NSString *treatmentName;
@property (nonatomic, strong) NSString *treatmentPrice;

@end

如果你需要更多的代码，就说

---

提前感谢

如果您的数组包含Dictionars或NSMutableDictionars，则必须使用其键指定数组的值，如下图所示。请尝试这样编写方法：

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
   return [treatments objectAtIndex:row];
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
   return[[treatments objectAtIndex:row]valueForKey:@"YourKey"];
}

以下是Picker view示例代码的基本实现：-

- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)thepickerView
{
    return 1;
}

- (NSInteger)pickerView:(UIPickerView *)thepickerView numberOfRowsInComponent:(NSInteger)component
{
        return [treatments count];
}

自定义UIpickerview的显示标签，如下图所示：-

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
{
    UILabel *label = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 300, 37)];



        if (component == 0) {

            label.font=[UIFont boldSystemFontOfSize:22];
            label.textAlignment = UITextAlignmentCenter;
            label.backgroundColor = [UIColor clearColor];



            label.text = [NSString stringWithFormat:@"%d", row];
            label.font=[UIFont boldSystemFontOfSize:22];

             NSLog(@"%@",[yourpickerview selectedRowInComponent:component]);

        }

    return label;

}
- (void)pickerView:(UIPickerView *)thePickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{

   NSLog(@"%@",[treatments objectAtIndex:row]);

}

---

删除你的应用程序。从模拟器，清理你的项目，然后重新运行。我该怎么做？？？我对这东西很陌生，所以去你的模拟器，按下应用程序的图标，删除你的应用程序。然后转到xcode项目和“产品”手册并选择“清洁”。。然后运行你的应用程序@iPatel还是一样的问题我想给你一个解决方案，你介意我问你另一个突然出现的问题吗