Java Can';t在EditText中显示转换后的JSONObject
我试图在android应用程序的EditText字段中显示已转换为字符串的JSONObject。当我运行应用程序时,它会无误加载,但我的EditText字段为空。我还试着做System.out.println(name);但是没有打印到控制台上,所以我最好的猜测是,控制台上实际上没有存储任何内容,我不确定原因。Java Can';t在EditText中显示转换后的JSONObject,java,android,Java,Android,我试图在android应用程序的EditText字段中显示已转换为字符串的JSONObject。当我运行应用程序时,它会无误加载,但我的EditText字段为空。我还试着做System.out.println(name);但是没有打印到控制台上,所以我最好的猜测是,控制台上实际上没有存储任何内容,我不确定原因。 这是我的主要文件 package com.apitest.rottentomatoestest; import android.os.Bundle; import java.u
这是我的主要文件
package com.apitest.rottentomatoestest;
import android.os.Bundle;
import java.util.ArrayList;
import java.util.HashMap;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import org.json.*;
import android.app.Activity;
import android.util.Log;
import android.view.Menu;
import android.widget.TextView;
import android.widget.EditText;
import java.util.logging.*;
public class Main extends Activity {
private static String url = "http://api.rottentomatoes.com/api/public/v1.0/movies/770672123/cast.json?apikey=3p9ehnhzbxwpd6mk8fnncf67";
private static final String TAG_CAST = "cast";
private static final String TAG_ID = "id";
private static final String TAG_NAME = "name";
private static final String TAG_CHARACTERS = "characters";
EditText display;
@Override
public void onCreate(Bundle savedInstanceState) {
try
{
super.onCreate(savedInstanceState);
setContentView(R.layout.mainlayout);
JSONArray cast = null;
JSONParser jParser = new JSONParser();
JSONObject jSon = jParser.getJSONFromUrl(url);
display = (EditText) findViewById(R.id.display);
try
{
cast = jSon.getJSONArray(TAG_CAST);
for(int i=0; i < cast.length(); i++){
JSONObject c = cast.getJSONObject(i);
String name = c.getString(TAG_NAME);
display.setText(name);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
catch (Exception e){
Log.e("ERROR", "ERROR IN CODE" + e.toString());
e.printStackTrace();
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.mainlayout, menu);
return true;
}
}
cast=jSon.getJSONArray(TAG_cast);
对于(int i=0;i
您最好检查
name
的最后一个值。您是否在打印服务器的响应时检查了它?确保您从服务器获得有效响应实际上给定的url返回json{“error”:“notauthorized”}
这就是原因吗?我尝试通过System.out.println(name)检查name的最后一个值,但这不会将任何内容打印到控制台。是否有其他方法可以检查值?在LogCat中,我得到了一个NullPointerException错误和一个解析数据的错误,该数据读取的输入末尾为的字符0。这之后就没有什么了。如何检查我是否收到服务器的响应?能否粘贴在classJSONParser
中获得的json
字符串值?给定的url返回{“error”:“Not Authorized”}
以下url对我有效:当我在浏览器中输入该url时,它将正常加载。我已检查了您的代码并获得了值。检查httpClient.execute(httpPost)
,是否存在抛出异常unknownhostexception
?也许你忘了权限了我昨晚抓到了一个未知的例外。我授予应用程序权限,然后它开始抛出以下错误。分析数据JSONException时出错:无法将java.lang.String类型的值596转换为JSONObejct。代码NullPointerException中出错。
package com.apitest.rottentomatoestest;
import java.io.*;
import org.apache.http.*;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.*;
import android.util.Log;
public class JSONParser {
static InputStream inputStream = null;
static JSONObject jObject = null;
static String jSon = "";
public JSONParser() {
// TODO Auto-generated constructor stub
}
public JSONObject getJSONFromUrl(String url){
//Make HTTP Request
try {
//defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
inputStream = httpEntity.getContent();
} catch (UnsupportedEncodingException e){
e.printStackTrace();
} catch (ClientProtocolException e){
e.printStackTrace();
}catch (IOException e){
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"), 8);
StringBuilder stringBuilder = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null){
stringBuilder.append(line + "\n");
}
inputStream.close();
jSon = stringBuilder.toString();
} catch (Exception e){
Log.e("Buffer Error", "Error converting result " + e.toString());
}
//try to parse the string to JSON Object
try {
jObject = new JSONObject(jSon);
} catch (JSONException e){
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
//return JSON String
return jObject;
}
}
cast = jSon.getJSONArray(TAG_CAST);
for(int i=0; i < cast.length(); i++){
JSONObject c = cast.getJSONObject(i);
String name = c.getString(TAG_NAME);
display.setText(name);
}