如何在Java中使用XStream构建外观更好的XML？

我在一个类中创建了一个main（）方法来测试XML文件的构造

public static void main(String[] args) {
    createXmlEmail();
}

private static void createXmlEmail() {
    XStream xstream = new XStream(new DomDriver());
    xstream.setMode(XStream.NO_REFERENCES);
    xstream.alias("email", EmailPojo.class);
    xstream.alias("recipient", Recipient.class);

    EmailPojo ep = new EmailPojo();

    List<Recipient> toRecipient = new ArrayList<Recipient>();
    toRecipient.add(new Recipient("user1@somecompany.com"));
    toRecipient.add(new Recipient("user2@somecompany.com"));

    List<Recipient> ccRecipient = new ArrayList<Recipient>();
    ccRecipient.add(new Recipient("user3@somecompany.com"));
    ccRecipient.add(new Recipient("user4@somecompany.com"));

    List<Recipient> bccRecipient = new ArrayList<Recipient>();
    bccRecipient.add(new Recipient("user5@somecompany.com"));
    bccRecipient.add(new Recipient("user6@somecompany.com"));

    ep.setTo(toRecipient);
    ep.setCc(ccRecipient);
    ep.setBcc(bccRecipient);
    ep.setSubject("subject test");
    ep.setBody("body test");

    String xml = xstream.toXML(ep);
    System.out.println(xml);
}

这就是构建XML文件的方法

public static void main(String[] args) {
    createXmlEmail();
}

private static void createXmlEmail() {
    XStream xstream = new XStream(new DomDriver());
    xstream.setMode(XStream.NO_REFERENCES);
    xstream.alias("email", EmailPojo.class);
    xstream.alias("recipient", Recipient.class);

    EmailPojo ep = new EmailPojo();

    List<Recipient> toRecipient = new ArrayList<Recipient>();
    toRecipient.add(new Recipient("user1@somecompany.com"));
    toRecipient.add(new Recipient("user2@somecompany.com"));

    List<Recipient> ccRecipient = new ArrayList<Recipient>();
    ccRecipient.add(new Recipient("user3@somecompany.com"));
    ccRecipient.add(new Recipient("user4@somecompany.com"));

    List<Recipient> bccRecipient = new ArrayList<Recipient>();
    bccRecipient.add(new Recipient("user5@somecompany.com"));
    bccRecipient.add(new Recipient("user6@somecompany.com"));

    ep.setTo(toRecipient);
    ep.setCc(ccRecipient);
    ep.setBcc(bccRecipient);
    ep.setSubject("subject test");
    ep.setBody("body test");

    String xml = xstream.toXML(ep);
    System.out.println(xml);
}

private static void createXmlEmail（）{
XStream XStream=newxstream（newdomdriver（））；
setMode（xstream.NO_引用）；
别名（“email”，EmailPojo.class）；
别名（“收件人”，recipient.class）；
EmailPojo ep=新的EmailPojo（）；
List toRecipient=new ArrayList（）；
toRecipient.add（新收件人（“user1@somecompany.com"));
toRecipient.add（新收件人（“user2@somecompany.com"));
List ccRecipient=new ArrayList（）；
ccRecipient.add（新收件人（“user3@somecompany.com"));
ccRecipient.add（新收件人（“user4@somecompany.com"));
List bccrecient=new ArrayList（）；
b收件人。添加（新收件人（“user5@somecompany.com"));
b收件人。添加（新收件人（“user6@somecompany.com"));
ep.setTo（收件人）；
ep.setCc（CCCC接收方）；
ep.setBcc（b客户）；
ep.设置主体（“主体测试”）；
ep.立根体（“车身试验”）；
字符串xml=xstream.toXML（ep）；
System.out.println（xml）；
}

提到的EmailPojo和收件人类定义如下：

public static class EmailPojo {
        private List<Recipient> to;
        private List<Recipient> cc;
        private List<Recipient> bcc;
        private String subject;
        private String body;

        public List<Recipient> getTo() {
            return to;
        }

        public void setTo(List<Recipient> to) {
            this.to = to;
        }

        public List<Recipient> getCc() {
            return cc;
        }

        public void setCc(List<Recipient> cc) {
            this.cc = cc;
        }

        public List<Recipient> getBcc() {
            return bcc;
        }

        public void setBcc(List<Recipient> bcc) {
            this.bcc = bcc;
        }

        public String getSubject() {
            return subject;
        }

        public void setSubject(String subject) {
            this.subject = subject;
        }

        public String getBody() {
            return body;
        }

        public void setBody(String body) {
            this.body = body;
        }
    }


public static class Recipient {
    private String recipient;

    public Recipient(String recipient) {
        this.recipient = recipient;
    }

    public String getRecipient() {
        return recipient;
    }

    public void setRecipient(String recipient) {
        this.recipient = recipient;
    }
}

公共静态类EmailPojo{
私人名单；
私人名单抄送；
私人名单密件抄送；
私有字符串主题；
私有字符串体；
公共列表getTo（）{
返回；
}
公共无效设置到（列表到）{
这个；
}
公共列表getCc（）{
返回cc；
}
公共无效setCc（列表cc）{
this.cc=cc；
}
公共列表getBcc（）{
返回密件抄送；
}
公用事业单位（列表密件抄送）{
this.bcc=bcc；
}
公共字符串getSubject（）{
返回主题；
}
public void setSubject（字符串主题）{
this.subject=主语；
}
公共字符串getBody（）{
返回体；
}
公共体（字符串体）{
这个身体=身体；
}
}
公共静态类收件人{
私有字符串接收者；
公共收件人（字符串收件人）{
this.recipient=收件人；
}
公共字符串getRecipient（）{
返回收件人；
}
公共空集合收件人（字符串收件人）{
this.recipient=收件人；
}
}

当我运行这个主类时，我没有得到任何错误或异常，并且输出是：

<email>
  <to>
    <recipient>
      <recipient>user1@company.com</recipient>
    </recipient>
    <recipient>
      <recipient>user2@company.com</recipient>
    </recipient>
  </to>
  <cc>
    <recipient>
      <recipient>user3@company.com</recipient>
    </recipient>
    <recipient>
      <recipient>user4@company.com</recipient>
    </recipient>
  </cc>
  <bcc>
    <recipient>
      <recipient>user5@company.com</recipient>
    </recipient>
    <recipient>
      <recipient>user6@company.com</recipient>
    </recipient>
  </bcc>
  <subject>subject test</subject>
  <body>body test</body>
</email>

user1@company.com
user2@company.com
user3@company.com
user4@company.com
user5@company.com
user6@company.com
科目测验
身体测试

但我希望是这样的：

<email>
  <to>
    <recipient>user1@company.com</recipient>
    <recipient>user2@company.com</recipient>
  </to>
  <cc>
    <recipient>user3@company.com</recipient>
    <recipient>user4@company.com</recipient>
  </cc>
  <bcc>
    <recipient>user5@company.com</recipient>
    <recipient>user6@company.com</recipient>
  </bcc>
  <subject>subject test</subject>
  <body>body test</body>
</email>

user1@company.com
user2@company.com
user3@company.com
user4@company.com
user5@company.com
user6@company.com
科目测验
身体测试

我错过了什么

---

提前谢谢

这是因为Recipient类具有属性Recipient。如果将集合标记为@XStreamImplicit，则外部收件人标记将被删除

---

请参见

可能必须使用自定义转换器i管理的变通方法来输出下面的xml。虽然没有我想象的那么好看，但它很管用。

user1@company.com     user2@company.com

你可以在这篇文章中找到答案：（参见：将对象映射到简单内容）@BlaiseDoughan，谢谢！我去看看！