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Java 如何在Spring控制器中捕获JQuery$post?_Java_Jquery_Spring Mvc_Post_Controller - Fatal编程技术网

Java 如何在Spring控制器中捕获JQuery$post?

Java 如何在Spring控制器中捕获JQuery$post?,java,jquery,spring-mvc,post,controller,Java,Jquery,Spring Mvc,Post,Controller,我创建了一个新的SpringMVC项目,然后在index.jsp中向名为springController.java的Spring控制器发送帖子。文件index.jsp: <%@page contentType="text/html" pageEncoding="UTF-8"%> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.

我创建了一个新的SpringMVC项目,然后在index.jsp中向名为springController.java的Spring控制器发送帖子。文件index.jsp:

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
    "http://www.w3.org/TR/html4/loose.dtd">

<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <script type="text/javascript" src="//code.jquery.com/jquery-1.10.2.js"></script>
        <script type="text/javascript" src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
        <title>Welcome to Spring Web MVC project</title>

        <script type="text/javascript">
             $(document).ready(function(){
                 $("#testForm").submit(onFormSubmit);
             });
             function onFormSubmit(e){

                 data = $("#testForm").serialize();
                // console.log(data);
                 $.post("/test/another");
                 e.preventDefault();
             }

        </script>
    </head>

    <body>
        <form id="testForm">
            <label>Imie: </label>
            <input type="text" name="login">
            <label>Nazwisko: </label>
            <input type="text" name="password">
            <input id="testPostButton" type="submit">
        </form>

    </body>
</html>
但是sendindpost不起作用,在WebInspector的控制台中我得到

 POST http://localhost:8084/test/another 404 (Not Found)
现在我只想从index.jsp发送catch POST。不幸的是,我是春季MVC的新手,我不知道我做错了什么。 以下是dispatcher-servlet.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:p="http://www.springframework.org/schema/p"
       xmlns:aop="http://www.springframework.org/schema/aop"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
       http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
       http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">

<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>

<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
    <property name="mappings">
        <props>
            <prop key="index.htm">indexController</prop>
        </props>
    </property>
</bean>

<bean id="viewResolver"
      class="org.springframework.web.servlet.view.InternalResourceViewResolver"
      p:prefix="/WEB-INF/jsp/"
      p:suffix=".jsp" />

<!--
The index controller.
-->
<bean name="indexController"
      class="org.springframework.web.servlet.mvc.ParameterizableViewController"
      p:viewName="index" />

<bean name="/test" class="newpackage.springController"/> 

索引控制器

下面是web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>2</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
        <welcome-file>redirect.jsp</welcome-file>
    </welcome-file-list>
</web-app>

上下文配置位置
/WEB-INF/applicationContext.xml
org.springframework.web.context.ContextLoaderListener
调度员
org.springframework.web.servlet.DispatcherServlet
2.
调度员
*.htm
30
redirect.jsp
我不知道出了什么问题,为什么我不能从springController.java中的index.jsp捕获“POST”。 这是我在StackOverflow上的第一篇文章,如果有人决定帮助我,我会非常高兴

来自波兰的问候,感谢您的帮助

这是文件应用程序上下文,我必须将文件粘贴到这里,因为我是新来的,没有足够的声誉。仍然在WebInspector的控制台中,我收到了与前面相同的消息:

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"        
xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.1.xsd                  
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context-3.1.xsd                 
    http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">




<context:component-scan base-package="by" use-default-filters="false">
    <context:include-filter expression="org.springframework.stereotype.Controller" type="annotation"/>
</context:component-scan>

<mvc:annotation-driven />
</beans>

尝试取消注释

RequestMethod.POST
在方法定义之上

还要确保您的控制器被spring识别为bean。您用@controller注释了类。要使其工作,您可以向applicationContext.xml添加配置:

    <context:component-scan base-package="newpackage" use-default-filters="false">
        <context:include-filter expression="org.springframework.stereotype.Controller" type="annotation"/>
    </context:component-scan>

    <mvc:annotation-driven />

不幸的是,它仍然不起作用,可能我将您的代码粘贴到了错误的位置,我必须在第一篇文章中粘贴文件applicationContext,因为回复消息太长,而且我没有足够的声誉来回答我自己。抱歉,请尝试将的“base package”属性从“by”更改为“newpackage”(您的类所在的包)。
    <context:component-scan base-package="newpackage" use-default-filters="false">
        <context:include-filter expression="org.springframework.stereotype.Controller" type="annotation"/>
    </context:component-scan>

    <mvc:annotation-driven />
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"          
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.1.xsd                  
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.1.xsd                 
        http://www.springframework.org/schema/mvc 
        http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd"