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Java Hazelcast锁不';不能提供同步_Java_Spring_Hazelcast - Fatal编程技术网

Java Hazelcast锁不';不能提供同步

Java Hazelcast锁不';不能提供同步,java,spring,hazelcast,Java,Spring,Hazelcast,我试图在Hazelcast中实现方法同步,但它似乎在单个集群上也不起作用 我正在使用一个简单的Hazelcast配置 @Configuration public class HazelcastConfig { @Bean HazelcastInstance hazelcastInstance(){ return Hazelcast.newHazelcastInstance(); } } 有一个示例服务,它使用时间戳生成一些ID。它应该是独一无二的,所以我

我试图在Hazelcast中实现方法同步,但它似乎在单个集群上也不起作用

我正在使用一个简单的Hazelcast配置

@Configuration
public class HazelcastConfig {
    @Bean
    HazelcastInstance hazelcastInstance(){
        return Hazelcast.newHazelcastInstance();
    }
}
有一个示例服务,它使用时间戳生成一些ID。它应该是独一无二的,所以我用的是Hazelcast提供的锁

@Service
public class MyService {
    @Autowired
    private HazelcastInstance hazelcastInstance;

    public Long generateVersion(){
        ILock lock = hazelcastInstance.getLock("version_key");
        try{
            lock.lock();
            return System.currentTimeMillis();
        } catch (Exception ex) {
            LOGGER.error("Could not generate version ", ex);
            throw ex;
        } finally{
            lock.unlock();
        }
    }
}
测试检查是否没有生成重复项

@Test
public void test() throws InterruptedException, ExecutionException {
    List<Long> versions = new ArrayList();
    Collection<Callable<Long>> tasks = new ArrayList<>();
    int nThreads = 100;
    for(int i=0; i<nThreads; i++){
        tasks.add(new Callable<Long>() {
            @Override
            public Long call() throws Exception {
                return myService.generateVersion();
            }
        });
    }
    ExecutorService executor = Executors.newFixedThreadPool(nThreads);
    List<Future<Long>> results = executor.invokeAll(tasks);
    for(Future<Long> result : results){
        Long pingResult = result.get();
        if (!versions.contains(pingResult))
            versions.add(pingResult);
        else
            throw new AssertionError("Found duplicate "+ pingResult);
    }
}
@测试
public void test()引发InterruptedException,ExecutionException{
列表版本=新的ArrayList();
收集任务=新建ArrayList();
int=100;
for(int i=0;i
System.getTimestamp()
可能不是唯一的。您可以调用它两次并得到相同的结果


你可以让Hazelcast为你生成id

为什么getTimestamp不是唯一的,如果它是由锁控制的?这是否意味着锁定/解锁Hazelcast过程需要不到1msc?我认为锁定/解锁过程需要足够的时间。@Ermintar对本地Hazelcast实例的更改会非常快。另外,System.currentTimeMillis()可以是粗粒度的(以我的经验,10ms是很常见的)。这意味着在两个刻度之间,您将检索相同的时间戳