Java错误，构造函数Mobile无法应用于给定类型；这是什么意思？

更新的代码，错误表明内部类Mobile.mymobile修饰符中的static declaration非法，仅在常量变量declaration中允许static，第75行，public static void main（String[]args）{，这是什么意思

我的代码：

   /**
 * to write a simple java class Mobile that models a mobile phone.
 * 
 * @author (jamal) 
 * @version (14/10/13)
 */
public class Mobile

{
    // type of phone
    private String phonetype;
    // size of screen in inches
    private int screensize;
    // menory card capacity
    private int  memorycardcapacity;
    // name of present service provider
    private String serviceprovider;
    // type of contract with service provider
    private int typeofcontract;
    // camera resolution in megapixels
    private int cameraresolution;
    // the percentage of charge left on the phone
    private int checkcharge;
    // wether the phone has GPS or not
    private String GPS;
    // instance variables - replace the example below with your own
    private int x;

    // The constructor method

    public Mobile(String mobilephonetype, int mobilescreensize,
            int mobilememorycardcapacity,int mobilecameraresolution,String mobileGPS, String newserviceprovider) {
        this.phonetype =  mobilephonetype;
        this.screensize = mobilescreensize;
        this.memorycardcapacity = mobilememorycardcapacity;
        this.cameraresolution = mobilecameraresolution;
        this.GPS = mobileGPS;

        // you do not use this ones during instantiation,you can remove them if you do not need or assign them some  default values 
        //this.serviceprovider = newserviceprovider;
        //this.typeofcontract = 12;
        //this.checkcharge = checkcharge;

   Mobile samsungPhone = new Mobile(
    "Samsung" // String mobilephonetype
,   1024    // int mobilescreensize 
,   2      // int mobilememorycardcapacity 
,   8       // int mobilecameraresolution 
,   "GPS"    //String mobileGPS
,   "verizon" // String newserviceprovider 
);


        //typeofcontract = 12;
        //checkcharge = checkcharge;

    }

    // A method to display the state of the object to the screen
    public void displayMobileDetails() {
        System.out.println("phonetype: " + phonetype);
        System.out.println("screensize: " + screensize);
        System.out.println("memorycardcapacity: " + memorycardcapacity);
        System.out.println("cameraresolution: " + cameraresolution);
        System.out.println("GPS: " + GPS);
         System.out.println("serviceprovider: " + serviceprovider);
        System.out.println("typeofcontract: " + typeofcontract);
}

      /**
 * The mymobile class implements an application that
 * simply displays "new Mobile!" to the standard output.
 */
public class mymobile {
    public static void main(String[] args) {
        System.out.println("new Mobile!"); //Display the string.
    }
}
    public static void buildPhones(){
    Mobile Samsung = new Mobile("Samsung", 3, 4, 8, "verizon",
                "GPS");
Mobile Blackberry = new Mobile("Blackberry", 3, 4,
                8, "verizon", "GPS");
        Samsung.displayMobileDetails();
        Blackberry.displayMobileDetails();
}
    public static void main(String[] args) {
        buildPhones();
}  

}

任何答案或答复和帮助将不胜感激，因为我完全迷路了

构造函数不能应用于给定类型

意味着您试图使用错误的参数调用构造函数

必需：java.lang.String，int，int，int，java.lang.String，java.lang.String

意味着构造函数需要这些类型作为传递给它的参数

找到：java.lang.String，java.lang.String，java.lang.String，java.lang.String，java.lang.String，java.lang.String

是你真正传递给它的东西

---

您正在传递五个

String

参数，而构造函数需要一个

String

、三个

int

s和两个

String

s。这就是为什么会出现错误

更新

正确的方法是：

Mobile Samsung = new Mobile("Samsung", 3, 4, 8, "verizon"
                "GPS");
Mobile Blackberry = new Mobile("Blackberry", 3, 4,
                8, "verizon", "GPS");

将参数更改为所需的参数

您的第一个构造函数调用也是错误的

Mobile samsungPhone = new Mobile(
    "Samsung" // String mobilephonetype
,   1024    // int mobilescreensize 
,   2      // int mobilememorycardcapacity 
,   8       // int mobilecameraresolution 
,   "verizon" // String newserviceprovider 

);

此处缺少一个参数，应为

Mobile samsungPhone = new Mobile(
    "Samsung" // String mobilephonetype
,   1024    // int mobilescreensize 
,   2      // int mobilememorycardcapacity 
,   8       // int mobilecameraresolution 
,   "GPS"    //String mobileGPS
,   "verizon" // String newserviceprovider 
);

---

您缺少构造函数String mobileGPS的第5个参数。

很抱歉，我如何传递一个字符串、三个int和两个字符串？？？@user2898828查看我的更新。它可以工作，但您必须根据需要更改参数值更新的代码，错误显示内部类Mobile.mymobile修饰符的static是非法的static declaration只允许在常量变量decellerations中，第75行，publicstaticvoidmain（String[]args）{，这意味着什么？这个问题已经回答了，但让我给你一个建议-为了防止这种情况，不要创建具有4个以上参数的方法（构造函数）。而不要使用或使用getter/setter。

Mobile samsungPhone = new Mobile(
    "Samsung" // String mobilephonetype
,   1024    // int mobilescreensize 
,   2      // int mobilememorycardcapacity 
,   8       // int mobilecameraresolution 
,   "GPS"    //String mobileGPS
,   "verizon" // String newserviceprovider 
);