如何在java中使用twitter4j发布tweet?
我可以使用twitter4j登录twitter,并获取有关已登录用户的信息,但我无法从我的应用程序发布twitter。我正在使用java web应用程序发布tweet。请参阅下面我使用的代码如何在java中使用twitter4j发布tweet?,java,twitter4j,Java,Twitter4j,我可以使用twitter4j登录twitter,并获取有关已登录用户的信息,但我无法从我的应用程序发布twitter。我正在使用java web应用程序发布tweet。请参阅下面我使用的代码 String ACCESS_TOKEN = "ttttttttt"; String ACCESS_TOKEN_SECRET = "gggggggggggggg"; String CONSUMER_KEY = "gggggggggggg"; String CONSUMER_SECRET
String ACCESS_TOKEN = "ttttttttt";
String ACCESS_TOKEN_SECRET = "gggggggggggggg";
String CONSUMER_KEY = "gggggggggggg";
String CONSUMER_SECRET = "hhhhhhhhhhhhh";
String tweet = "";
if (request.getParameter("tweet") != null) {
tweet = request.getParameter("tweet");
}
AccessToken accessToken = new AccessToken(ACCESS_TOKEN, ACCESS_TOKEN_SECRET);
OAuthAuthorization authorization = new OAuthAuthorization(ConfigurationContext.getInstance(), CONSUMER_KEY, CONSUMER_SECRET, accessToken);
Twitter twitter = new TwitterFactory().getInstance(authorization);
try {
//twitter.updateStatus("Hello World!");
twitter.updateStatus(tweet);
} catch (TwitterException e) {
System.err.println("Error occurred while updating the status!");
}
我得到以下例外情况:
TwitterException{exceptionCode=[fa54b184-3bf2623f],状态代码=401,retryAfter=0,rateLimitStatus=null,版本=2.1.5-快照(内部版本:D372A51B49B419CBD73D416474F4A855F3E889507)}
请帮助。状态代码401表示您
检查您的凭据是否有效。如果是,则可能您的应用程序未经用户验证。请参阅(第7点)上的示例。首先,重新生成您的访问令牌/密码和消费者密钥/密码。 那就试试这个
String consumerKey = "yourconsumerKey ";
String consumerSecret = "yourconsumerSecret";
String accessToken = "yourAccessToken";
String accessSecret = "yourAccessSecret";
ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true)
.setOAuthConsumerKey(consumerKey)
.setOAuthConsumerSecret(consumerSecret)
.setOAuthAccessToken(accessToken)
.setOAuthAccessTokenSecret(accessSecret);
try
{
TwitterFactory factory = new TwitterFactory(cb.build());
Twitter twitter = factory.getInstance();
System.out.println(twitter.getScreenName());
Status status = twitter.updateStatus(latestStatus);
System.out.println("Successfully updated the status to [" + status.getText() + "].");
}catch (TwitterException te) {
te.printStackTrace();
System.exit(-1);
}