Java 在运行完方法并检索'；返回'；？理解困难'；getter'；

我现在拥有的：我目前有一个公共类“MainMenu”，在这里我向用户打招呼，并要求他们输入一组数字（1-10）以获得他们想要执行的选项。这是由开关箱拾取的

在每个案例中，要么运行一个小的执行，要么指向一个单独的类

例如：

    public static void mainMenu(Scanner sc) {
    //Scanner sc = new Scanner(System.in);
    System.out.println("Welcome to the Flight Scheduler!\n");
    System.out.println("Please remember to always use U, M, T, W, R, F, S, for entering");
    System.out.println("the day of the week, and to always use military time");
    System.out.println("for entering the time.");
    System.out.println("Please make your choice\nby entering the corresponding menu number:\n");

    System.out.println("1.\tSet Clock");
    System.out.println("2.\tClear Schedule");
    System.out.println("3.\tAdd Airline");
    System.out.println("4.\tAdd Flight");
    System.out.println("5.\tCancel Flight");
    System.out.println("6.\tShow Flight Info");
    System.out.println("7.\tShow Departures");
    System.out.println("8.\tShow Arrivals");
    System.out.println("9.\tFind Flights Between Two Airports");
    System.out.println("10.\tExit\n");

    int userChoice = sc.nextInt();

    switch (userChoice) {
      case 1:
      AirlineAircraftData.AddAirline(sc);
      break;

这将执行我的AddAirline方法，我希望将一个对象返回主菜单，并允许用户在输入AddAirline方法请求的字段后，继续从前面提供的10个选项中进行选择

以下是用户选择后我正在运行的方法：

    public static A8AirlineAircraftData AddAirline(Scanner sc) {
    sc.nextLine();
    System.out.println("Please enter the Airline name:");
    String airName = sc.nextLine();

    System.out.println("Please enter the Airline code:");
    String airCode = sc.nextLine();
    System.out.println("Please enter the Delta Aircraft:");
    String airCraft = sc.nextLine();
    System.out.println("Please enter the first class seat capacity:");
    int firstClass = sc.nextInt();
    System.out.println("Please enter the business class seat capacity:");
    int busiClass = sc.nextInt();
    System.out.println("Please enter the economy class seat capacity:");
    int econClass = sc.nextInt();
    System.out.println("Airline name: " + airName);
    System.out.println("Airline code: " + airCode);
    System.out.println("Delta Aircraft: " + airCraft);
    //Splitting the first word from the rest of the string
    String arr[] = airCraft.split(" ", 2);
    String firstWord = arr[0];
    System.out.println(firstWord + " first class seat capacity: " + firstClass);
    System.out.println(firstWord + " business class seat capacity: " + busiClass);
    System.out.println(firstWord + " economy class seat capacity: " + econClass);
    //Airline object
    A8AirlineAircraftData airline = new A8AirlineAircraftData(airName, airCode, airCraft, firstClass, busiClass, econClass);
    System.out.println(airName + " successfully added. Press Enter to continue.");
    sc.nextLine();//Press Enter to continue
    sc.nextLine();   
    //A8MainMenu.mainMenu(sc); //return to main menu after Enter. 
    return airline;

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谢谢你的帮助，我是个新手，我知道我做的很多事情都不一定有意义

因为@dm，我能够想出如何解决这个问题。我只是将整个主菜单包装在一个do-while循环中，该循环在'10'上退出

通常你会在一个循环中运行主菜单，当用户选择退出时退出循环；这条线是不能接受的。为什么会这样？这不是一个好的做法，因为它会把更多的东西放在堆栈上。如果您这样做了，并且用户浏览菜单的次数足够多，最终您会得到一个

stackoverflowerrror

。