Java 如何通过验证API验证某些输入参数?
我有一个API,在其中我自己对某些输入参数进行验证。例如—Java 如何通过验证API验证某些输入参数?,java,validation,apache-commons,Java,Validation,Apache Commons,我有一个API,在其中我自己对某些输入参数进行验证。例如— public Builder(int clientId) { TestUtils.assertNonNegative(clientId, "ClientId"); this.clientId = clientId; } public Builder setUserId(String userid) { TestUtils.assertNotNull(userid,
public Builder(int clientId) {
TestUtils.assertNonNegative(clientId, "ClientId");
this.clientId = clientId;
}
public Builder setUserId(String userid) {
TestUtils.assertNotNull(userid, "UserId");
this.userid = userid;
return this;
}
在TestUtils
类中,我的assertNonNegative
和assertNotNull
方法如下-
public static void assertNonNegative(int val, String attr) {
if (val <= 0) {
s_logger.logError("Attribute = ", attr, " Value = ", val, " error=", attr, " cannot be negative or zero");
throw new IllegalArgumentException(attr + " cannot be negative or zero");
}
}
public static void assertNotNull(String value, String key) {
if (value == null || value.isEmpty()) {
s_logger.logError("Key = ", key, " Value = ", value, " error=", key,
" cannot be NULL or empty String");
throw new IllegalArgumentException(key + " cannot be null OR empty");
}
}
publicstaticvoidassertnonnegative(int-val,stringattr){
如果(val我不明白为什么要使用外部API实现空空或非负数验证,但是
如果您想直接在Java应用程序中验证数据库中用户的id
这可能会让您感兴趣:
使用一点PHP并验证用户是否在数据库中
if(isset($_GET['idcmd']))
{
switch($_GET['idcmd'])
{
case 1:
if(isset($_POST['iduser']))
{
$sql= "SELECT idUser FROM users WHERE idUser=:iduser ";
$result = $db_conn->prepare($sql);
$result->bindParam(":iduser" ,$_POST['iduser']);
$result->execute();
$num=$result->fetchColumn();
if($num > 0){
echo "cool";
}else{
echo "nocool";
}
}
break;
}
}
现在,如果您向url www.mydomain.com/myapi.php?idcmd=1发出POST请求,并得到很酷的响应,则表示用户在数据库中
if(isset($_GET['idcmd']))
{
switch($_GET['idcmd'])
{
case 1:
if(isset($_POST['iduser']))
{
$sql= "SELECT idUser FROM users WHERE idUser=:iduser ";
$result = $db_conn->prepare($sql);
$result->bindParam(":iduser" ,$_POST['iduser']);
$result->execute();
$num=$result->fetchColumn();
if($num > 0){
echo "cool";
}else{
echo "nocool";
}
}
break;
}
}
我希望有帮助