Java Android访问远程mysql数据库
我一直在尝试使用多个示例,通过android应用程序访问远程服务器(digitalocean)。目前,我在解析URL中的数据时遇到了一个错误,我不能100%确定原因。你能帮我一下吗,代码在下面 java代码:Java Android访问远程mysql数据库,java,php,android,mysql,Java,Php,Android,Mysql,我一直在尝试使用多个示例,通过android应用程序访问远程服务器(digitalocean)。目前,我在解析URL中的数据时遇到了一个错误,我不能100%确定原因。你能帮我一下吗,代码在下面 java代码: public class MainActivity extends Activity { TextView txt1,txt2,txt3; public void onCreate(Bundle savedInstanceState) { super.onCreate(saved
public class MainActivity extends Activity {
TextView txt1,txt2,txt3;
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
new task().execute();
}
class task extends AsyncTask<String, String, Void>
{
private ProgressDialog progressDialog = new ProgressDialog(MainActivity.this);
InputStream is = null ;
String result = "";
protected void onPreExecute() {
progressDialog.setMessage("Fetching data...");
progressDialog.show();
progressDialog.setOnCancelListener(new OnCancelListener() {
@Override
public void onCancel(DialogInterface arg0) {
task.this.cancel(true);
}
});
}
@Override
protected Void doInBackground(String... params) {
String url_select = "http://server1.chris.waszczuk/webservice/select.php";
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url_select);
ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();
try {
httpPost.setEntity(new UrlEncodedFormEntity(param));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
//read content
is = httpEntity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection "+e.toString());
}
try {
BufferedReader br = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = "";
while((line=br.readLine())!=null)
{
sb.append(line+"\n");
}
is.close();
result=sb.toString();
} catch (Exception e) {
// TODO: handle exception
Log.e("log_tag", "Error converting result "+e.toString());
}
return null;
}
protected void onPostExecute(Void v) {
// ambil data dari Json database
try {
JSONArray Jarray = new JSONArray(result);
for(int i=0;i<Jarray.length();i++)
{
JSONObject Jasonobject = null;
txt1 = (TextView)findViewById(R.id.txt1);
txt2 = (TextView)findViewById(R.id.txt2);
txt3 = (TextView)findViewById(R.id.txt3);
Jasonobject = Jarray.getJSONObject(i);
//get an output on the screen
String no = Jasonobject.getString("no// this should be same in the table field name");
String name = Jasonobject.getString("name");
String birthday = Jasonobject.getString("birthday");
txt1.setText(no);
txt2.setText(name);
txt3.setText(birthday);
}
this.progressDialog.dismiss();
} catch (Exception e) {
// TODO: handle exception
Log.e("log_tag", "Error parsing data "+e.toString());
}
}
}
}
更新:将登录url更改为服务器的IP地址后,会出现新的解析错误
新网址:
String url_select = "http://95.85.22.140/webservice/select.php";
错误:
04-01 14:19:26.206: E/log_tag(1037): Error parsing data org.json.JSONException: Value <!DOCTYPE of type java.lang.String cannot be converted to JSONArray
04-01 14:19:26.206:E/log_标记(1037):解析数据org.json.JSONException:Value正如我在评论中建议的那样,字符串url_select=”http://server1.chris.waszczuk/webservice/select.php";代码>是错误的。基本上,除非你有一个自己的DNS服务器并且你的所有流量都通过它,server1.chris.waszczuk
是一个不好的DNS名称
如果您在本地网络中运行此功能,我建议您使用服务器的专用IP地址。这样,您的URL将包含以下内容:
http://192.168.1.X/webservice/select.php
如果您将其作为远程服务器运行,请改用有效的DNS。String url\u select=”http://server1.chris.waszczuk/webservice/select.php";代码>您确定这确实解析为有效的URL吗?顺便说一句,您应该更新问题,并准确说明错误所在。您确定DigitalOcean托管DMZ之外的Web服务器可用吗。这可能是您的问题,因为它无法在防火墙后解决。有关您遇到的新错误,请查看以下内容:
String url_select = "http://95.85.22.140/webservice/select.php";
04-01 14:19:26.206: E/log_tag(1037): Error parsing data org.json.JSONException: Value <!DOCTYPE of type java.lang.String cannot be converted to JSONArray
http://192.168.1.X/webservice/select.php