Java make if只检查一个命令

我有一个ViewFlipper和一个next按钮，我希望在检查并执行一个命令后该按钮停止 我希望它停止检查其余部分，除非我再次单击它

我的代码：

    Next.setOnClickListener(new View.OnClickListener() {
            ViewFlipper flipp = (ViewFlipper) findViewById(R.id.flipp);
        @Override
        public void onClick(View view) {

            if(flipp.getDisplayedChild() == 0){if(qOne.isChecked()) {CorrectToast();}else{WrongToast();}} 
            if(flipp.getDisplayedChild() == 1){if(qTwo.isChecked()){CorrectToast();}else{WrongToast();}}
            if(flipp.getDisplayedChild() == 2){if(qThree.isChecked()){CorrectToast();}else{WrongToast();}}
            if(flipp.getDisplayedChild() == 3){if(qFour.isChecked()){CorrectToast();}else{WrongToast();}}
        }
    });

使用

if（）else if（）

construct

使用

if（）else if（）

construct

您可以像这样使用

if（）{}else if（）{}

语句

    Next.setOnClickListener(new View.OnClickListener() {
            ViewFlipper flipp = (ViewFlipper) findViewById(R.id.flipp);
        @Override
        public void onClick(View view) {

            if(flipp.getDisplayedChild() == 0){if(qOne.isChecked()) {CorrectToast();}else{WrongToast();}} 
            else if(flipp.getDisplayedChild() == 1){if(qTwo.isChecked()){CorrectToast();}else{WrongToast();}}
            else if(flipp.getDisplayedChild() == 2){if(qThree.isChecked()){CorrectToast();}else{WrongToast();}}
            else if(flipp.getDisplayedChild() == 3){if(qFour.isChecked()){CorrectToast();}else{WrongToast();}}
        }
    });

您可以像这样使用

if（）{}else if（）{}

语句

    Next.setOnClickListener(new View.OnClickListener() {
            ViewFlipper flipp = (ViewFlipper) findViewById(R.id.flipp);
        @Override
        public void onClick(View view) {

            if(flipp.getDisplayedChild() == 0){if(qOne.isChecked()) {CorrectToast();}else{WrongToast();}} 
            else if(flipp.getDisplayedChild() == 1){if(qTwo.isChecked()){CorrectToast();}else{WrongToast();}}
            else if(flipp.getDisplayedChild() == 2){if(qThree.isChecked()){CorrectToast();}else{WrongToast();}}
            else if(flipp.getDisplayedChild() == 3){if(qFour.isChecked()){CorrectToast();}else{WrongToast();}}
        }
    });

---

请改用switch语句：

Next.setOnClickListener(new View.OnClickListener() {
        ViewFlipper flipp = (ViewFlipper) findViewById(R.id.flipp);
    @Override
    public void onClick(View view) {
        switch(flipp.getDisplayedChild()) {
            case 0: if(qOne.isChecked()) {CorrectToast();}else{WrongToast();} break; 
            case 1: if(qTwo.isChecked()) {CorrectToast();}else{WrongToast();} break;
            case 2: if(qThree.isChecked()) {CorrectToast();}else{WrongToast();} break;
            case 3: if(qFour.isChecked()) {CorrectToast();}else{WrongToast();} break;
            default: break; //do default action,
        }
    }  

---

请改用switch语句：

Next.setOnClickListener(new View.OnClickListener() {
        ViewFlipper flipp = (ViewFlipper) findViewById(R.id.flipp);
    @Override
    public void onClick(View view) {
        switch(flipp.getDisplayedChild()) {
            case 0: if(qOne.isChecked()) {CorrectToast();}else{WrongToast();} break; 
            case 1: if(qTwo.isChecked()) {CorrectToast();}else{WrongToast();} break;
            case 2: if(qThree.isChecked()) {CorrectToast();}else{WrongToast();} break;
            case 3: if(qFour.isChecked()) {CorrectToast();}else{WrongToast();} break;
            default: break; //do default action,
        }
    }  

---

swith语句是可以的，但我建议这样做。它更具可读性，您可以添加对象，而不必太麻烦和混乱

public void onClick(View view) {
    CheckedObject[] objectsToCheck = new CheckedObject[]{qOne,qTwo,qThree,qFour};
    int index = flipp.getDisplayedChild();
    if (objectsToCheck[index].isChecked())
    {
         CorrectToast();
    }
    else 
    {
         WrongToast();
    }
}

---

swith语句是可以的，但我建议这样做。它更具可读性，您可以添加对象，而不必太麻烦和混乱

public void onClick(View view) {
    CheckedObject[] objectsToCheck = new CheckedObject[]{qOne,qTwo,qThree,qFour};
    int index = flipp.getDisplayedChild();
    if (objectsToCheck[index].isChecked())
    {
         CorrectToast();
    }
    else 
    {
         WrongToast();
    }
}

---

CheckedObject[]代表什么？Android Studio无法解决该问题。@user2989698您必须用正确类型的qOne、qTwo等替换CheckedObject。如果您使用的是JCheckBox，则JCheckBox[]。我不知道您使用的对象的类别。CheckedObject[]代表什么？Android Studio无法解决该问题。@user2989698您必须用正确类型的qOne、qTwo等替换CheckedObject。如果您使用的是JCheckBox，则JCheckBox[]。我不知道您使用的对象的类别。