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需要关于在Java中解析重复项的建议吗_Java_Arrays_Loops_Parsing_Java.util.scanner - Fatal编程技术网

需要关于在Java中解析重复项的建议吗

需要关于在Java中解析重复项的建议吗,java,arrays,loops,parsing,java.util.scanner,Java,Arrays,Loops,Parsing,Java.util.scanner,我有一个任务,要求我创建两个数组(具有用户定义的长度),其中满是1-100之间的随机数,然后以交替顺序合并两个数组,不重复。我只是需要帮助合并这两个没有任何重复的数字。有人能帮忙吗?谢谢 import java.util.Scanner; import java.lang.Math; class Main { public static void main(String[] args){ Scanner scan = new Scanner (System.in);

我有一个任务,要求我创建两个数组(具有用户定义的长度),其中满是1-100之间的随机数,然后以交替顺序合并两个数组,不重复。我只是需要帮助合并这两个没有任何重复的数字。有人能帮忙吗?谢谢

import java.util.Scanner;
import java.lang.Math; 

class Main {

  public static void main(String[] args){
      Scanner scan = new Scanner (System.in);
      int f=0;
      int j=0;
      int k=0;
      //getting first array length and making array1 and array2 that length
    while (f==0){
      System.out.println("Enter an array length (must be 10 or greater):");
    int length = scan.nextInt();
    if (length < 10){
      f=0;
    }
    else{
      f=1;
    }
    if (f==1){
      int [] array1 = new int[length];
      int [] array2 = new int[length];
      int [] array3 = new int[length*2];
      System.out.print("First Array: ");
    //creating random integers between 1 and 100 inclusive to fill array1
    for (int i=0; i<=length-1; i++){
      int x = (int)(Math.random()*100)+1;
      array1[i] = x;
      System.out.print(x+" ");
    }
    //creating random integers between 1 and 100 inclusive to fill array2
    System.out.print("\nSecond Array: ");
    for (int i=0; i<=length-1; i++){
      int y = (int)(Math.random()*100)+1;
      System.out.print(y+" ");
      array2[i] = y;
    }
    //combining both arrays
    System.out.print("\nMerged Array: ");
    for (int i=0; i<=length*2-1; i++){
      if ((i==0) || (i%2==0)){
            array3[i] = array1[j];
            j++;      
          }
      else{
        array3[i] = array2[k];
        k++;
      }
      System.out.print(array3[i]+" ");
    }
    }
    }
  }
}
import java.util.Scanner;
导入java.lang.Math;
班长{
公共静态void main(字符串[]args){
扫描仪扫描=新扫描仪(System.in);
int f=0;
int j=0;
int k=0;
//获取第一个数组长度并使array1和array2达到该长度
而(f==0){
System.out.println(“输入数组长度(必须大于等于10):”;
int length=scan.nextInt();
如果(长度<10){
f=0;
}
否则{
f=1;
}
如果(f==1){
int[]数组1=新的int[长度];
int[]array2=新的int[长度];
int[]数组3=新的int[长度*2];
System.out.print(“第一个数组:”);
//创建1到100(含)之间的随机整数以填充数组1

对于(inti=0;i首先,让我们提取方法来填充数组

static int[] fillRandomArray(int n) {
    int[] arr = new int[n];
    for (int i = 0; i < n; i++) {
        arr[i] = (int) (Math.random() * 100) + 1;
        System.out.print(arr[i] + " ");
    }
    System.out.println();
    return arr;
}
如果在合并时确实需要消除array1和array2之间的重复项,则不能假设输出数组的长度将是输入长度的两倍。我将使用
。例如

// combining both arrays
System.out.print("\nMerged Array: ");
Set<Integer> set = new LinkedHashSet<>();
for (int i = 0; i < array1.length + array2.length; i++) {
    if (i % 2 == 0) {
        if (set.add(array1[i / 2])) {
            System.out.print(array1[i / 2] + " ");
        }
    } else {
        if (set.add(array2[i / 2])) {
            System.out.print(array2[i] + " ");
        }
    }
}
// If you actually need an int[]
int[] array3 = set.stream().mapToInt(Integer::intValue).toArray();
//组合两个数组
System.out.print(“\n合并数组:”);
Set Set=newlinkedhashset();
for(int i=0;i
不要这样删除你的代码,你留下的部分孤立地没有用;如果你能在不删除所有内容的情况下使其更简洁,请随意编辑。对不起,我是新来的!对于某人来说,似乎很难理解他们脸上所有的代码是怎么回事。这回答了你的问题吗?这有点帮助,但也太难了对我来说很复杂;有很多符号我不熟悉。因为我是一个初学者,我需要用for循环最低限度地完成这项工作,但我不太确定如何完成。谢谢你的回答!很难相信互联网上随机出现的人能比我的导师提供更好的答案…lolIt看起来这本书中仍然有重复的内容代码也是。这是合并array1和array2,如果要消除重复,那么输出数组的长度将不总是相同。请稍候。此行出现语法错误:Set Set Set=new LinkedHashSet();
import java.util.Set;
import java.util.LinkedHashSet;
// combining both arrays
System.out.print("\nMerged Array: ");
Set<Integer> set = new LinkedHashSet<>();
for (int i = 0; i < array1.length + array2.length; i++) {
    if (i % 2 == 0) {
        if (set.add(array1[i / 2])) {
            System.out.print(array1[i / 2] + " ");
        }
    } else {
        if (set.add(array2[i / 2])) {
            System.out.print(array2[i] + " ");
        }
    }
}
// If you actually need an int[]
int[] array3 = set.stream().mapToInt(Integer::intValue).toArray();