Java Android:HttpPost不工作

Hi guy为我的英语错误感到抱歉：p我有一个问题，我正试图将一个变量id_art发布到php页面，问题是我无法理解变量是否发送不正确，或者我是否在php端错误地读取了它

JAVA代码：

 HttpClient httpclient = new DefaultHttpClient();
 HttpPost httpPost = new HttpPost(myurl);
 StringBuilder builder = new StringBuilder();
 String json, result = "";

//Build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("id_articolo", id_art);
//Convert JSONObject to JSON to String
json = jsonObject.toString();
//Set json to StringEntity
StringEntity se = new StringEntity(json);
//Set httpPost Entity
httpPost.setEntity(se);
//Set some headers to inform server about the type of the content   
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
//Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
//Receive response as inputStream
StatusLine statusLine = httpResponse.getStatusLine();
int statusCode = statusLine.getStatusCode();
//Convert input stream to string
if (statusCode == 200){     
   HttpEntity entity = httpResponse.getEntity();
   InputStream content = entity.getContent();
   BufferedReader reader = new BufferedReader(new InputStreamReader(content));
   String line="";

   while ((line = reader.readLine()) != null) {
      builder.append(line);
      result = builder.toString();
   }
     System.out.println("DEBUG"+" "+result);

PHP代码

<?php
include_once('configurazione.php');
header("Content-Type: application/json");
mysql_set_charset('utf8');

$value = json_decode(stripslashes($_POST),true);
var_dump($value);
?>

结果为空。。。为什么

TNKs4帮助

编辑1

---

我试图编辑我的php代码

这是：json\u decodeStripsalshes$\u POST，true

使用：$value=json\u decode$\u POST

但结果是一样的。。空的

编辑2 我试着替换

in.JAVA

httpPost.setEntity(new StringEntity(yourJson.toString(),"UTF-8"));

httpPost.setEntitynew StringEntityyourJson.toString，UTF-8

in.PHP $value=json\u decodefile\u get\u contents'php://input'; echo美元价值

但在.JAVA中，结果是空的

httpPost.setEntity(new StringEntity(yourJson.toString(),"UTF-8"));

in.PHP

$value = file_get_contents('php://input');
var_dump(json_decode($value , true));

$value = $_POST['json'];
var_dump(json_decode($value , true));

试试这个 in.JAVA

---

我相信您不能简单地发送StringEntity，因为POST参数应该是key=>value对。这意味着您需要为参数命名，比如json

然后你可以这样做：

JSONObject jsonObject = new JSONObject();
// here you can set up the data

HttpPost httppost = new HttpPost(URL);
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("json", jsonObject.toString()));
// here you can add more POST data using nameValuePairs.add()

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);

---

$\u POST是数组，这就是原因。stripslashes用于stringphpinfo，当您需要知道服务器正在接收什么时，它是您的朋友。这太过分了，但是它会告诉你你的JSON是否会被发送到哪里；使用：$value=json\u decode$\u POST；但结果是一样的。。我的第一个答案有效？我尝试了所有答案，但没有人有效。。。我不明白怎么了！

$value = json_decode($_POST['json'], true);
var_dump($value);