Java 我可以使用Gson序列化方法本地类和匿名类吗?
例如:Java 我可以使用Gson序列化方法本地类和匿名类吗?,java,gson,Java,Gson,例如: import com.google.gson.Gson; class GsonDemo { private static class Static {String key = "static";} private class NotStatic {String key = "not static";} void testGson() { Gson gson = new Gson(); System.out.println(g
import com.google.gson.Gson;
class GsonDemo {
private static class Static {String key = "static";}
private class NotStatic {String key = "not static";}
void testGson() {
Gson gson = new Gson();
System.out.println(gson.toJson(new Static()));
// expected = actual: {"key":"static"}
System.out.println(gson.toJson(new NotStatic()));
// expected = actual: {"key":"not static"}
class MethodLocal {String key = "method local";}
System.out.println(gson.toJson(new MethodLocal()));
// expected: {"key":"method local"}
// actual: null (be aware: the String "null")
Object extendsObject = new Object() {String key = "extends Object";};
System.out.println(gson.toJson(extendsObject));
// expected: {"key":"extends Object"}
// actual: null (be aware: the String "null")
}
public static void main(String... arguments) {
new GsonDemo().testGson();
}
}
我喜欢这些序列化,尤其是在单元测试中。有没有办法做到这一点?
我发现了,但是这个论证只对反序列化有效。FWIW,将匿名类和本地类序列化就可以了
public static void main(String[] args) throws Exception
{
ObjectMapper mapper = new ObjectMapper();
class MethodLocal {public String key = "method local";}
System.out.println(mapper.writeValueAsString(new MethodLocal()));
// {"key":"method local"}
Object extendsObject = new Object() {public String key = "extends Object";};
System.out.println(mapper.writeValueAsString(extendsObject));
// {"key":"extends Object"}
}
请注意,默认情况下Jackson不会像Gson那样通过反射访问非公共字段,但可以将其配置为这样做。Jackson的方法是使用常规Java属性(通过get/set方法)。(将其配置为使用私有字段确实会稍微降低运行时性能,但仍然比Gson快得多。)简短回答:不。嗨,Brian,我说的对吗,解释您的评论和链接线程,因为gson#序列化和gson#反序列化应该对称,所以现在和将来都不可能序列化本地类和匿名类?很有趣,因为序列化和反序列化几乎是不对称的