Java 将数组从Jquery发送到Struts1方法_Java_Jquery_Ajax_Json_Org.json

Java 将数组从Jquery发送到Struts1方法

java jquery ajax json

Java 将数组从Jquery发送到Struts1方法,java,jquery,ajax,json,org.json,Java,Jquery,Ajax,Json,Org.json,我的jsp和jquery代码如下 var article = new Object(); article.title = "abc"; article.url = "abc"; article.categories = [1,2,3]; article.tags = [1,2,3]; console.log('hi'); $.ajax({ type: 'POST', url: URL, conten

我的jsp和jquery代码如下

var article = new Object();
    article.title = "abc";
    article.url = "abc";
    article.categories = [1,2,3];
    article.tags = [1,2,3];


    console.log('hi');
    $.ajax({
        type: 'POST',
        url: URL,
       contentType:"application/json",
        data:  JSON.stringify(article),
        dataType: 'json',
        success: function(result) {
            console.log(result);

        },
        error: function(e){
            alert('Error in Processing');
        }

    });

我的java代码是

 BufferedReader br = new BufferedReader(new InputStreamReader(request.getInputStream()));
                String json = "";
                if(br != null){
                    json = br.readLine();
                }



                // 2. initiate jackson mapper
                ObjectMapper mapper = new ObjectMapper();
                //mapper.configure(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY, true);

                // 3. Convert received JSON to Article
                Article article = mapper.readValue(json, Article.class);

现在我的课堂是

public class Article {

    private String title;
    private String url;
    private List<String> categories;
    private List<String> tags;

//getters and setters
}

我得到的json如下

{"title":"abc","url":"abc","categories":"[1, 2, 3]","tags":"[1, 2, 3]"}

事实上应该是这样的

{"title":"abc","url":"abc","categories":[1, 2, 3],"tags":[1, 2, 3]}

我不明白发生了什么事因此我得到了一个例外 com.fasterxml.jackson.databind.JsonMappingException:无法反序列化java.util.ArrayList的实例超出值\u字符串标记在[来源：java.io。StringReader@f94ca；行：1，列：27]（通过引用链：com.ihexa.common.admin.cabsharing.action.Article[“categories”]）

我用下面的方法解出了答案

Article user=mapper.readValue（点，Article.class）

System.out.println（user.getRouteFirst（））

Gson Gson=新的Gson（）

TypeToken>token=新的TypeToken>（）{}； List personList=gson.fromJson（user.getRouteFirst（），token.getType（））

文章类别为

公共类文章{

private String routeFirst;
private String routeSecond;

//二传手和接球手

}

jspjQuery代码

我的

jsp

将

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"  "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Calculator</title>
</head>
<script
    src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">
</script>
<script type="text/javascript">


$( document ).ready(function() {
    //alert("DOM is ready");
});


function sendJsonData() {

    var article = new Object();
    article.title = "abc";
    article.url = "abc";
    article.categories = [1,2,3];
    article.tags = [1,2,3];

    //alert("JSON string :"+ JSON.stringify(article));

    $.ajax({
        type: 'POST',
        url: "JsonServlet",
        //contentType:"application/json",
        //data:  {point:point},
        data : "point="+encodeURIComponent(JSON.stringify(article)),
        dataType: 'json',
        success: function(result) {

        },
        error: function(e){
        //alert('Error in Processing');
        }

    });
}


</script>

<body>

    <button id="jsonButton" onclick="sendJsonData()">send jdon Data</button>

</body>
</html>

public class JsonServlet extends HttpServlet {

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {


        String point = request.getParameter("point");
        System.out.println("Point : " + point );

        if(point != null){

            ObjectMapper mapper = new ObjectMapper();

            try {
                // read from string, convert it to Article class object
                Article user = mapper.readValue(point, Article.class);

                // Conver the Article class object in to the JSON string
                System.out.println("Output Json String is :::::::::::> "+mapper.writeValueAsString(user));


            } catch (Exception e) {  
                e.printStackTrace();     
            } 
        }           
    }
}

这是我在控制台中得到的

输出

Point : {"title":"abc","url":"abc","categories":[1,2,3],"tags":[1,2,3]}
Json String is :::::::::::> {"title":"abc","url":"abc","categories":["1","2","3"],"tags":["1","2","3"]}

希望这有帮助。

您能提供您的运行代码吗？我已经尝试过了，但我使用的是struts1和jsp框架将myJsonData设置为null。我将此作为输出点：{“title”：“abc”，“url”：“efg”，“categories”：“[1,2,3]”，“tags”：“[4,5,6]”}com.fasterxml.jackson.databind.JsonMappingException:无法反序列化java.util.ArrayList的实例，使其超出[Source:java.io]处的字符串标记的值。StringReader@1a37192；行：1，列：27]（通过参考链：com.ihexa.common.admin.cabsharing.action.Article[“categories”]）在servlet和jsp中使用代码时，它的工作方式与您使用动态web应用程序作为输出给我的文件类似，但您的问题是

仅将数组从Jquery发送到servlet

。因此，您必须关闭此线程并创建一个新线程。如果您觉得我的

答案

很有用，您可以接受答案。我根据您的要求。请检查一下并告诉我。

public class JsonServlet extends HttpServlet {

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {


        String point = request.getParameter("point");
        System.out.println("Point : " + point );

        if(point != null){

            ObjectMapper mapper = new ObjectMapper();

            try {
                // read from string, convert it to Article class object
                Article user = mapper.readValue(point, Article.class);

                // Conver the Article class object in to the JSON string
                System.out.println("Output Json String is :::::::::::> "+mapper.writeValueAsString(user));


            } catch (Exception e) {  
                e.printStackTrace();     
            } 
        }           
    }
}

Point : {"title":"abc","url":"abc","categories":[1,2,3],"tags":[1,2,3]}
Json String is :::::::::::> {"title":"abc","url":"abc","categories":["1","2","3"],"tags":["1","2","3"]}