Java 从通讯簿中检索家庭联系人号码
目前我有一个应用程序,它将检索所有联系人 详细信息和将显示所有可用的联系人姓名。但现在我想检索家庭和工作号码。我在任何地方都搜索了这些号码,但我找不到。怎么可能 我能做到这一点吗?请帮帮我 谢谢 我用这个密码得到了家庭号码Java 从通讯簿中检索家庭联系人号码,java,android,Java,Android,目前我有一个应用程序,它将检索所有联系人 详细信息和将显示所有可用的联系人姓名。但现在我想检索家庭和工作号码。我在任何地方都搜索了这些号码,但我找不到。怎么可能 我能做到这一点吗?请帮帮我 谢谢 我用这个密码得到了家庭号码 Cursor c = getContentResolver().query(Data.CONTENT_URI, new String[] {Data._ID, Phone.NUMBER, Data.MIMETYPE},
Cursor c = getContentResolver().query(Data.CONTENT_URI,
new String[] {Data._ID, Phone.NUMBER, Data.MIMETYPE},
Data.RAW_CONTACT_ID + "=?" + " AND "
+ Data.MIMETYPE + "='" + Phone.TYPE_HOME + "'",
new String[] {String.valueOf(contactId)}, null);
但我需要的是使用单一查询获取家庭、工作、手机(带有姓名、电子邮件地址等)号码
使用此代码,它总是返回me type=0
Cursor c = getContentResolver().query(Data.CONTENT_URI,
null,
Data.CONTACT_ID + "=?",
new String[] {String.valueOf(contactId)}, null);
while(c.moveToNext()){
int type = c.getInt(c.getColumnIndex(Phone.TYPE));
..
}
在查询的where子句中使用
电话。键入\u HOME
。。这将为您提供所需的nor..确定最后我完成了任务。这里是我的代码
try this:
int type = mCursor.getInt(mCursor.getColumnIndex(Phone.TYPE));
the "type" value will be 1,2,3 or 4 where
TYPE_HOME = 1;
TYPE_MOBILE = 2;
TYPE_WORK = 3;
TYPE_OTHER = 7;
String mobile = "";
String home="";
String work="";
String fax="";
String other="";
String disName="";
String pName="";
String fName="";
String lName="";
String sName="";
String mName="";
String postBox="";
String streat="";
String country="";
String emailAdd="";
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null,null, null, null);
while (cur.moveToNext()) {
String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
disName = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
///*
Cursor phones = cr.query(Phone.CONTENT_URI, null,
Phone.CONTACT_ID + " = " + id, null, null);
while (phones.moveToNext()) {
String number = phones.getString(phones.getColumnIndex(Phone.NUMBER));
int type = phones.getInt(phones.getColumnIndex(Phone.TYPE));
System.out.println("Numeber= "+number);
switch (type) {
case Phone.TYPE_HOME:
home=number;
break;
case Phone.TYPE_MOBILE:
mobile=number;
break;
case Phone.TYPE_WORK:
work=number;
break;
case Phone.TYPE_OTHER:
other=number;
break;
case Phone.TYPE_FAX_HOME:
fax=number;
break;
case Phone.TYPE_FAX_WORK:
fax=number;
break;
}
}
phones.close();
Cursor name = cr.query(Data.CONTENT_URI, null,
Data.CONTACT_ID + " ="+id +" AND "+Data.MIMETYPE+"='"+StructuredName.CONTENT_ITEM_TYPE+"'", null, null);
while(name.moveToNext()){
sName=name.getString(name.getColumnIndex(StructuredName.PREFIX));
fName=name.getString(name.getColumnIndex(StructuredName.GIVEN_NAME));
mName=name.getString(name.getColumnIndex(StructuredName.MIDDLE_NAME));
lName=name.getString(name.getColumnIndex(StructuredName.FAMILY_NAME));
sName=name.getString(name.getColumnIndex(StructuredName.SUFFIX));
System.out.println(mName);
}
Cursor address = cr.query(Data.CONTENT_URI, null,
Data.CONTACT_ID + " ="+id +" AND "+Data.MIMETYPE+"='"+StructuredPostal.CONTENT_ITEM_TYPE+"'", null, null);
while(address.moveToNext()){
postBox=address.getString(address.getColumnIndex(StructuredPostal.POBOX));
streat=address.getString(address.getColumnIndex(StructuredPostal.STREET));
mName=address.getString(address.getColumnIndex(StructuredPostal.COUNTRY));
System.out.println(postBox);
}
Cursor email = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
Data.CONTACT_ID + " ="+id , null, null);
while(email.moveToNext()){
emailAdd=email.getString(email.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
}