Java 如何在android sdk中创建简单类?
我在Eclipse中借助android SDK创建了一个简单的android项目,我的代码是:Java 如何在android sdk中创建简单类?,java,android,eclipse,Java,Android,Eclipse,我在Eclipse中借助android SDK创建了一个简单的android项目,我的代码是: package com.example.deomanapp; import android.support.v7.app.ActionBarActivity; import android.support.v7.app.ActionBar; import android.support.v4.app.Fragment; import android.app.AlertDialog; import a
package com.example.deomanapp;
import android.support.v7.app.ActionBarActivity;
import android.support.v7.app.ActionBar;
import android.support.v4.app.Fragment;
import android.app.AlertDialog;
import android.content.Context;
import android.content.DialogInterface;
import android.location.Location;
import android.location.LocationManager;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.View.OnClickListener;
import android.view.ViewGroup;
import android.widget.Button;
import android.widget.TextView;
import android.widget.Toast;
import android.os.Build;
import android.provider.SyncStateContract.Helpers;
public class MainActivity extends ActionBarActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
if (savedInstanceState == null) {
getSupportFragmentManager().beginTransaction()
.add(R.id.container, new PlaceholderFragment())
.commit();
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
/**
* A placeholder fragment containing a simple view.
*/
public static class PlaceholderFragment extends Fragment {
public PlaceholderFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
final View rootView = inflater.inflate(R.layout.fragment_main, container, false);
Button b = (Button) rootView.findViewById(R.id.button1);
b.setOnClickListener(new OnClickListener() {
Mhelper mhelper = new Mhelper();
@Override
public void onClick(View v)
{
mhelper.mContext();
TextView tx = (TextView) rootView.findViewById(R.id.textView1);
tx.setText("Hi");
Toast.makeText(getActivity(), "ssss", Toast.LENGTH_SHORT).show();
}
});
return rootView;
}
}
}
我想在其他类中编写更多代码,因此我在项目中创建了helper类:
包com.example.deomanapp
import com.example.deomanapp.MainActivity.PlaceholderFragment;
import android.app.Activity;
import android.content.Context;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.widget.Toast;
public class Mhelper {
public void mContext(Context context)
{
LocationManager lm;
lm = (LocationManager)getSystemService(context.LOCATION_SERVICE);
Location location = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
double longitude = location.getLongitude();
double latitude = location.getLatitude();
}
}
我的问题是,我无法将上下文传递到类的任何部分或mhelper.mContext()中(它需要Contex参数)
我怎样才能把button onClick带到其他班级?或者我怎样才能使这个代码工作?我的新类是否应该从其他类扩展
编辑:
日志:
你能行
mhelper.mContext(getActivity());
然后
lm = (LocationManager)context.getSystemService(context.LOCATION_SERVICE);
它没有给我任何错误,但是程序在使用nullpointexeption单击按钮时崩溃。@Shombol shagol发布stacktrace。它将指示原因04-20 01:18:29.526:E/AndroidRuntime(1130):java.lang。NullPointerException@Shombol-shagol需要完整的stacktrace。my guess
getLastKnownLocation
返回空值。由你来纠正that@Shombol-shagolMhelper.java
中的第22行是什么?请遵循java惯例并以大写字母开头类名。小写字母表示变量名和方法名。我把它改为大写,但还是有同样的错误。@Shombol shagol崩溃不是因为这个。建议在命名类时遵循一些惯例。那是一件和这件事无关的事crash@Shombol-shagol在Mhelper.java
@Shombol shagol中,第22行是什么?您是否进行了此更改lm=(LocationManager)context.getSystemService(context.LOCATION\u SERVICE)代码>??。您仍然有lm=(LocationManager)getSystemService(context.LOCATION\u服务)代码>
lm = (LocationManager)context.getSystemService(context.LOCATION_SERVICE);
public final Activity getActivity ()
Added in API level 11
Return the Activity this fragment is currently associated with.