Java 每当我尝试执行API时，显示空响应的放心API

下面是代码片段，请给我一些帮助

@Test
public void VerifyCountries(){

//========================================================================================================================= //创建Gson生成器对象

    Gson gson = new GsonBuilder().create();
    Country[] country;

    String url = com.Tecksystem_demo_Utility.URL.FixUrl+EndPointURL.country.getResourcePath();

      response= Webservices.Get(url);

==================================================================== Webservices方法

public static Response Get(String uRI){
    RequestSpecification requestSpecification = RestAssured.given();
    requestSpecification.contentType(ContentType.JSON);
    Response response = requestSpecification.get(uRI);
    return response;
}

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下面是使用Gson和restassed库完成工作的代码片段。希望这对您所寻找的有帮助：

public class TestClass {

    public static void main(String[] args) throws JsonParseException, JsonMappingException, IOException {
        Response response = given().
                baseUri("http://services.groupkt.com/state/get/USA/all").get();
        Scanner sc = new Scanner(System.in);
        System.out.println(getLargestCityAndCapital(sc.nextLine(), response.getBody().asString()));
    }

    private static String getLargestCityAndCapital(String searchState, String responseBody) {
        JsonObject resultData = getJsonObjectFromJsonLevelOne("RestResponse", responseBody);
        JsonArray jArray = getJsonArrayFromJsonElement("result", resultData);
        for(int i = 0; i < jArray.size(); i++) {
            JsonObject jobj1 = jArray.get(i).getAsJsonObject();
            String StateName = jobj1.get("name").getAsString();
            String StateAbbr = jobj1.get("abbr").getAsString();
            if(searchState.equalsIgnoreCase(StateName) || searchState.equalsIgnoreCase(StateAbbr)) {
                String largestCity = jobj1.get("largest_city").getAsString();
                String capital = jobj1.get("capital").getAsString();
                return("Largest City is : " + largestCity + " and Capital is : " + capital);
            }
        }
        return ("No such city found.");
    }

    private static JsonObject getJsonObjectFromJsonLevelOne(String jsonElementIdentity, String jsonString) {
        JsonObject jobj = new Gson().fromJson(jsonString, JsonObject.class);
        return (jobj.get(jsonElementIdentity).getAsJsonObject());
    }

    public static JsonArray getJsonArrayFromJsonElement(String jsonElement, JsonObject jsonObject) {
        JsonArray properties = jsonObject.getAsJsonArray(jsonElement);
        return properties;
    }
}

无效情况下：

AL
Largest City is : Birmingham and Capital is : Montgomery

OOPS
No such city found.

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你想实现什么，条件是什么，最重要的问题是什么？兄弟，实际上我有一个API ie，问题是我需要从API的get方法获取数据，当我使用字符串url=com.Tecksystem\u demo\u Utility.url.FixUrl+EndPointURL.country.getResourcePath；response=Webservices.Geturl；System.out.printlnresponse.getBody.asString；响应显示为null，并创建一个程序，该程序根据用户输入的州名或州缩写返回最大城市和首都。将在一段时间内返回给您。let res={resresponse:{messages:[Total[249]records found.]，结果：[{name:Afghanistan，alpha2_code:AF，alpha3_code:AFG}let search='AFG'；let result=res.resresresponse.result.filterres=>{return res.alpha3_code.toLowerCase==search.toLowerCase；}；result.mapres=>{console.logres.name；}；这些是get Method背后的HTML逻辑非常感谢@learner8269，感谢您为我的任务贡献宝贵的时间