Java-从文本文件创建字符串数组
我有这样一个文本文件：Java-从文本文件创建字符串数组,java,string,Java,String,我有这样一个文本文件： abc def jhi klm nop qrs tuv wxy zzz 我想要一个字符串数组，如： String[] arr = {"abc def jhi","klm nop qrs","tuv wxy zzz"} 我试过： try { FileInputStream fstream_school = new FileInputStream("text1.txt"); DataInputStream data_input =
abc def jhi
klm nop qrs
tuv wxy zzz
String[] arr = {"abc def jhi","klm nop qrs","tuv wxy zzz"}
try
{
FileInputStream fstream_school = new FileInputStream("text1.txt");
DataInputStream data_input = new DataInputStream(fstream_school);
BufferedReader buffer = new BufferedReader(new InputStreamReader(data_input));
String str_line;
while ((str_line = buffer.readLine()) != null)
{
str_line = str_line.trim();
if ((str_line.length()!=0))
{
String[] itemsSchool = str_line.split("\t");
}
}
}
catch (Exception e)
{
// Catch exception if any
System.err.println("Error: " + e.getMessage());
}
所有答案都将不胜感激……使用a读取文件，将每行作为字符串读取，并将它们放在一个数组列表中，在循环结束时调用数组。如果使用Java 7，可以分两行完成，这要感谢：
List line=Files.readAllLines（您的文件，字符集）；
String[]arr=lines.toArray（新字符串[lines.size（）]）；
File file = new File("data.txt");
try {
//
// Create a new Scanner object which will read the data
// from the file passed in. To check if there are more
// line to read from it we check by calling the
// scanner.hasNextLine() method. We then read line one
// by one till all line is read.
//
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
String line = scanner.nextLine();
//store this line to string [] here
System.out.println(line);
}
} catch (FileNotFoundException e) {
e.printStackTrace();
}
[abc, def, jhi, klm, nop, qrs, tuv, wxy, zzz]
根据您的输入，您可以阅读有关扫描仪的更多信息，您就快到了。在循环中，您错过了保持从文件中读取每一行的位置。由于您事先不知道文件中的总行数，请使用集合（动态分配大小）获取所有内容，然后将其转换为
字符串的数组（因为这是您所需的输出）
大概是这样的：
String[] arr= null;
List<String> itemsSchool = new ArrayList<String>();
try
{
FileInputStream fstream_school = new FileInputStream("text1.txt");
DataInputStream data_input = new DataInputStream(fstream_school);
BufferedReader buffer = new BufferedReader(new InputStreamReader(data_input));
String str_line;
while ((str_line = buffer.readLine()) != null)
{
str_line = str_line.trim();
if ((str_line.length()!=0))
{
itemsSchool.add(str_line);
}
}
arr = (String[])itemsSchool.toArray(new String[itemsSchool.size()]);
}
这不是最佳解决方案。其他更聪明的答案已经给出。这只是您当前方法的一个解决方案 您可以使用readLine函数读取文件中的行并将其添加到数组中
例如：
File file = new File("abc.txt");
FileInputStream fin = new FileInputStream(file);
BufferedReader reader = new BufferedReader(fin);
List<String> list = new ArrayList<String>();
while((String str = reader.readLine())!=null){
list.add(str);
}
//convert the list to String array
String[] strArr = Arrays.toArray(list);
File File=new文件（“abc.txt”）；
FileInputStream fin=新的FileInputStream（文件）；
BufferedReader读取器=新的BufferedReader（fin）；
列表=新的ArrayList（）；
while（（String str=reader.readLine（））！=null）{
添加（str）；
}
//将列表转换为字符串数组
字符串[]strArr=Arrays.toArray（列表）；
上面的数组包含您所需的输出。这是我从文本文件创建数组生成随机电子邮件的代码
import java.io.*;
public class Generator {
public static void main(String[]args){
try {
long start = System.currentTimeMillis();
String[] firstNames = new String[4945];
String[] lastNames = new String[88799];
String[] emailProvider ={"google.com","yahoo.com","hotmail.com","onet.pl","outlook.com","aol.mail","proton.mail","icloud.com"};
String firstName;
String lastName;
int counter0 = 0;
int counter1 = 0;
int generate = 1000000;//number of emails to generate
BufferedReader firstReader = new BufferedReader(new FileReader("firstNames.txt"));
BufferedReader lastReader = new BufferedReader(new FileReader("lastNames.txt"));
PrintWriter write = new PrintWriter(new FileWriter("emails.txt", false));
while ((firstName = firstReader.readLine()) != null) {
firstName = firstName.toLowerCase();
firstNames[counter0] = firstName;
counter0++;
}
while((lastName= lastReader.readLine()) !=null){
lastName = lastName.toLowerCase();
lastNames[counter1]=lastName;
counter1++;
}
for(int i=0;i<generate;i++) {
write.println(firstNames[(int)(Math.random()*4945)]
+'.'+lastNames[(int)(Math.random()*88799)]+'@'+emailProvider[(int)(Math.random()*emailProvider.length)]);
}
write.close();
long end = System.currentTimeMillis();
long time = end-start;
System.out.println("it took "+time+"ms to generate "+generate+" unique emails");
}
catch(IOException ex){
System.out.println("Wrong input");
}
}
}
import java.io.*；
公共类生成器{
公共静态void main（字符串[]args）{
试一试{
长启动=System.currentTimeMillis（）；
String[]firstNames=新字符串[4945]；
字符串[]lastNames=新字符串[88799]；
String[]emailProvider={“google.com”、“yahoo.com”、“hotmail.com”、“onet.pl”、“outlook.com”、“aol.mail”、“proton.mail”、“icloud.com”}；
字符串名；
字符串lastName；
int计数器0=0；
int计数器1=0；
int generate=1000000；//要生成的电子邮件数
BufferedReader firstReader=新的BufferedReader（新文件阅读器（“firstNames.txt”）；
BufferedReader lastReader=新的BufferedReader（新文件阅读器（“lastNames.txt”）；
PrintWriter write=新的PrintWriter（新的FileWriter（“emails.txt”，false））；
而（（firstName=firstReader.readLine（））！=null）{
firstName=firstName.toLowerCase（）；
名字[0]=名字；
计数器0++；
}
而（（lastName=lastReader.readLine（））！=null）{
lastName=lastName.toLowerCase（）；
lastNames[counter1]=lastName；
计数器1++；
}
for（int i=0；iHello Edward，欢迎使用SO。如果您的问题已得到回答，请选择有效答案，谢谢：）+1我不知道readAllLines实用程序对小文件可能很方便。@assylias：我尝试过这个，但它在字符集上显示红色下划线。我该怎么办？提供文件使用的字符集-通常类似于charset.forName（“UTF-8”）
注意，他希望每一行都是数组中的一个条目，而不是被该行中的令牌分割。谢谢，我认为这是可行的，但在LogCat中，显示：Error:/text1.txt:open failed:enoint（没有这样的文件或目录）您应该在当前目录中有您的text1.txt
输入文件（正如您在问题中所做的那样）否则你需要提供路径和文件名。是的，我把它放在同一个文件夹中。对不起，我忘了提到我正在开发android应用程序。它会和普通Java应用程序的路径相同吗？是的，在同一个文件夹中，但最好不要把配置文件和源代码弄乱。你最好创建一个文件夹，然后放置我但我仍然发现了错误。一些教程提到了android的getFileDir（）方法，以便找到文件的路径。当我使用它时，在LogCat中要求我将文件放入/data/data中/
{"abc def jhi","klm nop qrs","tuv wxy zzz"}
File file = new File("abc.txt");
FileInputStream fin = new FileInputStream(file);
BufferedReader reader = new BufferedReader(fin);
List<String> list = new ArrayList<String>();
while((String str = reader.readLine())!=null){
list.add(str);
}
//convert the list to String array
String[] strArr = Arrays.toArray(list);
import java.io.*;
public class Generator {
public static void main(String[]args){
try {
long start = System.currentTimeMillis();
String[] firstNames = new String[4945];
String[] lastNames = new String[88799];
String[] emailProvider ={"google.com","yahoo.com","hotmail.com","onet.pl","outlook.com","aol.mail","proton.mail","icloud.com"};
String firstName;
String lastName;
int counter0 = 0;
int counter1 = 0;
int generate = 1000000;//number of emails to generate
BufferedReader firstReader = new BufferedReader(new FileReader("firstNames.txt"));
BufferedReader lastReader = new BufferedReader(new FileReader("lastNames.txt"));
PrintWriter write = new PrintWriter(new FileWriter("emails.txt", false));
while ((firstName = firstReader.readLine()) != null) {
firstName = firstName.toLowerCase();
firstNames[counter0] = firstName;
counter0++;
}
while((lastName= lastReader.readLine()) !=null){
lastName = lastName.toLowerCase();
lastNames[counter1]=lastName;
counter1++;
}
for(int i=0;i<generate;i++) {
write.println(firstNames[(int)(Math.random()*4945)]
+'.'+lastNames[(int)(Math.random()*88799)]+'@'+emailProvider[(int)(Math.random()*emailProvider.length)]);
}
write.close();
long end = System.currentTimeMillis();
long time = end-start;
System.out.println("it took "+time+"ms to generate "+generate+" unique emails");
}
catch(IOException ex){
System.out.println("Wrong input");
}
}
}