在java中将Youtube数据API V3视频持续时间转换为hh:mm:ss格式？

我正在使用Youtube data api v3获取视频信息，如标题、视图计数和持续时间。持续时间值对我来说是新的，因为它是

ISO8601日期

，我需要将其转换为可读格式，如hh:mm:ss。持续时间可以有以下不同的值：

PT1S-->00:01

PT1M-->01:00

PT1H-->01:00:00

PT1M1S-->01:01

PT1H1S-->01:00:01

PT1H1M1S-->01:01:01

我可以使用解析值并以秒为单位计算持续时间，但库的大小为500kb，这将增加我不想要的应用程序的大小。

查看以下代码：

private static HashMap<String, String> regexMap = new HashMap<>();
private static String regex2two = "(?<=[^\\d])(\\d)(?=[^\\d])";
private static String two = "0$1";

public static void main(String[] args) {

    regexMap.put("PT(\\d\\d)S", "00:$1");
    regexMap.put("PT(\\d\\d)M", "$1:00");
    regexMap.put("PT(\\d\\d)H", "$1:00:00");
    regexMap.put("PT(\\d\\d)M(\\d\\d)S", "$1:$2");
    regexMap.put("PT(\\d\\d)H(\\d\\d)S", "$1:00:$2");
    regexMap.put("PT(\\d\\d)H(\\d\\d)M", "$1:$2:00");
    regexMap.put("PT(\\d\\d)H(\\d\\d)M(\\d\\d)S", "$1:$2:$3");

    String[] dates = { "PT1S", "PT1M", "PT1H", "PT1M1S", "PT1H1S", "PT1H1M", "PT1H1M1S", "PT10H1M13S", "PT10H1S", "PT1M11S" };

    for (String date : dates) {
        String d = date.replaceAll(regex2two, two);
        String regex = getRegex(d);
        if (regex == null) {
            System.out.println(d + ": invalid");
            continue;
        }
        String newDate = d.replaceAll(regex, regexMap.get(regex));
        System.out.println(date + " : " +newDate);
    }    
}

private static String getRegex(String date) {
    for (String r : regexMap.keySet())
        if (Pattern.matches(r, date))
            return r;
    return null;
}

private static HashMap regexMap=new HashMap（）；
私有静态字符串regex2two=“（？也必须处理此问题。我必须将长度转换为毫秒，但一旦填充了secs/mins/hours变量，就可以转换为任何格式：

// Test Value
$vidLength = 'PT1H23M45S';

$secs = '';
$mins = '';
$hours = '';
$inspecting = '';
for($i=(strlen($vidLength)-1); $i>0; $i--){
    if(is_numeric($vidLength[$i])){
        if($inspecting == 'S'){
            $secs = $vidLength[$i].$secs;
        }
        else if($inspecting == 'M'){
            $mins = $vidLength[$i].$mins;
        }
        else if($inspecting == 'H'){
            $hours = $vidLength[$i].$hours;
        }
    }
    else {
        $inspecting = $vidLength[$i];
    }
}

$lengthInMS = 1000*(($hours*60*60) + ($mins*60) + $secs); 

我自己做的

让我们试试看

import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;
import java.util.

public class YouTubeDurationUtils {
    /**
     * 
     * @param duration
     * @return "01:02:30"
     */
    public static String convertYouTubeDuration(String duration) {
        String youtubeDuration = duration; //"PT1H2M30S"; // "PT1M13S";
        Calendar c = new GregorianCalendar();
        try {
            DateFormat df = new SimpleDateFormat("'PT'mm'M'ss'S'");
            Date d = df.parse(youtubeDuration);
            c.setTime(d);
        } catch (ParseException e) {
            try {
                DateFormat df = new SimpleDateFormat("'PT'hh'H'mm'M'ss'S'");
                Date d = df.parse(youtubeDuration);
                c.setTime(d);
            } catch (ParseException e1) {
                try {
                    DateFormat df = new SimpleDateFormat("'PT'ss'S'");
                    Date d = df.parse(youtubeDuration);
                    c.setTime(d);
                } catch (ParseException e2) {
                }
            }
        }
        c.setTimeZone(TimeZone.getDefault());

        String time = "";
        if ( c.get(Calendar.HOUR) > 0 ) {
            if ( String.valueOf(c.get(Calendar.HOUR)).length() == 1 ) {
                time += "0" + c.get(Calendar.HOUR);
            }
            else {
                time += c.get(Calendar.HOUR);
            }
            time += ":";
        }
        // test minute
        if ( String.valueOf(c.get(Calendar.MINUTE)).length() == 1 ) {
            time += "0" + c.get(Calendar.MINUTE);
        }
        else {
            time += c.get(Calendar.MINUTE);
        }
        time += ":";
        // test second
        if ( String.valueOf(c.get(Calendar.SECOND)).length() == 1 ) {
            time += "0" + c.get(Calendar.SECOND);
        }
        else {
            time += c.get(Calendar.SECOND);
        }
        return time ;
    }
}

我需要一个包含所有这些转换的持续时间的数组，所以我写了下面的代码作为解决方法，而且java.time.duration对我不起作用，不知道为什么

String[] D_uration = new String[10];
while(iteratorSearchResults.hasNext()){String Apiduration1=Apiduration.replace("PT","");
                            if(Apiduration.indexOf("H")>=0){
                                String Apiduration2=Apiduration1.replace("H",":");
                                if(Apiduration.indexOf("M")>=0){
                                    String Apiduration3=Apiduration2.replace("M",":");
                                    if(Apiduration.indexOf("S")>=0){
                                        D_uration[i]=Apiduration3.replace("S","");


                                    }
                                    else{
                                        String Apiduration4=Apiduration2.replace("M",":00");
                                        D_uration[i]=Apiduration4;
                                    }
                                }
                                else{
                                    String Apiduration4=Apiduration2.replace(":",":00:");
                                    if(Apiduration.indexOf("S")>=0){
                                        D_uration[i]=Apiduration4.replace("S","");


                                    }
                                    else{
                                        String Apiduration3=Apiduration4.replace(":00:",":00:00");
                                        D_uration[i]=Apiduration3;
                                    }
                                }
                            }
                            else{

                                if(Apiduration.indexOf("M")>=0){
                                    String Apiduration2=Apiduration1.replace("M",":");
                                    if(Apiduration.indexOf("S")>=0){
                                        D_uration[i]=Apiduration2.replace("S","");


                                    }
                                    else{
                                        String Apiduration4=Apiduration2.replace(":",":00");
                                        D_uration[i]=Apiduration4;
                                    }

                                }
                                else{

                                    D_uration[i]=Apiduration1.replace("S","");




                                }
                            }

“Apiduration”由Youtube数据Api以ISO8601格式返回

现在做了一些编辑，我想应该可以了。
这是最好的解决方案，到目前为止：）看看我的答案