如何从System.out.println()中删除尾随空格;JAVA
这是我的代码:如何从System.out.println()中删除尾随空格;JAVA,java,output,whitespace,Java,Output,Whitespace,这是我的代码: import java.util.*; public class Main { public static void fill(char mat[][], int x, int y, char prevV, char currV) { if (x < 0 || x >= mat.length || y < 0 || y >= mat.length) return; if (mat[x][y] != prevV)
import java.util.*;
public class Main {
public static void fill(char mat[][], int x, int y, char prevV, char currV) {
if (x < 0 || x >= mat.length || y < 0 || y >= mat.length)
return;
if (mat[x][y] != prevV)
return;
mat[x][y] = currV;
fill(mat, x + 1, y, prevV, currV);
fill(mat, x - 1, y, prevV, currV);
fill(mat, x, y + 1, prevV, currV);
fill(mat, x, y - 1, prevV, currV);
}
public static void replace(char mat[][]) {
for (int i = 0; i < mat.length; i++)
for (int j = 0; j < mat.length; j++)
if (mat[i][j] == 'O')
mat[i][j] = 'v';
for (int i = 0; i < mat.length; i++)
if (mat[i][0] == 'v')
fill(mat, i, 0, 'v', 'O');
for (int i = 0; i < mat.length; i++)
if (mat[i][mat.length - 1] == 'v')
fill(mat, i, mat.length - 1, 'v', 'O');
for (int i = 0; i < mat.length; i++)
if (mat[0][i] == 'v')
fill(mat, 0, i, 'v', 'O');
for (int i = 0; i <mat.length; i++)
if (mat[mat.length - 1][i] == 'v')
fill(mat, mat.length - 1, i, 'v', 'O');
for (int i = 0; i < mat.length; i++)
for (int j = 0; j < mat.length; j++)
if (mat[i][j] == 'v')
mat[i][j] = 'X';
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int m = sc.nextInt();
char[][] mat = new char[n][m];
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) {
mat[i][j] = sc.next().charAt(0);
}
}
replace(mat);
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) {
System.out.print(mat[i][j] + " ");
}
System.out.println();
}
}
}
import java.util.*;
公共班机{
公共静态空白填充(字符mat[][],整数x,整数y,字符prevV,字符currV){
如果(x<0 | | x>=材料长度| | y<0 | | y>=材料长度)
返回;
if(mat[x][y]!=prevV)
返回;
mat[x][y]=currV;
填充物(垫、x+1、y、上一层、当前);
填充物(垫、x-1、y、上一层、当前);
填充物(垫、x、y+1、上一层、当前);
填充物(垫、x、y-1、上一层、当前);
}
公共静态无效替换(char mat[][]){
对于(int i=0;i 对于(int i=0;i,当它位于行的末尾时,不要给出空格字符。
你可以这样写:
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (j < m - 1)
System.out.print(mat[i][j] + " ");
else
System.out.println(mat[i][j]);
}
}
for(int i=0;i
在行尾时不要给空格字符。
你可以这样写:
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
if (j < m - 1)
System.out.print(mat[i][j] + " ");
else
System.out.println(mat[i][j]);
}
}
for(int i=0;i
为输出空白添加条件:
for (int j = 0; j < m; j++) {
System.out.print(mat[i][j]);
if (j < m - 1) {
System.out.print(" ");
}
}
for(int j=0;j
为输出空白添加条件:
for (int j = 0; j < m; j++) {
System.out.print(mat[i][j]);
if (j < m - 1) {
System.out.print(" ");
}
}
for(int j=0;j
除了给出答案之外,您还可以这样做
for(int i = 0; i < n; i++) {
int j =0; //we move j outside so that it can be accessed later
for( ; j < m -1; j++) { //notice we skip the last entry of the row
System.out.print(mat[i][j] + " ");
}
System.out.println(mat[i][j]); //we add the last entry of the row here.
}
for(int i=0;i
优点是,您不需要每次迭代都进行if检查,并且对当前代码的更改最小。除了给出的答案之外,您还可以这样做
for(int i = 0; i < n; i++) {
int j =0; //we move j outside so that it can be accessed later
for( ; j < m -1; j++) { //notice we skip the last entry of the row
System.out.print(mat[i][j] + " ");
}
System.out.println(mat[i][j]); //we add the last entry of the row here.
}
for(int i=0;i
优点是您不需要每次迭代都进行if检查,并且对当前代码的更改最小。您还可以在else部分中使用println
,并将其从外循环中删除。您也可以在else部分中使用println
,并将其从外循环中删除。