Java startActivity（）不'；不要开始活动

我有一个名为ShowBoardList的类，我在其中检查用户是否已登录。如果用户尚未登录，那么我想返回到main活动，该活动为用户提供了登录不同服务的按钮

我的AndroidManifests.xml如下所示：

<application
   <activity android:name="im.chaitanya.TaskTimer.MainActivity" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <activity android:name="im.chaitanya.TaskTimer.WebViewActivity" >
    </activity>
    <activity android:name="im.chaitanya.TaskTimer.ShowBoardList"
        android:label="Your Tasks">
    </activity>
</application>

...
Intent mainActivityIntent = new Intent(ShowBoardList.this, im.chaitanya.TaskTimer.MainActivity.class);
Intent intent = getIntent();
String url = intent.getStringExtra(WebViewActivity.EXTRA_MESSAGE); //url can be null here
Keys keys = new Keys(); //this gets an API key

SharedPreferences settings = getSharedPreferences("mySettings", 0);
String savedToken = settings.getString("token", "Empty");

if (MyUtils.equalsWithNulls(url,"tasktimer://oauthresponse#token=")) {
    Log.d("From ME:", "I've reached inside url check");
    mainActivityIntent.putExtra(caller, "ShowBoardList");
    //caller is a String. I'm storing the name of the current activity (ShowBoardList) in it. 
    //So that the main activity (which I'm trying to call) will know where the call came from.
    startActivity(mainActivityIntent);
}

if(savedToken.equals("Empty") || savedToken.equals("")) {
    String searchString = "#token=";
    int tokenIndex = url.indexOf(searchString) + searchString.length(); //Since url can be null there can be an error here
    String token = url.substring(tokenIndex);
    savedToken = token;
    SharedPreferences.Editor editor = settings.edit();
    editor.putString("token", token);
    editor.apply();
}
...

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    SharedPreferences settings = getSharedPreferences("mySettings", 0);
    String token = settings.getString("token", "Empty");
    Intent intent = new Intent(this, ShowBoardList.class);

    if(token != "Empty") {
        startActivity(intent);
    }

    intent = getIntent();
    String callerActivity = intent.getStringExtra(ShowBoardList.caller);
    View coordinatorLayoutView = findViewById(R.id.snackbarPosition);

    if (callerActivity!=null && callerActivity == "ShowBoardList") {
        Snackbar
                .make(coordinatorLayoutView, "Permission Denied", Snackbar.LENGTH_LONG)
                .show();
    }
    setContentView(R.layout.activity_main);
}

conditionequalsWithNulls检查url是null还是等于参数中的字符串。我在那里有日志语句来检查控件是否到达if语句内部。然而，主要活动并未开始

MainActivity.java的编辑：onCreate（）如下所示：

<application
   <activity android:name="im.chaitanya.TaskTimer.MainActivity" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <activity android:name="im.chaitanya.TaskTimer.WebViewActivity" >
    </activity>
    <activity android:name="im.chaitanya.TaskTimer.ShowBoardList"
        android:label="Your Tasks">
    </activity>
</application>

...
Intent mainActivityIntent = new Intent(ShowBoardList.this, im.chaitanya.TaskTimer.MainActivity.class);
Intent intent = getIntent();
String url = intent.getStringExtra(WebViewActivity.EXTRA_MESSAGE); //url can be null here
Keys keys = new Keys(); //this gets an API key

SharedPreferences settings = getSharedPreferences("mySettings", 0);
String savedToken = settings.getString("token", "Empty");

if (MyUtils.equalsWithNulls(url,"tasktimer://oauthresponse#token=")) {
    Log.d("From ME:", "I've reached inside url check");
    mainActivityIntent.putExtra(caller, "ShowBoardList");
    //caller is a String. I'm storing the name of the current activity (ShowBoardList) in it. 
    //So that the main activity (which I'm trying to call) will know where the call came from.
    startActivity(mainActivityIntent);
}

if(savedToken.equals("Empty") || savedToken.equals("")) {
    String searchString = "#token=";
    int tokenIndex = url.indexOf(searchString) + searchString.length(); //Since url can be null there can be an error here
    String token = url.substring(tokenIndex);
    savedToken = token;
    SharedPreferences.Editor editor = settings.edit();
    editor.putString("token", token);
    editor.apply();
}
...

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    SharedPreferences settings = getSharedPreferences("mySettings", 0);
    String token = settings.getString("token", "Empty");
    Intent intent = new Intent(this, ShowBoardList.class);

    if(token != "Empty") {
        startActivity(intent);
    }

    intent = getIntent();
    String callerActivity = intent.getStringExtra(ShowBoardList.caller);
    View coordinatorLayoutView = findViewById(R.id.snackbarPosition);

    if (callerActivity!=null && callerActivity == "ShowBoardList") {
        Snackbar
                .make(coordinatorLayoutView, "Permission Denied", Snackbar.LENGTH_LONG)
                .show();
    }
    setContentView(R.layout.activity_main);
}

---

在需要的地方尝试定义你的新意图

Intent newIntent = new Intent(ShowBoardList.this, im.chaitanya.TaskTimer.MainActivity.class);
newIntent .putExtra(caller, "ShowBoardList");

startActivity(newIntent );

---

我的解决方案是基于苏拉布对这个问题的评论。我从日志中意识到，活动确实已经开始了

我没有意识到的是，当调用

startActivity（）

时，调用活动（在本例中是

ShowBoardList

）会暂停，当再次调用

ShowBoardList

时，它会从

startActivity（）

之后恢复

因此，这里的解决方案是调用

finish（）

，然后在startActivity（）之后立即返回

以确保下次调用onCreate。我希望，如果有人处于同样的情况，这是有道理的

这些问题帮助我进一步了解了
finish（）
：


有什么错误吗？怎么搞的？我用调试器来检查发生了什么。控件遍历该语句并转到if语句外的下一行。那边没有错。后来出现了一个错误，但这是因为主活动没有启动，程序试图调用空对象上的函数。我添加了一些代码。这应该让我更清楚地知道我在努力完成什么。但是就像我说的，startActivity（）语句没有错误。
startActivity（）
不是同步的。它立即返回，活动稍后开始。这是你的问题吗？可能是。如何等待活动开始？