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Java 合并时避免JPA和OneToMany关系中的ConstraintViolationException_Java_Hibernate_Postgresql_Jpa_One To Many - Fatal编程技术网

Java 合并时避免JPA和OneToMany关系中的ConstraintViolationException

Java 合并时避免JPA和OneToMany关系中的ConstraintViolationException,java,hibernate,postgresql,jpa,one-to-many,Java,Hibernate,Postgresql,Jpa,One To Many,我想通过下面的示例实现的是避免出现约束冲突异常 运行以下命令时: Parent p = new Parent(); Set<Child> children = new HashSet<Child>(); Child c = new Child(); children.add(c); p.setChildren(children); entityManager.merge(p); entityManager.merge(p); 如何配置JPA以实现此效果?下面是课程 @

我想通过下面的示例实现的是避免出现约束冲突异常 运行以下命令时:

Parent p = new Parent();
Set<Child> children = new HashSet<Child>();
Child c = new Child();
children.add(c);
p.setChildren(children);

entityManager.merge(p);
entityManager.merge(p);
如何配置JPA以实现此效果?下面是课程

@Entity
@Table(name = "parent", indexes = {uniqueConstraints = { @UniqueConstraint(columnNames = { "uri" }) })
public class Parent implements Serializable {
  ...
  private String uri;
  private Set<Child> children = new HashSet<Child>();


  @Id
  @Column(name = "id", unique = true)
  @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "parent_seq")
  @SequenceGenerator(name = "parent_seq", sequenceName = "parent_seq", allocationSize = 1)
  public Long getId() {
    return id;
  }

  @OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, orphanRemoval = true)
  @JoinColumn(name = "parent_id")
  public Set<Child> getChildren() {
    return children;
  }

@Override
  public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Parent other = (Parent) obj;
        if (uri == null) {
            if (other.uri != null)
                return false;
        } else if (!uri.equals(other.uri))
            return false;
        return true;
    }


@Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((uri == null) ? 0 : uri.hashCode());
        return result;
    }



}

@Entity
@Table(name = "child", indexes = {uniqueConstraints = { @UniqueConstraint(columnNames = { "text" }) })
public class Child implements Serializable {

  private String text;

  @Id
  @Column(name = "id", unique = true)
  @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "child_seq")
  @SequenceGenerator(name = "child_seq", sequenceName = "child_seq", allocationSize = 1)
  public Long getId() {
    return id;
  }



  @Override
  public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Child other = (Child) obj;
        if (text == null) {
            if (other.text != null)
                return false;
        } else if (!text.equals(other.text))
            return false;
        return true;
    }


@Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((text == null) ? 0 : text.hashCode());
        return result;
    }
}

我使用postgres和hibernate作为JPA提供程序

我不知道您使用的是哪个hibernate版本,但在版本4.3.5之前,@OneToMany注释上的fetch=FetchType.LAZY仍然存在问题。并且仅适用于@LazyCollectionLazyCollectionType.TRUE hibernate等效项在我的配置中,我有class=org.springframework.orm.jpa.vendor.hibernatejbavendorapter,spring orm的版本是4.0.4-RELEASE。根据这个链接,应该是Hibernate4.3.5-Final——我当然想用JPA,而不是Hibernate。