Java 从加载的文本文件输出数据时出现问题
我有一个程序,应该加载一个文本文件并显示/排序数据,但是数据根本没有显示。你知道我做错了什么吗?我只能坚持使用1.4.2Java 代码如下:Java 从加载的文本文件输出数据时出现问题,java,file-io,Java,File Io,我有一个程序,应该加载一个文本文件并显示/排序数据,但是数据根本没有显示。你知道我做错了什么吗?我只能坚持使用1.4.2Java 代码如下: import java.io.*; import java.util.StringTokenizer; class NewClass { private static int quantity; private static String[] name; public static void main(String args[]
import java.io.*;
import java.util.StringTokenizer;
class NewClass {
private static int quantity;
private static String[] name;
public static void main(String args[]) throws Exception {
InputStreamReader kb = new InputStreamReader(System.in);
BufferedReader in;
in = new BufferedReader(kb);
String buffer;
char choice;
boolean fileread=false;
int[]number=new int[quantity];
String[]name=new String[quantity];
String sorttype="";
do
{ //Setup Menu
choice=menu(in);
if(choice=='E')
{
if(fileread)
System.out.println("Data already has been entered");
else
{
fileread=true;
getdata(number,name);
}
}
else if(choice=='D')
{
if(fileread)
display(number,name,in);
else
System.out.println("Must enter data before it is displayed");
}
else if(choice=='S')
{
if(fileread)
sorttype=sort(number,name,in);
else
System.out.println("Must enter data before it is sorted");
}
} while(choice!='X');
}
//Sort Data
public static void sortint(int[] number, String[] name)
{
int i,j;
for(i=0;i<quantity-1;i++)
for(j=i+1;j<quantity;j++)
if(number[i]>number[j])
{
swap(number,i,j);
swap(name,i,j);
}
}
public static void sortstring(String[] name, int[] number)
{
int i,j;
for(i=0;i<quantity-1;i++)
for(j=i+1;j<quantity;j++)
if(name[i].compareToIgnoreCase(name[j])>0)
{
swap(number,i,j);
swap(name,i,j);
}
}
public static void swap(int[] a,int i,int j)
{
int t;
t=a[i];
a[i]=a[j];
a[j]=t;
}
public static void swap(String[] a,int i,int j)
{
String t;
t=a[i];
a[i]=a[j];
a[j]=t;
}
public static String sort(int[] number, String[] name, BufferedReader kb)throws Exception
{
String buffer;
do
{
//Allow user to sort the phone book
System.out.println("What do you want to sort by?");
System.out.println("Number");
System.out.println("Name");
System.out.print("Enter>>");
buffer=kb.readLine();
if(buffer.equalsIgnoreCase("number"))
{
sortint(number,name);
print(name, number,kb);
return buffer;
}
else if(buffer.equalsIgnoreCase("name"))
{
sortstring(name,number);
print(name,number,kb);
return buffer;
}
System.out.println("Invalid entry");
} while(true);
}
public static void print(String[] name, int[] number, BufferedReader kb)throws Exception
{
System.out.println("Sorted data");
System.out.println("Number\tName");
for(int i=0;i<quantity;i++)
System.out.println(number[i]+"\t"+name[i]);
}
public static void display(int[] number, String[] name, BufferedReader kb)throws Exception
{
System.out.println("Number Name");
for(int i=0;i<quantity;i++)
System.out.println(number[i]+" "+name[i]);
}
public static void getdata(int number[],String name[])throws Exception
{
FileReader file = new FileReader("phoneData.txt");
try (BufferedReader input = new BufferedReader(file)) {
int i;
String buffer;
for( i=0;i<quantity;i++)
{
buffer=input.readLine();
StringTokenizer st = new StringTokenizer(buffer, ",");
name[i]=st.nextToken();
number[i]=Integer.parseInt((st.nextToken()).trim());
}
}
}
public static char menu(BufferedReader kb)throws Exception
{
String buffer;
char input;
do
{
System.out.println("\nWhat would you like to do?");
System.out.println("E-Enter phone book data");
System.out.println("D-Display phone book data");
System.out.println("X-Exit program");
System.out.println("S-Sort list");
System.out.print("Enter E, D, X, S>>");
buffer=kb.readLine();
input=(buffer.toUpperCase()).charAt(0);
if(input=='E'||input=='D'||input=='X'||input=='S')
return input;
System.out.println("Invalid entry");
} while(true);
}
}
非常感谢您的帮助。您可能需要初始化
数量
private static int quantity = 1;
而不仅仅是
private static int quantity;
这样循环中的代码
for( i=0;i<quantity;i++)
因为您在main
中本地声明了name
编辑
public static void getdata(int number[],String name[])throws Exception
{
BufferedReader input = null;
try {
input = new BufferedReader(new FileReader("phoneData.txt"));
int i;
String buffer;
for( i=0;i<quantity;i++)
{
// readLinde returns null when EOF is reached
buffer=input.readLine();
if(buffer != null) {
StringTokenizer st = new StringTokenizer(buffer, ",");
name[i]=st.nextToken();
number[i]=Integer.parseInt((st.nextToken()).trim());
} else {
break; // since nothing left to read
// remaining buckets in the arrays are left empty
}
}
} catch (Exception e) {
// catch exceptions to where know your program fails
System.out.println(e.toString());
} finally {
if(input != null) {
// close the input stream when you are done
input.close();
}
}
}
@user1965245
phoneData.txt
可能只是空的或不存在(因为有异常,所以您不会知道它)。。。您没有检查input.readLine()
的返回值,而是从0
读取到quantity-1
。如果文件中的数据行数小于数量,那么您将在StringTokenizer
上获得一个NPE。。。而且你似乎没有任何输入数据的菜单选项。。。而且您的E
菜单选项有误导性,因为它从文件中读取数据…您想做什么?E-输入电话簿数据D-显示电话簿数据X-退出程序S-排序列表输入E,D,X,S>>D号码姓名号码数据应在“号码”下,但其为空,对于name@user1965245如果输入了E
,则方法为getdata(编号、名称)调用code>,并将fileread
设置为true
。如何用数据填充文件?“我必须坚持只使用1.4.2 Java”哎哟!为什么?@A4L文件已填充,文件中没有任何内容更改。按E键将文件加载到程序中,其他选项将对文件中的数据进行排序和显示,然后我得到您想做什么?E-Enter phone book data D-Display phone book data X-Exit program S-Sort list在java.util.StringTokenizer.nextToken(StringTokenizer.java:349)的NewClass.getdata(NewClass.java:130)的NewClass.main(NewClass.java:27)的线程“main”中输入E,D,X,S>>E异常
@user1965245你读过我的第一条评论吗??我在其中提到了所有这些,看看javadoc的说明,当传递的字符串为null时,它抛出一个N
ullP
ointerE
异常,当到达流的末尾时返回null。。。请参阅我的编辑,了解如何使代码更加健壮。我不太了解tokenizer,我在线阅读了如何在代码中使用它。所以我不确定是否有任何错误。这只是我的第一年
private static String[] name;
public static void getdata(int number[],String name[])throws Exception
{
BufferedReader input = null;
try {
input = new BufferedReader(new FileReader("phoneData.txt"));
int i;
String buffer;
for( i=0;i<quantity;i++)
{
// readLinde returns null when EOF is reached
buffer=input.readLine();
if(buffer != null) {
StringTokenizer st = new StringTokenizer(buffer, ",");
name[i]=st.nextToken();
number[i]=Integer.parseInt((st.nextToken()).trim());
} else {
break; // since nothing left to read
// remaining buckets in the arrays are left empty
}
}
} catch (Exception e) {
// catch exceptions to where know your program fails
System.out.println(e.toString());
} finally {
if(input != null) {
// close the input stream when you are done
input.close();
}
}
}
public static void getdata(List number,List name) {
BufferedReader input = null;
try {
input = new BufferedReader(new FileReader("phoneData.txt"));
String buffer;
while(null != (buffer = input.readLine())) {
StringTokenizer st = new StringTokenizer(buffer, ",");
name.add(st.nextToken());
number.add(Integer.valueOf(Integer.parseInt((st.nextToken()).trim())));
}
} catch (Exception e) {
System.out.println(e.toString());
} finally {
if(input != null) {
try {
input.close();
} catch (IOException e) {
// ignore
}
}
}
}