如何将包含数组的JSON转换为Java对象

无法转换包含少量元素和数组的JSON字符串。 在UI上，我需要将数组馈送到引导表

JSON字符串：

 {
    "IsOperationSuccessful": true,
    "IsResult": true,
    "StatusCode": "OK",
    "Response": [{
        "PlaylistCreatedBy": "XYZ",
        "PlaylistCreatedOn": "10/10/2019 14:10",
        "PlaylistDisplayTitle": "blah",
        "PlaylistId": 101,
        "PlaylistScheduledReleaseTime": "10/10/2019 14:10"
    }, {
        "PlaylistCreatedBy": "HHJK",
        "PlaylistCreatedOn": "10/10/2019 14:10",
        "PlaylistDisplayTitle": "blah blah",
        "PlaylistId": 102,
        "PlaylistScheduledReleaseTime": "10/10/2019 14:10"
    }, {
        "PlaylistCreatedBy": "HJHJ",
        "PlaylistCreatedOn": "10/10/2019 14:10",
        "PlaylistDisplayTitle": "UIUI",
        "PlaylistId": 103,
        "PlaylistScheduledReleaseTime": "10/10/2019 14:10"
    }, {
        "PlaylistCreatedBy": "KJK",
        "PlaylistCreatedOn": "10/10/2019 14:10",
        "PlaylistDisplayTitle": "kkj",
        "PlaylistId": 104,
        "PlaylistScheduledReleaseTime": "10/10/2019 14:10"
    }],
    "Total": 4
}

到目前为止，我添加了以下代码：

    PreRecordedCall morningCallResponse = new PreRecordedCall();
    JSONArray playListinfo = null; 
    String testResponse = "//Json Goes here "
    JSONObject finalJson = new JSONObject();
    finalJson.put("testResponse", testResponse); 
    Gson gson = new Gson();

    morningCallResponse = gson.fromJson(testResponse, 
    PreRecordedCall.class); 
    playListinfo =  morningCallResponse.getPreRecordplayListInformation(); 

---

检查以下代码是否适用于您：

String finalJson= "//Json Goes here ";
ObjectMapper objectMapper = new ObjectMapper();
try {
    PreRecordedCall morningCallResponse = objectMapper.readValue(json, PreRecordedCall.class);
} catch (JsonProcessingException e) {
    e.printStackTrace();
}

---

一种方法是创建2个POJO（表示

Response

和

PreRecordedCall

），如下所示。

Response

用于带有键“Response”的JSON数组，

PreRecordedCall

用于整个JSON对象。关键是使用

List

存储JSON数组

顺便说一句，为了遵循POJO中变量的命名规则，使用

@SerializedName

进行对象名称映射

课堂反应

static class Response {
    @SerializedName("PlaylistCreatedBy")
    private String playlistCreatedBy;

    @SerializedName("PlaylistCreatedOn")
    private String playlistCreatedOn;

    @SerializedName("PlaylistDisplayTitle")
    private String playlistDisplayTitle;

    @SerializedName("PlaylistId")
    private int playlistId;

    @SerializedName("PlaylistScheduledReleaseTime")
    private String playlistScheduledReleaseTime;

    //general getters and setters
}

类预录呼叫

static class PreRecordedCall {
    @SerializedName("IsOperationSuccessful")
    private Boolean isOperationSuccessful;

    @SerializedName("IsResult")
    private Boolean isResult;

    @SerializedName("StatusCode")
    private String statusCode;

    @SerializedName("Response")
    private List<Response> response;

    @SerializedName("Total")
    private int total;

    //general getters and setters
}

控制台输出

四,

如果您使用

Jackson

作为JSON解析器，请将

@SerializedName

更改为

@JsonProperty

，您可以通过以下代码片段获得相同的结果

ObjectMapper mapper = new ObjectMapper();
PreRecordedCall preRecordedCall = mapper.readValue(testResponse, PreRecordedCall.class);
System.out.println(preRecordedCall.getResponse().size());

---

这很好，但我的响应需要是JSONArray而不是列表，因为我需要将此响应提供给引导表。

ObjectMapper mapper = new ObjectMapper();
PreRecordedCall preRecordedCall = mapper.readValue(testResponse, PreRecordedCall.class);
System.out.println(preRecordedCall.getResponse().size());