如何在aws中运行java lambda函数

试一试{ PreparedStatement pst=con.PrepareStatement插入员工详细信息E_姓名、E_密码、E_用户名、E_联系人、， +E_角色价值观？，？，？，？，？；； 状态=1

        pst.setString(1,employee.getEname());//Step 7: calling getter() from getter/setter class
    //Step 10: setting getter values to corresponding query
        pst.setString(2,employee.getPass());//Step 7: calling getter() from getter/setter class
            //Step 10: setting getter values to corresponding
        pst.setString(3,employee.getUname());//Step 7: calling getter() from getter/setter class
            //Step 10: setting getter values to corresponding 
        pst.setString(4,employee.getEcontact());//Step 7: calling getter() from getter/setter class
            //Step 10: setting getter values to corresponding 
        pst.setInt(5,employee.getUrole());//Step 7: calling getter() from getter/setter class
            //Step 10: setting getter values to corresponding 
        pst.executeQuery();
        System.out.println("name:"+employee.getEname()+"  pass:"+employee.getPass()+"   uname:"+employee.getUname()+"  con:"+employee.getEcontact()+"  role:"+employee.getUrole());

    }
    catch(SQLException e){
        e.printStackTrace();
    }

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prepare语句末尾有一个不需要的分号，请将其删除

试试这个

 PreparedStatement pst=con.prepareStatement("INSERT INTO employee_details (E_NAME,E_PASSWORD,E_USERNAME,E_CONTACT,"
                + "E_ROLE) VALUES (?,?,?,?,?)");

而不是

 PreparedStatement pst=con.prepareStatement("INSERT INTO employee_details (E_NAME,E_PASSWORD,E_USERNAME,E_CONTACT,"
                + "E_ROLE) VALUES (?,?,?,?,?);"); 

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没什么可继续的。您的表是什么样子的？您试图插入什么数据？可能希望将println移动到表的第一行，以查看您的数据是否为badRefer Java文档