Java startForeground的错误通知(调用记录器API 29)

Java startForeground的错误通知(调用记录器API 29),java,android,Java,Android,我在做一个电话录音程序但是, 操作\新\传出\调用权限从api 29中删除,它给出了这样一个错误。 我的目标,删除此权限使用的代码,我该怎么办?我不希望收到我们的输出信息。请帮忙 我的代码: public void onReceive(Context context, Intent intent) { String action = intent.getAction(); if (!action.equals(TelephonyManager.ACTION_PHO

我在做一个电话录音程序但是, 操作\新\传出\调用权限从api 29中删除,它给出了这样一个错误。 我的目标,删除此权限使用的代码,我该怎么办?我不希望收到我们的输出信息。请帮忙

我的代码:

public void onReceive(Context context, Intent intent) {
        String action = intent.getAction();
        if (!action.equals(TelephonyManager.ACTION_PHONE_STATE_CHANGED) &&
                !action.equals(Intent.ACTION_NEW_OUTGOING_CALL)) {
            return;
        }

        String phoneNumber = intent.getStringExtra(Intent.EXTRA_PHONE_NUMBER);
        String extraState = intent.getStringExtra(TelephonyManager.EXTRA_STATE);

        Log.d(Constants.TAG, "PhoneReceiver phone number: " + phoneNumber);
        if (!FileHelper.isStorageWritable(context))
            return;
        if (Intent.ACTION_NEW_OUTGOING_CALL.equals(intent.getAction())) {
            App.isOutComming = true;
        }
        if (extraState != null) {
            dispatchExtra(context, intent, phoneNumber, extraState);
        } else if (phoneNumber != null) {
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
                context.startForegroundService(new Intent(context, RecordService.class)
                        .putExtra("commandType", Constants.STATE_INCOMING_NUMBER)
                        .putExtra("phoneNumber", phoneNumber));
            } else {
                context.startService(new Intent(context, RecordService.class)
                        .putExtra("commandType", Constants.STATE_INCOMING_NUMBER)
                        .putExtra("phoneNumber", phoneNumber));
            }
        } else {
            Log.d(Constants.TAG, "phone number x:x " + null);
        }
    }
但当我关闭此应用程序时,我看到以下错误:

android.app.RemoteServiceException: Bad notification for startForeground: java.lang.RuntimeException: invalid channel for service notification: Notification(channel=null pri=0 contentView=null vibrate=null sound=null defaults=0x0 flags=0x40 color=0x00000000 number=0 vis=PRIVATE semFlags=0x0 semPriority=0 semMissedCount=0)

你应该为android.O创建通知频道

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            val importance = android.app.NotificationManager.IMPORTANCE_LOW
            val mChannel = NotificationChannel(CHANNEL_ID, CHANNEL_NAME, importance)
            mChannel.description = CHANNEL_DESCRIPTION
            mChannel.enableLights(true)
            mChannel.lightColor = Color.RED
            mChannel.enableVibration(true)
            val mNotificationManager =
                context.getSystemService(Context.NOTIFICATION_SERVICE) as android.app.NotificationManager
            mNotificationManager.createNotificationChannel(mChannel)
        }
在创建通知时,您应该为其提供通道id

 NotificationCompat.Builder(context, CHANNEL_ID)

我有这样一个代码//startForeground(1,newnotification());您是否尝试使用channel id NotificationCompat.Builder(上下文,channel_id)通知我是一名新开发人员:)。我不知道怎么做。但我将学习thanksnotification=newNotificationCompat.Builder(getActivity()).setContentTitle(getActivity().getString(R.string.app_name)).setTicker(“fgfgf”).setContentText(getActivity().getString(R.string.record_enabled)).SetMallIcon(R.drawable.icon_notification).setLargeIcon(notificationLargeIconBitmap).setContentIntent(PendingContent).setContinuous(true).build();阅读此博客