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BitmapFactory:无法解码流:java.io.FileNotFoundException,即使文件实际存在_Java_Android - Fatal编程技术网

BitmapFactory:无法解码流:java.io.FileNotFoundException,即使文件实际存在

BitmapFactory:无法解码流:java.io.FileNotFoundException,即使文件实际存在,java,android,Java,Android,我正在创建一个简单的应用程序来拍照。这是我的密码 Button b1; ImageView iv; String TAG = "MAIN ACTIVITY"; File photo; private Uri mImageUri; private File createTemporaryFile(String part, String ext) throws Exception { File externalStorageDirectory = Environment.getEx

我正在创建一个简单的应用程序来拍照。这是我的密码

Button b1;
ImageView iv;
String TAG = "MAIN ACTIVITY";

File photo;
private Uri mImageUri;


private File createTemporaryFile(String part, String ext) throws Exception {


    File externalStorageDirectory = Environment.getExternalStorageDirectory();
    File tempDir = new File(externalStorageDirectory + "/cameratest/");
    if (!tempDir.exists()) {
        tempDir.mkdir();

    }
    return File.createTempFile(part, ext, tempDir);
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);


    b1 = (Button) findViewById(R.id.button);
    iv = (ImageView) findViewById(R.id.imageView);

    b1.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            Intent intent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);

            try {
                // place where to store camera taken picture
                photo = createTemporaryFile("picture", ".jpg");
                photo.delete();
            } catch (Exception e) {
                Log.v(TAG, "Can't create file to take picture!");
                Toast.makeText(getApplicationContext(), "Please check SD card! Image shot is impossible!",
                        Toast.LENGTH_SHORT).show();

            }

            mImageUri = Uri.fromFile(photo);
            intent.putExtra(MediaStore.EXTRA_OUTPUT, mImageUri);

            startActivityForResult(intent, 0);
        }
    });
}

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // TODO Auto-generated method stub
    super.onActivityResult(requestCode, resultCode, data);


    if (requestCode == 0 && resultCode == RESULT_OK) {



        Log.d(TAG, mImageUri.toString());
        Bitmap bitmap = BitmapFactory.decodeFile(mImageUri.toString());
        iv.setImageBitmap(bitmap);

    }


}
如您所见,我添加了
eLog.d(标记,mimageri.toString())
在结尾和logcat(以及
文件NotFoundException
)中,我看到了以下目录:

03-27 00:43:30.498 30526-30526/myapplication.example.falcoleo.cameratest1 D/MAIN ACTIVITY: file:///storage/emulated/0/cameratest/picture459838058.jpg
03-27 00:43:30.499 30526-30526/myapplication.example.falcoleo.cameratest1 E/BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: file:/storage/emulated/0/cameratest/picture459838058.jpg: open failed: ENOENT (No such file or directory)
猜猜这个目录是否存在? 斯波勒警报。而且图像不是在
位图工厂.decodeFile
之后创建的。我真的不明白我做错了什么。一切正常,除非它实际上必须显示照片,然后它就不显示了。一片空白。就像WTF m8一样,我只是想做好我的工作,不必发疯,你知道的

file:///storage/emulated/0/cameratest/picture459838058.jpg
删除
文件://
,因为decodeFile()需要文件系统路径

/storage/emulated/0/cameratest/picture459838058.jpg

mimageri.toString()
替换为
mimageri.getPath()


decodeFile
需要路径,而不是uri字符串。

使用BitmapFactory.decodeStream而不是BitmapFactory.decodeFile

try ( InputStream is = new URL( file_url ).openStream() ) {
  Bitmap bitmap = BitmapFactory.decodeStream( is );
}

Source

对我来说,是文件路径错误,所以我需要获取真实的文件路径

首先

File file = new File(getPath(uri));

public String getPath (Uri uri)
{
    String[] projection = {MediaStore.Images.Media.DATA};
    Cursor cursor = getContentResolver().query(uri,
                                               projection,
                                               null,
                                               null,
                                               null);
    if (cursor == null)
        return null;
    int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
    cursor.moveToFirst();
    String s = cursor.getString(column_index);
    cursor.close();
    return s;
}
然后返回Uri

Uri newUri = Uri.fromFile(file);

这种对文件和uri的转换为我带来了好处。我从action.SEND收到了简单的数据。

您确定您有权限在外部内存中读/写吗?我有权限确保它正常工作。我使用了
string.replace(“文件://”,“”)
是否有更优雅的解决方案?有许多其他复杂的系统可以获取文件路径,但这是一些人可能需要遵循的方向。。。我只是发布了一个简单的(从其他地方复制和粘贴)以简单的方式展示我的观点