Java Spring:找不到URI为的HTTP请求的映射
我已经开始使用spring,遇到了这个错误 在名为“SpringSocialSample”的DispatcherServlet中找不到URI为[/SpringSocialSample/login.htm]的HTTP请求的映射 我发现DispatcherServlet无法找到login.htm My SpringSocialSample-servlet.xmlJava Spring:找不到URI为的HTTP请求的映射,java,spring,spring-mvc,Java,Spring,Spring Mvc,我已经开始使用spring,遇到了这个错误 在名为“SpringSocialSample”的DispatcherServlet中找不到URI为[/SpringSocialSample/login.htm]的HTTP请求的映射 我发现DispatcherServlet无法找到login.htm My SpringSocialSample-servlet.xml <context:component-scan base-package="com.social.spring.co
<context:component-scan
base-package="com.social.spring.controllers" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/views/" p:suffix=".jsp" />
web.xml-
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID"
version="2.5">
<display-name>SpringSocialSample</display-name>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>updatestatus.root</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>SpringSocialSample</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>SpringSocialSample</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
SpringSocialSample
WebApprotKey
根
上下文配置位置
/WEB-INF/applicationContext.xml
SpringSocialSample
org.springframework.web.servlet.DispatcherServlet
2.
SpringSocialSample
*.htm
org.springframework.web.context.ContextLoaderListener
index.jsp
我将index.jsp重定向到login.jsp,并将其放在WEB-INF/views下。您已经将Spring Dispatcher映射到*.htm,因此每次请求与该模式匹配的url时,Dispatcher都会查找映射到该特定url请求的控制器,它不会尝试加载静态文件(也就是说,您的login.html html文件被此配置有效隐藏,除非您首先通过将其作为视图发送回的Spring控制器,否则无法返回该文件)。您创建一个Spring控制器,返回该页面,将其映射到[login.htm]URI,然后Spring将不再抱怨它找不到该URL的映射: 查看“13.4.处理程序映射”一章: