Java InvalidDataAccessResourceUsageException:org.hibernate.exception.SQLGrammarException:

我有以下问题，我被困了一段时间：

我得到这个错误： org.springframework.dao.InvalidDataAccessResourceUsageException:无法准备语句；SQL[调用hibernate_序列的下一个值]；嵌套异常为org.hibernate.exception.sqlgrammareexception:无法准备语句

我发现有此错误的人之所以会得到它，是因为他们使用保留字作为表名，但我认为这不是我的问题

我的两个模型类如下。我跳过了接球手/二传手和接球手

@Entity
@Table(name = "GATEWAY_MODEL")
public class GetewayModel implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    @Column(name = "serial_number", nullable = false, length = 12, updatable = true)
    private String serialNumber;
    @Column(name = "name", nullable = false, length = 12, updatable = true)
    private String name;
    @Column(name = "ipFour", nullable = false, length = 12, updatable = true)
    private String ipFour;
    @Column(name = "peripheral_devices", updatable = true)
    @OneToMany(cascade = CascadeType.ALL, mappedBy = "gateway")
    private Set<PeripheralDevicesModel> peripheralDevices = new HashSet<PeripheralDevicesModel>();


@Entity
@Table(name = "PERIPHERAL_DIVICES_MODEL")
public class PeripheralDevicesModel {
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    @Column(name = "uID", nullable = false)
    private String uID;
    @Column(name = "vendor", nullable = false)
    private String vendor;
    @Column(name = "date_created", nullable = false)
    private Date dateCreated;
    @Enumerated(EnumType.STRING)
    @Column(name = "status")
    private Status status;
    @JsonIgnore
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "gateway")
    private GetewayModel gateway;

更新： 在生成GenerationType.IDENTITY后，我现在出现以下错误：

Hibernate: 
    select
        getewaymod0_.id as id1_0_1_,
        getewaymod0_.ip_four as ip_four2_0_1_,
        getewaymod0_.name as name3_0_1_,
        getewaymod0_.serial_number as serial_n4_0_1_,
        peripheral1_.gateway as gateway5_1_3_,
        peripheral1_.id as id1_1_3_,
        peripheral1_.id as id1_1_0_,
        peripheral1_.date_created as date_cre2_1_0_,
        peripheral1_.gateway as gateway5_1_0_,
        peripheral1_.uid as uid3_1_0_,
        peripheral1_.vendor as vendor4_1_0_ 
    from
        gateway_model getewaymod0_ 
    left outer join
        peripheral_divices_model peripheral1_ 
            on getewaymod0_.id=peripheral1_.gateway 
    where
        getewaymod0_.id=?
2020-06-26 16:42:04 - SQL Error: 42102, SQLState: 42S02
2020-06-26 16:42:04 - Table "GATEWAY_MODEL" not found; SQL statement:
select getewaymod0_.id as id1_0_1_, getewaymod0_.ip_four as ip_four2_0_1_, getewaymod0_.name as name3_0_1_, getewaymod0_.serial_number as serial_n4_0_1_, peripheral1_.gateway as gateway5_1_3_, peripheral1_.id as id1_1_3_, peripheral1_.id as id1_1_0_, peripheral1_.date_created as date_cre2_1_0_, peripheral1_.gateway as gateway5_1_0_, peripheral1_.uid as uid3_1_0_, peripheral1_.vendor as vendor4_1_0_ from gateway_model getewaymod0_ left outer join peripheral_divices_model peripheral1_ on getewaymod0_.id=peripheral1_.gateway where getewaymod0_.id=? [42102-200]
2020-06-26 16:42:04 - HHH000327: Error performing load command
org.hibernate.exception.SQLGrammarException: could not prepare statement

我改变了两件事（除了代码中的一些语法/打字错误）：

添加了

cascade=CascadeType。所有
如下：

 @JsonIgnore
 @ManyToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
 @JoinColumn(name = "gateway")
 private GatewayModel gateway;

无法添加包含列的

nullable=false

：
setGateway（新的getwaymodel（））

devices.setGateway（网关）

否则，它在

H2

上工作正常

更新：
要查找的语法/打字错误：

• @Table（name=“PERIPHERAL\u DIVICES\u MODEL”）

  需要是

  @Table（name=“PERIPHERAL\u DEVICES\u MODEL”）

• 公共类网关模型

  需要是

  公共类网关模型

• 专用网关

  需要是

  私有网关模型网关

---

HIbernate无法执行“为HIbernate\u序列调用下一个值”。你在使用什么数据库？休眠_序列是否存在？你真的想使用GenerationType.AUTO吗？嗨，我正在使用H2数据库，我已经用application.properties configutarionOK更新了我的代码。我的问题是，为什么要使用GenerationType.auto，这不是特别的原因。只是举个例子，但不明白这是怎么回事？可能我错了。请尝试将其更改为GenerationType.IDENTITY，然后重试。我认为这是问题所在，因为错误显示“HIBERNATE_SEQUENCE”未找到。嗨，我添加了cascade=CascadeType.ALL和remove nullable=false，但我仍然得到相同的错误兄弟，我更新了我的答案。检查你的语法/打字错误。

Hibernate: 
    select
        getewaymod0_.id as id1_0_1_,
        getewaymod0_.ip_four as ip_four2_0_1_,
        getewaymod0_.name as name3_0_1_,
        getewaymod0_.serial_number as serial_n4_0_1_,
        peripheral1_.gateway as gateway5_1_3_,
        peripheral1_.id as id1_1_3_,
        peripheral1_.id as id1_1_0_,
        peripheral1_.date_created as date_cre2_1_0_,
        peripheral1_.gateway as gateway5_1_0_,
        peripheral1_.uid as uid3_1_0_,
        peripheral1_.vendor as vendor4_1_0_ 
    from
        gateway_model getewaymod0_ 
    left outer join
        peripheral_divices_model peripheral1_ 
            on getewaymod0_.id=peripheral1_.gateway 
    where
        getewaymod0_.id=?
2020-06-26 16:42:04 - SQL Error: 42102, SQLState: 42S02
2020-06-26 16:42:04 - Table "GATEWAY_MODEL" not found; SQL statement:
select getewaymod0_.id as id1_0_1_, getewaymod0_.ip_four as ip_four2_0_1_, getewaymod0_.name as name3_0_1_, getewaymod0_.serial_number as serial_n4_0_1_, peripheral1_.gateway as gateway5_1_3_, peripheral1_.id as id1_1_3_, peripheral1_.id as id1_1_0_, peripheral1_.date_created as date_cre2_1_0_, peripheral1_.gateway as gateway5_1_0_, peripheral1_.uid as uid3_1_0_, peripheral1_.vendor as vendor4_1_0_ from gateway_model getewaymod0_ left outer join peripheral_divices_model peripheral1_ on getewaymod0_.id=peripheral1_.gateway where getewaymod0_.id=? [42102-200]
2020-06-26 16:42:04 - HHH000327: Error performing load command
org.hibernate.exception.SQLGrammarException: could not prepare statement

 @JsonIgnore
 @ManyToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
 @JoinColumn(name = "gateway")
 private GatewayModel gateway;