Java 比较给定方法头的名称？v2

嗯，另一个问题很老了，我想不太可能有更多的人会偶然发现它并阅读/回答它，所以下面是： 给定标题：

public boolean equals(Name otherName)

我应该比较两个名称对象是否相等。我现在得到的是：

public boolean equals(Name otherName){
        return (otherName.equalsIgnoreCase(this));
    }

正如前一个帖子中的某人所建议的那样

但是，我得到一个找不到符号错误

下面是我要挑剔的其余代码。请原谅我的草率和诸如此类的行为，今晚我的代码一点也不好

Name.java：

public class Name{
    private String firstName;
    private String middleName;
    private String lastName;

    public Name (String first, String middle, String last){
        firstName = first;
        middleName = middle;
        lastName = last;
    }

    public String getFirst(){
    return firstName;
    }

    public String getMiddle(){
        return middleName;
    }

    public String getLast(){
        return lastName;
    }

    public String firstMiddleLast(){
        return (firstName + middleName + lastName);
    }

    public String lastFirstMiddle(){
        return (lastName + ", " + middleName + firstName);      
    }

    public boolean equals(Name otherName){
        return (otherName.equalsIgnoreCase(this));
    }

    public String initials(){
        String initials = firstName.substring(0,1) + middleName.substring(0,1) + lastName.substring(0,1);
        initials.toUpperCase();
        return initials; 
    }

    public int length(){
        int sum = firstName.length() + middleName.length() + lastName.length();
        return sum;
    }
}

TestingNames.java：

import java.util.Scanner;

public class TestNames{
    public static void main(String[] args){
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter the first name, middle name, and last name in that order for the first name object.");
    Name name = new Name(scan.next(), scan.next(), scan.next());
    System.out.println("Enter the second name, middle name, and last name in that order for the first name object.");
    Name name2 = new Name(scan.next(), scan.next(), scan.next());   

    System.out.println("Printing name in the order first name, middle name, last name");
    System.out.println(name.firstMiddleLast());
    System.out.println(name2.firstMiddleLast());

    System.out.println("Printing name in the order last name, first name, middle name");
    System.out.println(name.lastFirstMiddle());
    System.out.println(name2.lastFirstMiddle());

    System.out.println("Printing initials");
    System.out.println(name.initials());
    System.out.println(name2.initials());

    System.out.println("Printing name length");
    System.out.println(name.length());
    System.out.println(name2.length());

    System.out.println("Are these names equal?");
    System.out.println(name.equals(name2));



    }
}

在中使用时，没有在类名中实现equalsIgnoreCase方法：

public boolean equals(Name otherName){
    return (otherName.equalsIgnoreCase(this));
}

所以错误肯定会发生。 您可以尝试：

 public boolean equals(Name otherName){
    if(firstName.equalsIgnoreCase(otherName.firstName) && middleName.equalsIgnoreCase(otherName.middleName) && lastName.equalsIgnoreCase(otherName.lastName))
        return true;
    else 
        return false;
}

您正在比较的对象不是字符串

---

尝试返回otherName.equalsIgnoreCasethis.firstName；我的猜测是，Name并没有声明equalsIgnoreCase字符串。你为什么超载？另外，请提供一个到上一个问题的链接，这样我们可以了解一些背景。好吧，这将是一个愚蠢的问题，但请容忍我：你说它没有实现是什么意思？我只需要调用这个方法就行了。Sorryit适用于字符串，因为它是在那里实现的。如果您正在使用它，您必须像定义equals方法一样定义此方法。查看我的最新答案

public boolean equals(Name otherName){
            return (otherName.getFirst().equalsIgnoreCase(firstName));
        }