使用javax.XML.xpath时使用标记查询XML Bloxk

我正在尝试使用xpath获取XML块（不仅仅是元素值）。遇到了几篇这样的文章，我能够对上面提到的问题得到很好的回答。但是，如何获取XML块作为xpath（如/Employees）的响应

i、 例如，得到回应

<Employee id="1">
    <age>29</age>
    <name>Pankaj</name>
    <gender>Male</gender>
    <role>Java Developer</role>
</Employee>
<Employee id="2">
    <age>35</age>
    <name>Lisa</name>
    <gender>Female</gender>
    <role>CEO</role>
</Employee>
<Employee id="3">
    <age>40</age>
    <name>Tom</name>
    <gender>Male</gender>
    <role>Manager</role>
</Employee>
<Employee id="4">
    <age>25</age>
    <name>Meghna</name>
    <gender>Female</gender>
    <role>Manager</role>
</Employee>

代码：

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你能分享你目前拥有的不适用于你的代码吗？@ug_u它基本上与链接中提到的相同，只是有一些小的调整。在问题中添加了代码。您需要将返回的DOM节点序列化为XML标记，使用Java，您可以使用DOM级别3加载和保存或JAXP默认转换器。

    29
    Pankaj
    Male
    Java Developer


    35
    Lisa
    Female
    CEO


    40
    Tom
    Male
    Manager


    25
    Meghna
    Female
    Manager  

package com.eugthom.xmlBlock;

import java.io.IOException;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;

import org.w3c.dom.Document;
import org.xml.sax.SAXException;

public class XpathEvaluate {

/**
 * @param args
 */
public static void main(String[] args) {
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    factory.setNamespaceAware(true);
    DocumentBuilder builder;
    Document doc = null;
    try {
        builder = factory.newDocumentBuilder();
        doc = builder.parse("C:\\Users\\thoeu01\\Desktop\\a.xml");

        // Create XPathFactory object
        XPathFactory xpathFactory = XPathFactory.newInstance();

        // Create XPath object
        XPath xpath = xpathFactory.newXPath();

        String nodeName = getEntireNode(doc, xpath);
        System.out.println("Node is: " + nodeName);

    } catch (ParserConfigurationException | SAXException | IOException e) {
        e.printStackTrace();
    }

}

private static String getEntireNode(Document doc, XPath xpath) {
    String name = null;
    try {
        XPathExpression expr = xpath.compile("/Employees");
//          name = (String) expr.evaluate(doc, XPathConstants.STRING).toString();
        name = expr.evaluate(doc);
    } catch (XPathExpressionException e) {
        e.printStackTrace();
    }

    return name;
}
}