每当用户输入负数时,我需要帮助尝试重新输入值 import java.util.*; 公共类继承{ 公共静态扫描仪objScan=新扫描仪(System.in); 公共静态void main(字符串[]args){ System.out.println(“输入名称:”); 字符串strName=objScan.nextLine(); 双双数据表; 内耳; 字符串strTIN; 字符串strLoopControl=“1”; 试一试{ System.out.println(“输入薪资:”); dSalary=dGetSalary(); System.out.println(“输入工作年限:”); iYears=iGetYears(); System.out.println(“输入ID号:”); strTIN=strGetID(); Employee1 objEmp=新员工1(strName、dSalary、iyear、strTIN); print(); } 捕获(例外e){ if(负输入异常的实例){ strLoopControl=“0”; System.out.println(e.getMessage()); //strLoopControl=“0”; } else if(例如ZeroIdentificationException的实例){ System.out.println(e.getMessage()); } } } 公共静态双dGetSalary()引发NegativeInputException{ 双双数据表; 做{ 试试{ dSalary=objScan.nextDouble(); 如果(数据量=最大值) 抛出新的IllegalArgumentException(“…”) while(true){ System.out.println(“请输入一个整数(“+minValue+”-“+maxValue+”)); int val=objScan.nextInt(); 如果(val>=minValue&&val
而不是抛出每当用户输入负数时,我需要帮助尝试重新输入值 import java.util.*; 公共类继承{ 公共静态扫描仪objScan=新扫描仪(System.in); 公共静态void main(字符串[]args){ System.out.println(“输入名称:”); 字符串strName=objScan.nextLine(); 双双数据表; 内耳; 字符串strTIN; 字符串strLoopControl=“1”; 试一试{ System.out.println(“输入薪资:”); dSalary=dGetSalary(); System.out.println(“输入工作年限:”); iYears=iGetYears(); System.out.println(“输入ID号:”); strTIN=strGetID(); Employee1 objEmp=新员工1(strName、dSalary、iyear、strTIN); print(); } 捕获(例外e){ if(负输入异常的实例){ strLoopControl=“0”; System.out.println(e.getMessage()); //strLoopControl=“0”; } else if(例如ZeroIdentificationException的实例){ System.out.println(e.getMessage()); } } } 公共静态双dGetSalary()引发NegativeInputException{ 双双数据表; 做{ 试试{ dSalary=objScan.nextDouble(); 如果(数据量=最大值) 抛出新的IllegalArgumentException(“…”) while(true){ System.out.println(“请输入一个整数(“+minValue+”-“+maxValue+”)); int val=objScan.nextInt(); 如果(val>=minValue&&val,java,exception,input,Java,Exception,Input,而不是抛出NegativeInputException,您可以将nextInt代码包装在while循环中,该循环只返回正值 此外,也许将输入功能包装到如下方法中是个好主意 import java.util.*; public class Inheritance { public static Scanner objScan = new Scanner(System.in); public static void main(String[] args) {
NegativeInputException
,您可以将nextInt
代码包装在while循环中,该循环只返回正值
此外,也许将输入功能包装到如下方法中是个好主意
import java.util.*;
public class Inheritance {
public static Scanner objScan = new Scanner(System.in);
public static void main(String[] args) {
System.out.println("Enter name:");
String strName = objScan.nextLine();
double dSalary;
int iYears;
String strTIN;
String strLoopControl = "1";
try {
System.out.println("Enter salary:");
dSalary = dGetSalary();
System.out.println("Enter years worked:");
iYears = iGetYears();
System.out.println("Enter ID number:");
strTIN = strGetID();
Employee1 objEmp = new Employee1(strName, dSalary, iYears, strTIN);
objEmp.print();
}
catch (Exception e) {
if (e instanceof NegativeInputException) {
strLoopControl = "0";
System.out.println(e.getMessage());
//strLoopControl = "0";
}
else if (e instanceof ZeroIdentificationException) {
System.out.println(e.getMessage());
}
}
}
public static double dGetSalary () throws NegativeInputException {
double dSalary;
do {
try {
dSalary = objScan.nextDouble();
if (dSalary < 0) {
throw new NegativeInputException();
}
return dSalary;
}
catch (NegativeInputException nie) {
throw nie;
}
} while (dSalary<0);
}
public static int iGetYears() throws NegativeInputException {
int iYears;
try {
iYears = objScan.nextInt();
if (iYears < 0) {
throw new NegativeInputException();
}
return iYears;
}
catch (NegativeInputException nie) {
throw nie;
}
}
public static String strGetID() throws ZeroIdentificationException {
String strTIN;
try {
strTIN = objScan.next();
if (strTIN.equals("0000000")) {
throw new ZeroIdentificationException();
}
return strTIN;
}
catch (ZeroIdentificationException zie) {
throw zie;
}
}
}
class NegativeInputException extends Exception {
public NegativeInputException() {
super("You have inputted a negative number.");
}
public NegativeInputException (String strMessage) {
super(strMessage);
}
}
class ZeroIdentificationException extends Exception {
public ZeroIdentificationException() {
super("You inputted an invalid ID number. \n Please input again.");
}
public ZeroIdentificationException(String strMessage) {
super(strMessage);
}
}
class Person1 {
private String strName;
public Person1() {
strName = "";
}
public Person1(String strName) {
this.strName = strName;
}
public void setName(String strName) {
this.strName = strName;
}
public String getName() {
return strName;
}
public void print() {
System.out.println("Name: " +strName);
}
}
class Employee1 extends Person1 {
private String strName;
private double dSalary;
private int iYears;
private String strTIN;
public Employee1 (String strName, double dSalary, int iYears, String strTIN) {
this.strName = strName;
this.dSalary = dSalary;
this.iYears = iYears;
this.strTIN = strTIN;
}
public void print() {
System.out.println();
System.out.print("Name: " +this.strName);
System.out.println();
System.out.print("Salary:" +this.dSalary);
System.out.println();
System.out.print("Years WorkedS:" +this.iYears);
System.out.println();
System.out.print("ID Number:" +this.strTIN);
}
}
int readInteger(int minValue,int maxValue){
如果(最小值>=最大值)
抛出新的IllegalArgumentException(“…”)
while(true){
System.out.println(“请输入一个整数(“+minValue+”-“+maxValue+”));
int val=objScan.nextInt();
如果(val>=minValue&&val而不是抛出一个NegativeInputException
,您可以将nextInt
代码包装在一个while循环中,该循环只返回正值
此外,也许将输入功能包装到如下方法中是个好主意
import java.util.*;
public class Inheritance {
public static Scanner objScan = new Scanner(System.in);
public static void main(String[] args) {
System.out.println("Enter name:");
String strName = objScan.nextLine();
double dSalary;
int iYears;
String strTIN;
String strLoopControl = "1";
try {
System.out.println("Enter salary:");
dSalary = dGetSalary();
System.out.println("Enter years worked:");
iYears = iGetYears();
System.out.println("Enter ID number:");
strTIN = strGetID();
Employee1 objEmp = new Employee1(strName, dSalary, iYears, strTIN);
objEmp.print();
}
catch (Exception e) {
if (e instanceof NegativeInputException) {
strLoopControl = "0";
System.out.println(e.getMessage());
//strLoopControl = "0";
}
else if (e instanceof ZeroIdentificationException) {
System.out.println(e.getMessage());
}
}
}
public static double dGetSalary () throws NegativeInputException {
double dSalary;
do {
try {
dSalary = objScan.nextDouble();
if (dSalary < 0) {
throw new NegativeInputException();
}
return dSalary;
}
catch (NegativeInputException nie) {
throw nie;
}
} while (dSalary<0);
}
public static int iGetYears() throws NegativeInputException {
int iYears;
try {
iYears = objScan.nextInt();
if (iYears < 0) {
throw new NegativeInputException();
}
return iYears;
}
catch (NegativeInputException nie) {
throw nie;
}
}
public static String strGetID() throws ZeroIdentificationException {
String strTIN;
try {
strTIN = objScan.next();
if (strTIN.equals("0000000")) {
throw new ZeroIdentificationException();
}
return strTIN;
}
catch (ZeroIdentificationException zie) {
throw zie;
}
}
}
class NegativeInputException extends Exception {
public NegativeInputException() {
super("You have inputted a negative number.");
}
public NegativeInputException (String strMessage) {
super(strMessage);
}
}
class ZeroIdentificationException extends Exception {
public ZeroIdentificationException() {
super("You inputted an invalid ID number. \n Please input again.");
}
public ZeroIdentificationException(String strMessage) {
super(strMessage);
}
}
class Person1 {
private String strName;
public Person1() {
strName = "";
}
public Person1(String strName) {
this.strName = strName;
}
public void setName(String strName) {
this.strName = strName;
}
public String getName() {
return strName;
}
public void print() {
System.out.println("Name: " +strName);
}
}
class Employee1 extends Person1 {
private String strName;
private double dSalary;
private int iYears;
private String strTIN;
public Employee1 (String strName, double dSalary, int iYears, String strTIN) {
this.strName = strName;
this.dSalary = dSalary;
this.iYears = iYears;
this.strTIN = strTIN;
}
public void print() {
System.out.println();
System.out.print("Name: " +this.strName);
System.out.println();
System.out.print("Salary:" +this.dSalary);
System.out.println();
System.out.print("Years WorkedS:" +this.iYears);
System.out.println();
System.out.print("ID Number:" +this.strTIN);
}
}
int readInteger(int minValue,int maxValue){
如果(最小值>=最大值)
抛出新的IllegalArgumentException(“…”)
while(true){
System.out.println(“请输入一个整数(“+minValue+”-“+maxValue+”));
int val=objScan.nextInt();
如果(val>=minValue&&val您的方法被破坏-当值为负值时,它们尝试循环,但如果值为负值,它们将抛出异常…因此它们只会执行一次循环,返回值或抛出异常
你想要这样的东西:
int readInteger(int minValue, int maxValue) {
if (minValue >= maxValue)
throw new IllegalArgumentException("...")
while(true) {
System.out.println("Please enter an integer ("+minValue+"-"+maxValue+")");
int val = objScan.nextInt();
if (val >= minValue && val <= maxValue) return val;
}
}
double readDouble(...
您可能应该重复提示,并在无效输入时给出错误消息,尽管
还请注意:
- 捕获一个异常,然后像这样再次抛出它是很可怕的:
public static double getNonNegativeDouble(Scanner scanner) {
while (true) {
double value = scanner.nextDouble();
if (value >= 0) {
return value;
}
}
}
- 您的“伪匈牙利”方法名称违反Java命名约定
- 捕捉
Exception
然后使用instanceof
检查不同的类型是可怕的;只需捕捉您感兴趣的类型即可
您的方法已损坏-它们试图在值为负值时循环,但如果值为负值,它们将引发异常…因此它们只会执行一次循环,返回值或引发异常
你想要这样的东西:
int readInteger(int minValue, int maxValue) {
if (minValue >= maxValue)
throw new IllegalArgumentException("...")
while(true) {
System.out.println("Please enter an integer ("+minValue+"-"+maxValue+")");
int val = objScan.nextInt();
if (val >= minValue && val <= maxValue) return val;
}
}
double readDouble(...
您可能应该重复提示,并在无效输入时给出错误消息,尽管
还请注意:
- 捕获一个异常,然后像这样再次抛出它是很可怕的:
public static double getNonNegativeDouble(Scanner scanner) {
while (true) {
double value = scanner.nextDouble();
if (value >= 0) {
return value;
}
}
}
- 您的“伪匈牙利”方法名称违反Java命名约定
- 捕捉
Exception
然后使用instanceof
检查不同的类型是可怕的;只需捕捉您感兴趣的类型即可
我知道我在这里有点冒险,但我在尝试提问时添加了“家庭作业”标签,因为这样的代码在现实生活中是不可能使用的。非常感谢。这是我第一次在这里提问,所以我没有意识到标签的重要性。:)我知道我在这里有点冒险,但我在尝试提问时添加了“家庭作业”标签,因为这样的代码在现实生活中是不可能使用的。非常感谢。这是我第一次在这里提问,所以我没有意识到标签的重要性。:)我想在这里补充一点,使用异常来处理逻辑流——特别是在同一个方法中——是一个坏主意,而且很快就会变得混乱。我想这是一个合理的例子来解释为什么。根本不需要在这里抛出异常——你可以按照Jon的建议,将if块的结构更改为相同、更简单的结尾。我d在这里补充说,使用异常来处理逻辑流——特别是在同一个方法中——是一个坏主意,而且很快就会变得混乱。我想这是一个合理的例子,说明了为什么。根本不需要在这里抛出异常——正如Jon所建议的那样,您可以将if块的结构更改为相同、更简单的结尾。