使用java在xml中搜索结束排除_Java_Xml_Xpath

使用java在xml中搜索结束排除

java xml xpath

使用java在xml中搜索结束排除,java,xml,xpath,Java,Xml,Xpath,我正在尝试在xml文件中搜索这些事件： <xml> <corpus> <body> <nonterminals> <graph> <s> <nt id="s9_509" cat="fcl"></nt> <nt id="s9_501" cat="pp"> <edge label="H" idref="s9_1"/>

我正在尝试在xml文件中搜索这些事件：

<xml>  
<corpus>  
<body>  
<nonterminals>  
<graph>  
<s>  
<nt id="s9_509" cat="fcl"></nt>  

<nt id="s9_501" cat="pp">  
                <edge label="H" idref="s9_1"/>  
                <edge label="DP" idref="s9_502"/>  
                <edge label="STA" idref="s9_509"/>  
                <edge label="P" idref="s9_19"/>  
                <edge label="S" idref="s9_510"/>  
                <edge label="PU" idref="s9_25"/>  
            </nt>  
</nonterminals>  
</graph>  
</s>  
</body>  
</corpus>  
</xml>

我的代码是：

XPath xpath = XPathFactory.newInstance().newXPath();    
String path = "//xml//corpus//build//s//graph//nonterminals//nt";  
XPathExpression expr = xpath.compile(path);    
System.out.println("Query1: "+path);  
Object result = expr.evaluate(document, XPathConstants.NODESET);    
NodeList nodes = (NodeList) result;    
System.out.println("Number of nodes: "+nodes.getLength());  
for (int i = 0; i < nodes.getLength(); i++) {    
    System.out.println(nodes.item(i).getAttributes().getNamedItem("id").getNodeValue());

XPath=XPathFactory.newInstance（）.newXPath（）；
String path=“//xml//corpus//build//s//graph//nonterminals//nt”；
XPathExpression expr=xpath.compile（路径）；
System.out.println（“Query1:+path”）；
对象结果=expr.evaluate（文档，XPathConstants.NODESET）；
节点列表节点=（节点列表）结果；
System.out.println（“节点数：+nodes.getLength（））；
对于（inti=0；i


这个问题正确吗？
还有别的办法吗？
如何删除节点结果？
如果这是XML的整个结构，并且
是根节点，那么XPath应该是：
/xml/corpus/build/s/graph/nonterminals/nt
有一些有用的免费工具可以查看XPath查询的结果，而无需预先编写java：

>/P>>在XML/Objult/Cudio>中，我们也会考虑两个标签之间的中间标签。只有在开始时，你应该有<代码> /< />代码>，然后你应该使用<代码> /< /代码>。我已经尝试过了，但是节点的结果仍然是：我猜这是一个打印错误，但是你的XML有I。nvalid嵌套…这是一个有效的XML，但我猜这不是问题所在，我将检查代码中的错误，谢谢。我可以向您保证，上面的示例不是有效的XML。谢谢，我将在之后输入链接
//nt