Java HQL：在查询中有条件地计算子集合

我在HQL方面相当缺乏经验，所以我想知道是否有人能在这方面帮助我。我有一段关系，学生和学生学院只有一个办公室的关系。我试图写一个查询，查找每个申请的学生，以及他们提交了多少申请。我写了下面的查询，但我不确定它是否接近我应该做的

select distinct new ReportVO (stu.id, stu.first_name, stu.last_name, stu.year, stu.school.school_name, sum(case when si.applied = 1 then 1 else 0 end) as numApplications) " +
                    "from StudentCollege as si join si.student as stu where stu.year <= 12 and stu.user.id = :userId and si.applied = 1 order by stu.last_name

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感谢您的帮助

我相信您在where子句之后缺少了一个“groupby”子句

select distinct new ReportVO (stu.id, stu.first_name, stu.last_name, stu.year, stu.school.school_name, sum(case when si.applied = 1 then 1 else 0 end) as numApplications) " +
                    "from StudentCollege as si join si.student as stu where stu.year <= 12 and stu.user.id = :userId and si.applied = 1 group by stu.id, stu.first_name, stu.last_name, stu.year, stu.school.school_name order by stu.last_name

选择不同的新报告VO（stu.id、stu.first\u name、stu.last\u name、stu.year、stu.school.school\u name、sum（当si.applicated=1，则为1，否则为0）作为numApplications）+
“从StudentCollege作为si加入si.student作为stu，其中stu.year不幸地添加了group by子句，产生了相同的异常和消息——“无法在课堂上找到合适的构造函数”，尽管如此，我还是很欣赏这个想法。
public ReportVO(int id, String firstName, String lastName, int year, String school, Integer numApplications)

select distinct new ReportVO (stu.id, stu.first_name, stu.last_name, stu.year, stu.school.school_name, sum(case when si.applied = 1 then 1 else 0 end) as numApplications) " +
                    "from StudentCollege as si join si.student as stu where stu.year <= 12 and stu.user.id = :userId and si.applied = 1 group by stu.id, stu.first_name, stu.last_name, stu.year, stu.school.school_name order by stu.last_name