Java XML结构创建问题
I以下格式的数据(HashMap列表) 下面是所需的输出Java XML结构创建问题,java,xml,Java,Xml,I以下格式的数据(HashMap列表) 下面是所需的输出 <node id="1" label="India" > <node id="1.1" label="Sachin" Score="170" /> <node id="1.2" label="Sehwag" Score="120" /> </node> <node id="2" label="Sri-Lanka"> <node i
<node id="1" label="India" >
<node id="1.1" label="Sachin" Score="170" />
<node id="1.2" label="Sehwag" Score="120" />
</node>
<node id="2" label="Sri-Lanka">
<node id="2.1" label="Sangakara" Score="20" />
<node id="2.2" label="Murali" Score="20" />
<node id="2.3" label="Jayasurya" Score="70" />
</node>
<node id="3" label="World-XI">
<node id="2.2" label="Murali" Score="20" />
<node id="1.1" label="Sachin" Score="170" />
</node>
现在,我已经能够生成上述结构,但有一个问题,“node id=3”中的id需要重复,而不是重新创建为3.1/3.2
另一个是,不一定是节点3是最后一个,我可以只为它迭代,但可能还有很多其他节点
下面是上面的当前代码,有什么建议吗
Map hm = new HashMap();
Element em = null;
try {
int serverId = 0;
int clientId = 0;
DocumentBuilderFactory documentBuilderFactory =
DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
Document document = documentBuilder.newDocument();
Element rootElement = document.createElement("CricketDetails");
document.appendChild(rootElement);
for (int i=0; i < l.size(); i++) {
hm = (HashMap) l.get(i);
sortListIP.add(hm.get("TeamName"));
}
Collections.sort(sortListIP);
HashSet h = new HashSet(sortListIP);
sortListIP.clear();
sortListIP.addAll(h);
for (int i=0; i < sortListIP.size(); i++) {
++serverId;
clientId = 0;
em = document.createElement("node");
em.setAttribute("id", ""+serverId);
em.setAttribute("TeamName", ""+sortListIP.get(i));
for (int j=0; j < l.size();j++) {
hm = (HashMap) l.get(j);
if (sortListIP.get(i).equals(hm.get("TeamName"))) {
Element em_child = document.createElement("node");
++clientId;
em_child.setAttribute("id", serverId+"."+clientId);
em_child.setAttribute("label", (String) hm.get("Name"));
em.appendChild(em_child);
rootElement.appendChild(em);
}
}
}
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource source = new DOMSource(document);
StreamResult result = new StreamResult("cricketDetails.xml");
transformer.transform(source, result);
Map hm=newhashmap();
元素em=null;
试一试{
int serverId=0;
int clientId=0;
DocumentBuilderFactory DocumentBuilderFactory=
DocumentBuilderFactory.newInstance();
DocumentBuilder DocumentBuilder=documentBuilderFactory.newDocumentBuilder();
Document Document=documentBuilder.newDocument();
Element rootElement=document.createElement(“CricketDetails”);
document.appendChild(rootElement);
对于(int i=0;i
另外,定义的格式可能不正确,但只需要这样的预期输出!如果要修改使用代码生成的节点的属性id,请修改包含em_child.setAttribute(“id”,serverId+“+clientId”)的行;适当。父节点id的生成方式类似 我不确定您的xml是否不完整,但在xml中,您需要有根或文档实体 [XML]文档以“根”开头 或文件实体。”-
XML代码工作得非常好,我已经测试过了,当然我有一个根元素。我唯一的问题是迭代,我只需要这方面的帮助。您的代码缺少理解它所必需的细节,例如sortListIP的声明。此外,您应该使用泛型集合来实现类型安全。
Map hm = new HashMap();
Element em = null;
try {
int serverId = 0;
int clientId = 0;
DocumentBuilderFactory documentBuilderFactory =
DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
Document document = documentBuilder.newDocument();
Element rootElement = document.createElement("CricketDetails");
document.appendChild(rootElement);
for (int i=0; i < l.size(); i++) {
hm = (HashMap) l.get(i);
sortListIP.add(hm.get("TeamName"));
}
Collections.sort(sortListIP);
HashSet h = new HashSet(sortListIP);
sortListIP.clear();
sortListIP.addAll(h);
for (int i=0; i < sortListIP.size(); i++) {
++serverId;
clientId = 0;
em = document.createElement("node");
em.setAttribute("id", ""+serverId);
em.setAttribute("TeamName", ""+sortListIP.get(i));
for (int j=0; j < l.size();j++) {
hm = (HashMap) l.get(j);
if (sortListIP.get(i).equals(hm.get("TeamName"))) {
Element em_child = document.createElement("node");
++clientId;
em_child.setAttribute("id", serverId+"."+clientId);
em_child.setAttribute("label", (String) hm.get("Name"));
em.appendChild(em_child);
rootElement.appendChild(em);
}
}
}
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource source = new DOMSource(document);
StreamResult result = new StreamResult("cricketDetails.xml");
transformer.transform(source, result);