java.sql.SQLException：没有这样的列

我被指派使用sqlite演示CRUD操作。当我尝试从数据库检索项目时，我的ResultSet似乎没有“id”列。我很困惑

这是我的ContactRepository类

public class ContactRepositoryJDBC implements ContactRepository {

    private static Connector connector = new Connector();

    ...

    public Contact getById(int id) throws SQLException {
        Contact contact = null;

        try (Connection conn = connector.getConnection();
            PreparedStatement statement = conn
                    .prepareStatement(SQL.GET_CONTACT_BY_ID)) {
            statement.setInt(1, id);
            try (ResultSet resultSet = statement.executeQuery()) {
                if (resultSet.next()) {
                    contact = new Contact();
                    contact.setId(resultSet.getInt("id"));
                    contact.setFirstName(resultSet.getString("first_name"));
                    contact.setSurname(resultSet.getString("surname"));
                    contact.setHomeNumber(resultSet.getString("home_number"));
                    contact.setCellNumber(resultSet.getString("cell_number"));
                    contact.setEmail(resultSet.getString("email"));
                }
            }
        }

        if (contact == null) {
            System.out.print("no contact with id " + id + " found : ");
        }
        return contact;
    }

...

}

我对sql语句使用单独的类

public class SQL {

...

public static final String GET_CONTACT_BY_ID = "SELECT first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?";

...

}

我得到一个SQLException“没有这样的列id”

编辑：

接触模型类

public class Contact {

    private int id;
    private String firstName;
    private String surname;
    private String homeNumber;
    private String cellNumber;
    private String email;

    public Contact(String firstName, String surname, String homeNumber,
            String cellNumber, String email) {
        this.firstName = firstName;
        this.surname = surname;
        this.homeNumber = homeNumber;
        this.cellNumber = cellNumber;
        this.email = email;
    }

    public Contact() {

    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    ... getters and setter for everything else
}

---

您的选择不包括列

id

，因此它不在结果集中。将其添加到选择中：

public static final String GET_CONTACT_BY_ID = "SELECT id, first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?";

您的SQL查询

public static final String GET_CONTACT_BY_ID = "SELECT first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?";

不要选择id列。您只能从查询中选择的结果集中检索这些列

为了获得id列值，您需要将查询修改为

public static final String GET_CONTACT_BY_ID = "SELECT id,first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?";

---

查询您使用的数据库时：

SELECT first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?

但是在

resultset

中，您需要id

contact.setId（resultset.getInt（“id”）

因此，错误将查询更改为：

SELECT id, first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?

只需检查您的数据库“CONTACT”表是否包含名为“id”的列。
此错误仅在列名不匹配时出现

您的查询是正确的
请输入实体联系人的代码好吗？您是如何创建数据库的？是否有名为“id”的列？select语句在select关键字后不包含id列。谢谢大家。成功了。现在我坐了几个小时却没有注意到，我觉得自己很傻。非常感谢。！
SELECT id, first_name, surname, home_number, cell_number, email FROM Contact WHERE id = ?