Java矩形类区域/周长输出0
当我运行my Rectangle.java时,我可以得到矩形中输入的长度和宽度,但是当我试图用getter计算面积/周长时,结果是零 我试图添加和删除setter,将getter/setter方法放在getArea和getPermission中,但似乎没有任何效果Java矩形类区域/周长输出0,java,getter-setter,Java,Getter Setter,当我运行my Rectangle.java时,我可以得到矩形中输入的长度和宽度,但是当我试图用getter计算面积/周长时,结果是零 我试图添加和删除setter,将getter/setter方法放在getArea和getPermission中,但似乎没有任何效果 //Code provided by the teacher as a template Rectangle temp = new Rectangle(); temp.print(); System.
//Code provided by the teacher as a template
Rectangle temp = new Rectangle();
temp.print();
System.out.println();
temp.setLength(2.5);
temp.setWidth(3.0);
//Consider how your rectangle will change after setting the length and width to specific values.
temp.print();
System.out.println();
Rectangle r = new Rectangle(3.5,2);
r.print();
//My Class
public class Rectangle
{
private static double length;
private static double width;
private static double perimeter;
private static double area;
public Rectangle(double length, double width)
{
setLength(length);
setWidth(width);
}
public Rectangle()
{
}
public static double getLength()
{
return length;
}
public static void setLength(double length)
{
Rectangle.length = length;
}
public static double getWidth()
{
return width;
}
public static void setWidth(double width)
{
Rectangle.width = width;
}
public static double getPerimeter(double length, double width)
{
return 2*width+2*length;
}
public static double getArea(double length, double width)
{
area= getLength()*getWidth();
return length*width;
}
public static String print()
{
String Rectangle = new String();
System.out.println("This rectangle has a length of "+length+" and a width of "+width);
System.out.println("The area of the rectangle is: "+ area);
System.out.println("The perimeter of the rectangle is: "+ perimeter);
return Rectangle;
}
}
没有错误消息
输出:
此矩形的长度为0.0,宽度为0.0
矩形的面积为:0.0
矩形的周长为:0.0
此矩形的长度为2.5,宽度为3.0
矩形的面积为:0.0
矩形的周长为:0.0
此矩形的长度为3.5,宽度为2.0
矩形的面积为:0.0
矩形的周长为:0.0您需要更改打印方法并调用周长和面积方法,以便这些变量获得所需的值
public static String print()
{
getPerimeter(length,width);
getArea(length,width);
String Rectangle = new String();
System.out.println("This rectangle has a length of "+length+" and a width of "+width);
System.out.println("The area of the rectangle is: "+ area);
System.out.println("The perimeter of the rectangle is: "+ perimeter);
return Rectangle;
}
我建议不要使用静态关键字,因为这些值不会绑定到对象您能给出完整的矩形类吗?按要求添加完整的矩形类。我是新来这里的,上面写着“重要部分”。真的有那么明显吗?!多谢各位ⵍⵢⴻⵙ. 问题结束。我是个新手,所以容易犯愚蠢的错误。
stringrectangle=newstring()
。我建议您更改此变量的名称,这非常令人困惑。我已经从其中一条评论中找到了一个简单的问题,但我将继续阅读此线程,以获得良好的编码实践,因为我想成为真正的优秀