用Java中的正则表达式匹配字符串中的浮点数

我试图用java中的正则表达式在一个特定的单词后找到一个浮点数，但我只在单词和浮点数之间没有任何内容时才得到它，但我想得到它，即使有空格、任何其他字符和新行

这里是我制作的正则表达式：

(?<=TOTAL)([+-]?([0-9]*[.])?[0-9]+)

---

（？我将这个问题解释为，您希望提取某个单词后面的第一个浮点数，而不管两者之间是什么。
一个非贪婪的通配符只会帮你做到这一点

（？我将这个问题解释为，您希望提取某个单词后面的第一个浮点数，而不管两者之间是什么。
一个非贪婪的通配符只会帮你做到这一点

（？使用

看

解释

--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  TOTAL                    'TOTAL'
--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  [\s\S]*?                 any character of: whitespace (\n, \r, \t,
                           \f, and " "), non-whitespace (all but \n,
                           \r, \t, \f, and " ") (0 or more times
                           (matching the least amount possible))
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [+-]?                    any character of: '+', '-' (optional
                             (matching the most amount possible))
--------------------------------------------------------------------------------
    \d*                      digits (0-9) (0 or more times (matching
                             the most amount possible))
--------------------------------------------------------------------------------
    \.?                      '.' (optional (matching the most amount
                             possible))
--------------------------------------------------------------------------------
    \d+                      digits (0-9) (1 or more times (matching
                             the most amount possible))
--------------------------------------------------------------------------------
  )                        end of \1

Java代码：

String regex = "\\bTOTAL\\b[\\s\\S]*?([+-]?\\d*\\.?\\d+)";
String string = "69003 LYON 03 ejuodnid 04 72.84.75.20 affm groa TICKET FACTURE 361203- SEPHORA EYE PALET LIG PALE 29991 14.99 Sephora Collection -Prix 392729 SEPHORA CINESCOPE 16.501 328451- SEPHORA THE MASC BIG MASC goe( 6.99193.49 P Sephora Co11ection Prix 347597SEPHORA LING GRENADE NG 25 i5.99 1) 2.99 Sephora Collect1o0 PriX adoy (30 00 1o)o 6.00 oniop20% achats Black Mars 2019 451087 OFFRE 20%ACHATS 15.00 MASC 16.50 3.50 3.00 N'2 24.00 VPBLA 0.00 tnoe 0001* 1eepom TOTAL EUR 62.00";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(string);
if (matcher.find()) {
    System.out.println(matcher.group(1));
}

结果：
62.00
使用

\bTOTAL\b[\s\S]*?([+-]?\d*\.?\d+)

看

解释

--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  TOTAL                    'TOTAL'
--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  [\s\S]*?                 any character of: whitespace (\n, \r, \t,
                           \f, and " "), non-whitespace (all but \n,
                           \r, \t, \f, and " ") (0 or more times
                           (matching the least amount possible))
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [+-]?                    any character of: '+', '-' (optional
                             (matching the most amount possible))
--------------------------------------------------------------------------------
    \d*                      digits (0-9) (0 or more times (matching
                             the most amount possible))
--------------------------------------------------------------------------------
    \.?                      '.' (optional (matching the most amount
                             possible))
--------------------------------------------------------------------------------
    \d+                      digits (0-9) (1 or more times (matching
                             the most amount possible))
--------------------------------------------------------------------------------
  )                        end of \1

Java代码：

String regex = "\\bTOTAL\\b[\\s\\S]*?([+-]?\\d*\\.?\\d+)";
String string = "69003 LYON 03 ejuodnid 04 72.84.75.20 affm groa TICKET FACTURE 361203- SEPHORA EYE PALET LIG PALE 29991 14.99 Sephora Collection -Prix 392729 SEPHORA CINESCOPE 16.501 328451- SEPHORA THE MASC BIG MASC goe( 6.99193.49 P Sephora Co11ection Prix 347597SEPHORA LING GRENADE NG 25 i5.99 1) 2.99 Sephora Collect1o0 PriX adoy (30 00 1o)o 6.00 oniop20% achats Black Mars 2019 451087 OFFRE 20%ACHATS 15.00 MASC 16.50 3.50 3.00 N'2 24.00 VPBLA 0.00 tnoe 0001* 1eepom TOTAL EUR 62.00";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(string);
if (matcher.find()) {
    System.out.println(matcher.group(1));
}

结果：
62.00
请发布一些示例数据只需使用：
（？s）\bTOTAL\b.*（[+-]）？\d+（？：\。\d+）
并获取组1FYI:javadoc中显示了用于匹配浮点数的完整正则表达式。请发布一些示例数据只需使用：
（？s）\bTOTAL\b.*（[+]？\d+）（？：\。。。。\。。）
和get group#1FYI:javadoc中显示了匹配浮点数的完整正则表达式。否，它无效。：）编辑时有一个拼写错误，我现在已将其更改回。否，它无效。：）编辑时有一个拼写错误，我现在已将其更改回。