无法将Java.lang.string类型的Java值转换为jsonobject

我有一个输出JSON字符串作为输出的API。我想解析这个JSON。它在一段时间前就开始工作了，但我可能已经更改了API或java代码中的某些内容

这是我正在使用的代码：

public function get_cleaner($mobile, $pass){
    $this->db->select("cleaner.cleaner_id, cleaner.cleaner_name, cleaner.date_of_joining, cleaner.current_address, cleaner.mobile1, cleaner.mobile2, cleaner.date_of_birth, skill.skill_name as cleaner_designation");
    $this->db->from("cleaner");
    $this->db->join('skill', 'cleaner.designation = skill.skill_id', 'left');
    $this->db->where("mobile1", $mobile);
    $this->db->where("user_pass", $pass);
    $data = $this->db->get()->result_array();

    return $data;
}

public function getCleaner(){
    $mobile_no = $this->input->get('mobile');
    $pass = $this->input->get('pass');
    if(!is_null($mobile_no) && !is_null($pass))
    {
        header('Content-Type: application/javascript');
        $data = $this->cleaner_model->get_cleaner($mobile_no, $pass);
        if(!empty($data))
            echo json_encode($data[0]);
        else 
            echo '{"cleaner_id":"-10","cleaner_name":"cleaner_not_found"}';
    }

}

这里，

msg

是一个包含api响应的字符串

try {
    /* this prints */
    Toast.makeText(MainActivity.this, msg, Toast.LENGTH_SHORT).show();
    JSONObject jObject = new JSONObject(msg);
    String cleaner_id = jObject.getString("cleaner_id");

   /* but this does not */
   Toast.makeText(MainActivity.this, msg, Toast.LENGTH_SHORT).show();

}
catch(Exception e) {
   Toast.makeText(MainActivity.this, e.toString(), Toast.LENGTH_SHORT).show();
}

我正在php中使用codeigniter框架

这是我的php模型中的函数：

public function get_cleaner($mobile, $pass){
    $this->db->select("cleaner.cleaner_id, cleaner.cleaner_name, cleaner.date_of_joining, cleaner.current_address, cleaner.mobile1, cleaner.mobile2, cleaner.date_of_birth, skill.skill_name as cleaner_designation");
    $this->db->from("cleaner");
    $this->db->join('skill', 'cleaner.designation = skill.skill_id', 'left');
    $this->db->where("mobile1", $mobile);
    $this->db->where("user_pass", $pass);
    $data = $this->db->get()->result_array();

    return $data;
}

public function getCleaner(){
    $mobile_no = $this->input->get('mobile');
    $pass = $this->input->get('pass');
    if(!is_null($mobile_no) && !is_null($pass))
    {
        header('Content-Type: application/javascript');
        $data = $this->cleaner_model->get_cleaner($mobile_no, $pass);
        if(!empty($data))
            echo json_encode($data[0]);
        else 
            echo '{"cleaner_id":"-10","cleaner_name":"cleaner_not_found"}';
    }

}

这是我的php控制器：

public function get_cleaner($mobile, $pass){
    $this->db->select("cleaner.cleaner_id, cleaner.cleaner_name, cleaner.date_of_joining, cleaner.current_address, cleaner.mobile1, cleaner.mobile2, cleaner.date_of_birth, skill.skill_name as cleaner_designation");
    $this->db->from("cleaner");
    $this->db->join('skill', 'cleaner.designation = skill.skill_id', 'left');
    $this->db->where("mobile1", $mobile);
    $this->db->where("user_pass", $pass);
    $data = $this->db->get()->result_array();

    return $data;
}

public function getCleaner(){
    $mobile_no = $this->input->get('mobile');
    $pass = $this->input->get('pass');
    if(!is_null($mobile_no) && !is_null($pass))
    {
        header('Content-Type: application/javascript');
        $data = $this->cleaner_model->get_cleaner($mobile_no, $pass);
        if(!empty($data))
            echo json_encode($data[0]);
        else 
            echo '{"cleaner_id":"-10","cleaner_name":"cleaner_not_found"}';
    }

}

我在网上搜索了很多，尝试了很多不同的解决方案，但是没有一个解决方案适合我

更新：

给出了错误

给出了错误

但是

解析精细并给我just key not found异常

Github示例json api和my api给出了

无法将字符串转换为json obj

异常，但google maps api没有。我的api格式有什么问题吗

修复：我终于发现我的api输出有一个导致解析错误的前导隐藏字符

这是我收到的错误截图（截图太大，但你明白了…）

---

我试图解决这个问题，但什么都不管用，我也不知道为什么！我有一个解决方案，但我不知道它是否有意义

    try{
        HttpURLConnection conn = (HttpURLConnection) new URL("http://mridulahuja.com/api/index.php/cleaner/getCleaner?mobile=1111111111&pass=njnjhbh").openConnection();
        InputStreamReader isr = new InputStreamReader(conn.getInputStream(), "UTF-8");
        BufferedReader reader = new BufferedReader(isr);
        String line = reader.readLine();
        if(line != null){
            line = line.substring(line.indexOf("{"));
            JSONObject obj = new JSONObject(line);
            System.out.println(obj.getString("cleaner_name"));
        }
        reader.close();
    }catch(Exception e){
        System.err.println(e.getMessage());
    }

---

我试图解决这个问题，但什么都不管用，我也不知道为什么！我有一个解决方案，但我不知道它是否有意义

    try{
        HttpURLConnection conn = (HttpURLConnection) new URL("http://mridulahuja.com/api/index.php/cleaner/getCleaner?mobile=1111111111&pass=njnjhbh").openConnection();
        InputStreamReader isr = new InputStreamReader(conn.getInputStream(), "UTF-8");
        BufferedReader reader = new BufferedReader(isr);
        String line = reader.readLine();
        if(line != null){
            line = line.substring(line.indexOf("{"));
            JSONObject obj = new JSONObject(line);
            System.out.println(obj.getString("cleaner_name"));
        }
        reader.close();
    }catch(Exception e){
        System.err.println(e.getMessage());
    }

---

抱歉…我现在添加了它。您使用org.json.JSONObject类还是org.json.simple.JSONObject？为什么您的内容类型是

application/javascript

而不是

application/json

？我尝试使用application/json，但没有任何改变，我使用的是org.json.JSONObject对不起……我现在添加了它。您使用org.json.JSONObject类还是org.json.simple.JSONObject？为什么您的内容类型是

application/javascript

而不是

application/json

？我尝试使用application/json，但没有任何改变，我正在使用org.json.JSONObject