无法使用Java/Hibernate反序列化NativeQuery中的日期时间
简化示例 我运行带有日期的本机查询:无法使用Java/Hibernate反序列化NativeQuery中的日期时间,java,json,jackson,jodatime,Java,Json,Jackson,Jodatime,简化示例 我运行带有日期的本机查询: SELECT id, start FROM event; 我做了一个SqlResultSetMapping,如下所示: @SqlResultSetMapping( name="EventMapping", classes={ @ConstructorResult( targetClass=de.teamsystems.domain.Overvie
SELECT id, start FROM event;
我做了一个SqlResultSetMapping,如下所示:
@SqlResultSetMapping(
name="EventMapping",
classes={
@ConstructorResult(
targetClass=de.teamsystems.domain.OverviewEvent.class,
columns={
@ColumnResult(name="id", type = Long.class ),
@ColumnResult(name="start", type = DateTime.class )
}
)
}
)
我的OverviewEvent类看起来像:
@Entity
public class OverviewEvent {
@Id
private Long id;
private String name;
private DateTime start;
public Long getId() {
return id;
}
public DateTime getStart() {
return start;
}
public OverviewEvent(Long id, DateTime start) {
this.id = id;
this.start = start;
}
}
当我在控制器中执行此代码时,会出现以下异常:
{
"error": "Internal Server Error",
"exception": "javax.persistence.PersistenceException",
"message": "org.hibernate.type.SerializationException: could not deserialize",
"path": "/event",
"status": 500,
"timestamp": "2017-03-13T22:22:30.527+0100"
}
日志文件显示:
2017-03-13 22:22:30.523 ERROR 23479 --- [nio-8080-exec-1] o.a.c.c.C.[.[.[/].[dispatcherServlet] : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is javax.persistence.PersistenceException: org.hibernate.type.SerializationException: could not deserialize] with root cause
java.io.StreamCorruptedException: invalid stream header: 32303137
at java.io.ObjectInputStream.readStreamHeader(ObjectInputStream.java:808) ~[na:1.8.0_111]
当我在OverviewEvent类和SqlResultSetMapping中将DateTime更改为字符串时,它就起作用了。但是我想使用datetime格式
有人能帮我解决这个问题吗。我尝试了不同的方法,例如:
@Type(type = "org.jadira.usertype.dateandtime.joda.PersistentDateTime")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd HH:mm:ss")
private DateTime start;
但例外情况依然如此。感谢您的帮助。尝试使用Date java.util.Date代替DateTime:
或者为DateTime创建自定义反序列化程序。谢谢。今天晚上,当我再次参与这个项目时,我会尝试一下。因为我是一个新手,这就是你所说的:工作。谢谢
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd HH:mm:ss")
private Date start;