java.lang.IndexOutOfBoundsException:索引1无效，在分段回收视图中大小为1

在方法

onClick（）

中尝试获取RecyclerView中对象的当前位置时，出现此错误。下面是一段代码：

@Override
    public void onClick(View v) {
        if (v == btnAccept) {
            int position              = (Integer) v.getTag();
            Notification notification = mNotifications.get(position); // Here is an error
            mFragmentPageOne.acceptMembership(notification.getGroupId());
        } else if (v == btnDecline) {

        }
    }

@Override
public void onBindItemViewHolder(RecyclerView.ViewHolder holder, Notification item, @ViewType int viewType) {
    NotificationHolder notificationHolder = (NotificationHolder) holder;
    final int position = holder.getAdapterPosition();

    notificationHolder.tvNotification.setText(
              item.getNotification() + " ti je poslao zahtev za clanstvo u ekipu "
            + item.getGroupName());
    long timestamp = DateUtil.getDifference(item.getTimestamp());
    // Converting timestamp into x ago format
    CharSequence timeAgo = DateUtils.getRelativeTimeSpanString(
            Long.parseLong(String.valueOf(timestamp)),
            System.currentTimeMillis(), DateUtils.SECOND_IN_MILLIS);
    notificationHolder.tvTimestamp.setText(timeAgo);

    notificationHolder.btnAccept.setTag(position);
    notificationHolder.btnDecline.setTag(position);

    setAnimation(notificationHolder.mRelativeLayout, position);
}

所以我试图在列表中找到当前选定对象的位置。此列表还有一些分段项。 在这里，我将数据设置为对象数组：

try {
    JSONObject obj = new JSONObject(response);
    boolean error = obj.getBoolean("error");
    JSONArray ary = obj.getJSONArray("membership");
    if (!error) {
        for (int i = 0; i < ary.length(); i++) {
            JSONObject innerObj = ary.getJSONObject(i);
            Notification notification = new Notification();
            notification.setNotification(innerObj.getString("name"));
            notification.setTimestamp(innerObj.getString("createdAt"));
            notification.setGroupId(innerObj.getInt("group_id"));
            notification.setGroupName(innerObj.getString("group_name"));
            notification.setCategory("Membership Requests");
            mNotificationList.add(notification);
        }

        mAdapter = new NotificationHeaderListAdapter(getActivity(), mNotificationList, FragmentPageOne.this);
        LinearLayoutManager linearLayoutManager = new LinearLayoutManager(getActivity(), LinearLayoutManager.VERTICAL, false);
        mRecyclerView.setLayoutManager(linearLayoutManager);
        mRecyclerView.addItemDecoration(new HorizontalDividerItemDecoration(getActivity()));
        mRecyclerView.setHasFixedSize(true);
        mRecyclerView.setAdapter(mAdapter);
    }
} catch (JSONException e) {
    e.printStackTrace();
}

试试这个：

notificationHolder.checkParentView.setTag(itemsData.ge(position));
notificationHOlder.checkParentView.setOnClickListener(checkedListener);
private View.OnClickListener checkedListener = new View.OnClickListener() {
    @Override
    public void onClick(View v) {

        int positon = (Integer) v.getTag();
    }
};

---

Java中的ArrayList是基于零的。Try

Notification Notification=mNotifications.get（位置1）
Java中的ArrayList是基于零的。Try
Notification Notification=mNotifications.get（位置1）
@Jens将此评论作为答案发布，因为它解决了我的问题，可能也会帮助其他人。我已经这样做了。请投票和/或接受答案。
notificationHolder.checkParentView.setTag(itemsData.ge(position));
notificationHOlder.checkParentView.setOnClickListener(checkedListener);
private View.OnClickListener checkedListener = new View.OnClickListener() {
    @Override
    public void onClick(View v) {

        int positon = (Integer) v.getTag();
    }
};